• priority_queue member function


    没有优先队列的dijkstra不算真的dijkstra

    所以我又回来补常识了

    <1>priority_queue::emplace

    <7>priority_queue::top

     1 // priority_queue::emplace
     2 #include <iostream>       // std::cout
     3 #include <queue>          // std::priority_queue
     4 #include <string>         // std::string
     5 
     6 int main ()
     7 {
     8   std::priority_queue<std::string> mypq;
     9 
    10   mypq.emplace("orange");
    11   mypq.emplace("strawberry");
    12   mypq.emplace("apple");
    13   mypq.emplace("pear");
    14 
    15   std::cout << "mypq contains:";
    16   while (!mypq.empty())
    17   {
    18      std::cout << ' ' << mypq.top();
    19      mypq.pop();
    20   }
    21   std::cout << '
    ';
    22 
    23   return 0;
    24 }
    25 //Ooutput:mypq contains: strawberry pear orange apple

    <2>priority_queue::empty

    <3>priority_queue::pop

    <4>priority_queue::push

     1 // priority_queue::push/pop
     2 #include <iostream>       // std::cout
     3 #include <queue>          // std::priority_queue
     4 
     5 int main ()
     6 {
     7   std::priority_queue<int> mypq;
     8 
     9   mypq.push(30);
    10   mypq.push(100);
    11   mypq.push(25);
    12   mypq.push(40);
    13 
    14   std::cout << "Popping out elements...";
    15   while (!mypq.empty())
    16   {
    17      std::cout << ' ' << mypq.top();
    18      mypq.pop();
    19   }
    20   std::cout << '
    ';
    21 
    22   return 0;
    23 }
    24 //Output:Popping out elements... 100 40 30 25

    <5>priority_queue::size

    <6>priority_queue::swap

     1 // priority_queue::swap
     2 #include <iostream>       // std::cout
     3 #include <queue>          // std::priority_queue
     4 
     5 int main ()
     6 {
     7   std::priority_queue<int> foo,bar;
     8   foo.push (15); foo.push(30); foo.push(10);
     9   bar.push (101); bar.push(202);
    10 
    11   foo.swap(bar);
    12 
    13   std::cout << "size of foo: " << foo.size() << '
    ';
    14   std::cout << "size of bar: " << bar.size() << '
    ';
    15 
    16   return 0;
    17 
    18 /*Output:
    19 size of foo: 2
    20 size of bar: 3*/

    然后还有个自定义排序来着,到时候再摸。

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  • 原文地址:https://www.cnblogs.com/h404nofound/p/11688328.html
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