/Files/hanguoji/MongoDB权威指南中文版.rar
MongoDB权威介绍:http://www.cnblogs.com/silentcross/archive/2011/06/27/2091530.html
查询:
MySQL:
SELECT * FROM user
Mongo:
db.user.find()
MySQL:
SELECT * FROM user WHERE name = ’starlee’
Mongo:
db.user.find({‘name’ : ’starlee’})
插入:
MySQL:
INSERT INOT user (`name`, `age`) values (’starlee’,25)
Mongo:
db.user.insert({‘name’ : ’starlee’, ‘age’ : 25})
如果你想在MySQL里添加一个字段,你必须:
ALTER TABLE user….
但在MongoDB里你只需要:
db.user.insert({‘name’ : ’starlee’, ‘age’ : 25, ‘email’ : ’starlee@starlee.com’})
删除:
MySQL:
DELETE * FROM user
Mongo:
db.user.remove({})
MySQL:
DELETE FROM user WHERE age < 30
Mongo:
db.user.remove({‘age’ : {$lt : 30}})
$gt : > ; $gte : >= ; $lt : < ; $lte : <= ; $ne : !=
更新:
MySQL:
UPDATE user SET `age` = 36 WHERE `name` = ’starlee’
Mongo:
db.user.update({‘name’ : ’starlee’}, {$set : {‘age’ : 36}})
MySQL:
UPDATE user SET `age` = `age` + 3 WHERE `name` = ’starlee’
Mongo:
db.user.update({‘name’ : ’starlee’}, {$inc : {‘age’ : 3}})
MySQL:
SELECT COUNT(*) FROM user WHERE `name` = ’starlee’
Mongo:
db.user.find({‘name’ : ’starlee’}).count()
MySQL:
SELECT * FROM user limit 10,20
Mongo:
db.user.find().skip(10).limit(20)
MySQL:
SELECT * FROM user WHERE `age` IN (25, 35,45)
Mongo:
db.user.find({‘age’ : {$in : [25, 35, 45]}})
MySQL:
SELECT * FROM user ORDER BY age DESC
Mongo:
db.user.find().sort({‘age’ : -1})
MySQL:
SELECT DISTINCT(name) FROM user WHERE age > 20
Mongo:
db.user.distinct(‘name’, {‘age’: {$lt : 20}})
MySQL:
SELECT name, sum(marks) FROM user GROUP BY name
Mongo:
db.user.group({
key : {‘name’ : true},
cond: {‘name’ : ‘foo’},
reduce: function(obj,prev) { prev.msum += obj.marks; },
initial: {msum : 0}
});
MySQL:
SELECT name FROM user WHERE age < 20
Mongo:
db.user.find(‘this.age < 20′, {name : 1})
for(var i=0;i<100;i++)db.test.insert({uid:i,uname:’nosqlfan’+i});
上面一次性插入一百条数据,大概结构如下: