Given an unsorted array of integers, find the length of longest continuous
increasing subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
思路:
遍历即可。水题。
int findLengthOfLCIS(vector<int>& nums) { int n =nums.size(); if(n <= 1)return n; int ret = 1,length=1; for(int i=1;i<n;i++) { if(nums[i]>nums[i-1])length++; else length =1; ret = max(length,ret); } return ret; }