• shell脚本处理大数据系列之(二)使用函数返回值


    转自http://longriver.me/?p=80

    随着shell脚本行数的增大,为了编写和维护的需要,想把一些特定的功能的代码抽取出来,组成函数的形式,放到一个叫做functions.sh中这样将来使用的时候只需要在脚本中source functions.sh 一下,然后就可以方便使用,处理大数据的时候,上篇博文提到过使用多线程处理是重要的手段,所以想到了写一个lock()函数,使得多个进程之间可以异步的工作。

    函数的返回值有两种用途
    1,返回函数结束的状态(可以是int,也可以是string)
    2,共享一些变量

    以下代码来自

    (EDIT: This is also true for some other shells...)
    1. echo strings

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    lockdir="somedir"
    testlock(){
        retval=""
        if mkdir "$lockdir"
        then # directory did not exist, but was created successfully
             echo >&2 "successfully acquired lock: $lockdir"
             retval="true"
        else
             echo >&2 "cannot acquire lock, giving up on $lockdir"
             retval="false"
        fi
        echo "$retval"
    }
    retval=$( testlock )
    if [ "$retval"=="true" ]
    then
         echo "directory not created"
    else
         echo "directory already created"
    fi

    2. return exit status

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    lockdir="somedir"
    testlock(){
        if mkdir "$lockdir"
        then # directory did not exist, but was created successfully
             echo >&2 "successfully acquired lock: $lockdir"
             retval=0
        else
             echo >&2 "cannot acquire lock, giving up on $lockdir"
             retval=1
        fi
        return "$retval"
    }
     
    testlock
    retval=$?
    if [ "$retval" == 0 ]
    then
         echo "directory not created"
    else
         echo "directory already created"
    fi

    3. share variable

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    lockdir="somedir"
    retval=-1
    testlock(){
        if mkdir "$lockdir"
        then # directory did not exist, but was created successfully
             echo >&2 "successfully acquired lock: $lockdir"
             retval=0
        else
             echo >&2 "cannot acquire lock, giving up on $lockdir"
             retval=1
        fi
    }
     
    testlock
    if [ "$retval" == 0 ]
    then
         echo "directory not created"
    else
         echo "directory already created"
    fi

    【NOTICE】关于shell函数的一个陷阱,我曾经深尝苦果,shell函数内部定义的变量,不是局部变量,这就意味着变量不会随着函数的结束而消失,这个特点可以被利用,所以shell函数中的变量要初始化,每次执行的时候注意重新赋值。

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  • 原文地址:https://www.cnblogs.com/harveyaot/p/3600448.html
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