• 快手:笔试题(版本号比较,平方和为1,合并两个流)


    1. 版本号比较

    方法1,没有AC

    public class A19 {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            int m = sc.nextInt();
            sc.nextLine();
            String[][] strs = new String[m][2];
            boolean[] result = new boolean[m];
            for (int i = 0; i < m; i++) {
                strs[i] = sc.nextLine().split(" ");
                int c1 = strs[i][0].split("\.").length;
                int c2 = strs[i][1].split("\.").length;
                while(c1<c2){
                    strs[i][0]+=".0";
                    c1++;
                }
                while(c1>c2){
                    strs[i][1]+=".0";
                    c2++;
                }
                if(strs[i][0].compareTo(strs[i][1])<0){
                    result[i]= true;
                }
            }
            for (int i = 0; i < m; i++) {
                System.out.println(result[i]);
            }
        }
    }

    方法2 没有ac

    package test;
    
    import java.util.Scanner;
    
    public class A17 {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            int m = sc.nextInt();
            sc.nextLine();
            String[][] strs = new String[m][2];
            
            for (int i = 0; i < m; i++) {
                strs[i] = sc.nextLine().split(" ");
            }
            boolean[] result = new boolean[m];
            for (int i = 0; i < m; i++) {
                String[] str1 = strs[i][0].split("\.");
                String[] str2 = strs[i][1].split("\.");
                int[] val1 = new int[4];
                int[] val2 = new int[4];
                for (int j = 0; j < str1.length; j++) {
                    val1[j] = Integer.valueOf(str1[j]);
                }
                for (int j = 0; j < str2.length; j++) {
                    val2[j] = Integer.valueOf(str2[j]);
                }
                for (int j = 0; j < 4; j++) {
                    if(val1[j]<val2[j]){
                        result[i]=true;
                        break;
                    }
                }
            }
            for (int i = 0; i < m; i++) {
                System.out.println(result[i]);
            }
        }
    }

    方法3 AC

    作者:jerryzhuo
    链接:https://www.nowcoder.com/discuss/233405?type=post&order=time&pos=&page=1
    来源:牛客网
    
    import java.util.Scanner;
     
    /**
     * 版本问题
     */
    public class Main {
        public static void main(String[] args) {
            Scanner in = new Scanner(System.in);
            int m = in.nextInt();
            String[] op1 = new String[m];
            String[] op2 = new String[m];
            for (int i = 0; i < m; i++) {
                op1[i] = in.next();
                op2[i] = in.next();
            }
     
            Main main = new Main();
            main.outputResult(op1, op2);
        }
     
        private void outputResult(String[] op1, String[] op2) {
            boolean[] result = new boolean[op1.length];
            for (int i = 0; i < op1.length; i++) {
                String[] oneArray = op1[i].trim().split("\.");
                String[] twoArray = op2[i].trim().split("\.");
                boolean isOk = true;
     
                int pointerOne = 0;
                int pointerTwo = 0;
                while (pointerOne < oneArray.length && pointerTwo < twoArray.length) {
                    int compare = Integer.parseInt(oneArray[pointerOne]) - Integer.parseInt(twoArray[pointerTwo]);
                    if (compare < 0) {
                        break;
                    } else if (compare > 0) {
                        isOk = false;
                        break;
                    } else if (pointerOne == oneArray.length - 1) {
                        pointerTwo++;
                        while (pointerTwo < twoArray.length && twoArray[pointerTwo].equals("0")) {
                            pointerTwo++;
                        }
                        if (pointerTwo == twoArray.length) {
                            isOk = false;
                        }
                    } else if (pointerTwo == twoArray.length - 1) {
                        isOk = false;
                        break;
                    }
                    pointerOne++;
                    pointerTwo++;
                }
     
                result[i] = isOk;
            }
     
            for (boolean value : result) {
                System.out.println(value);
            }
        }
    }

    2. 平方和为1

    4 → 16 → 37 → 58 → 89 → 145 → 42 → 20 → 4 ,循环了,return false

    AC

    方法1

    import java.util.Scanner;
    
    public class A20 {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            int m = sc.nextInt();
            int[] n = new int[m];
            for (int i = 0; i < m; i++) {
                n[i] = sc.nextInt();
                
            }
            for (int i = 0; i < m; i++) {
                long result = getresult(n[i]);
                boolean r = true;
                while(result!=1){
                    result = getresult(result);
                    if(result==n[i]){
                        r=false;
                        break;
                    }
                }
                System.out.println(r);
            }
            
        }
        public static long getresult(long result2){
            long result = 0;
            
            while(result2!=0){
                long digit = result2 % 10;
                result = result+ digit*digit;
                result2 = result2/10;
            }
            return result;
        }
    }

    方法2

    import java.util.Scanner;
    
    public class A20 {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            int m = sc.nextInt();
            int[] n = new int[m];
            for (int i = 0; i < m; i++) {
                n[i] = sc.nextInt();
                
            }
            for (int i = 0; i < m; i++) {
                long result = getresult(n[i]);
                int time =0;
                while(result!=1 && time<1000){
                    result = getresult(result);
                    time++;
                }
                if(result==1){
                    System.out.println(true);
                }else{
                    System.out.println(false);
                }
            }
            
        }
        public static long getresult(long result2){
            long result = 0;
            
            while(result2!=0){
                long digit = result2 % 10;
                result = result+ digit*digit;
                result2 = result2/10;
            }
            return result;
        }
    }

    3. 合并两个流

    AC 

    import java.util.Scanner;
    
    public class A18 {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            String[] str1 = sc.nextLine().split(" ");
            String[] str2 = sc.nextLine().split(" ");
            int len1 = str1.length;
            int len2 = str2.length;
            String[] result = new String[len1+len2];
            int position = 0;
            int index2 = 0;
            for (int i = 0; i < len1; i++) {
                if((i+1)%4==0 && index2<len2){
                    result[position++]=str1[i];
                    result[position++]=str2[index2++];
                }else{
                    result[position++]=str1[i];
                }
            }
            while(index2<len2){
                result[position++]=str2[index2++];
            }
            
            for (int i = 0; i < (len1+len2); i++) {
                System.out.print(result[i]);
                if(i!=(len1+len2-1)){
                    System.out.print(" ");
                }
            }
        }
    }
  • 相关阅读:
    [OpenGL]用OpenGL制作动画
    主管喜欢什么样的程序员
    windows下使用git管理代码,其中出现的问题的解决办法
    iOS7隐藏状态栏 status Bar
    [微信开发_02]环境搭建
    Matlab PCA 算法
    Git学习之msysGit环境支持
    Git学习之Git 暂存区
    Git学习之Git检出
    STL——(3)string容器
  • 原文地址:https://www.cnblogs.com/haimishasha/p/11408901.html
Copyright © 2020-2023  润新知