描述
写一个MyString 类，使得下面程序的输出结果是：
1. abcd-efgh-abcd-
2. abcd-
3.
4. abcd-efgh-
5. efgh-
6. c
7. abcd-
8. ijAl-
9. ijAl-mnop
10. qrst-abcd-
11. abcd-qrst-abcd- uvw xyz
about
big
me
take
abcd
qrst-abcd-
要求：MyString类必须是从C++的标准类string类派生而来。提示1：如果将程序中所有 "MyString" 用"string" 替换，那么题目的程序中除了最后两条语句编译无法通过外，其他语句都没有问题，而且输出和前面给的结果吻合。也就是说，MyString类对 string类的功能扩充只体现在最后两条语句上面。提示2: string类有一个成员函数 string substr(int start,int length); 能够求从 start位置开始，长度为length的子串
程序：
#include <iostream> #include <cstring> #include <cstdlib> using namespace std;
// 在此处补充你的代码
int CompareString( const void * e1, const void * e2) {
MyString * s1 = (MyString * ) e1;
MyString * s2 = (MyString * ) e2;
if( *s1 < *s2 ) return -1;
else if( *s1 == *s2 ) return 0;
else if( *s1 > *s2 ) return 1;
}
int main() {
MyString s1("abcd-"),s2,s3("efgh-"),s4(s1);
MyString SArray[4] = {"big","me","about","take"};
cout << "1. " << s1 << s2 << s3<< s4<< endl;
s4 = s3; s3 = s1 + s3;
cout << "2. " << s1 << endl;
cout << "3. " << s2 << endl;
cout << "4. " << s3 << endl;
cout << "5. " << s4 << endl;
cout << "6. " << s1[2] << endl;
s2 = s1; s1 = "ijkl-";
s1[2] = 'A' ;
cout << "7. " << s2 << endl;
cout << "8. " << s1 << endl;
s1 += "mnop";
cout << "9. " << s1 << endl;
s4 = "qrst-" + s2;
cout << "10. " << s4 << endl;
s1 = s2 + s4 + " uvw " + "xyz";
cout << "11. " << s1 << endl;
qsort(SArray,4,sizeof(MyString), CompareString);
for( int i = 0;i < 4;++i )
cout << SArray[i] << endl;
//输出s1从下标0开始长度为4的子串
cout << s1(0,4) << endl;
//输出s1从下标为5开始长度为10的子串
cout << s1(5,10) << endl;
return 0;
}
输入无输出1. abcd-efgh-abcd-
2. abcd-
3.
4. abcd-efgh-
5. efgh-
6. c
7. abcd-
8. ijAl-
9. ijAl-mnop
10. qrst-abcd-
11. abcd-qrst-abcd- uvw xyz
about
big
me
take
abcd
qrst-abcd-样例输入
无
样例输出
1. abcd-efgh-abcd- 2. abcd- 3. 4. abcd-efgh- 5. efgh- 6. c 7. abcd- 8. ijAl- 9. ijAl-mnop 10. qrst-abcd- 11. abcd-qrst-abcd- uvw xyz about big me take abcd qrst-abcd-
找了几个参考答案，但是提交的时候都失败了。
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
class MyString : public string
{
public:
MyString() {};
//1.0继承类继承父类所有的成员变量和成员函数，但不继承构造函数和析构函数
//1.1继承类的无参构造函数，会隐式调用父类的无参构造函数
MyString(const char * st) :string(st) {};
//1.2继承类的有参构造函数，如果父类也有有参构造函数，则必须显示调用它
//2.0这里的参数根据reference有两种选择，此处必须用const char*,"xxx"的类型是const char*
MyString(const MyString& s):string(s){}
//1.3继承类的复制构造函数必须要显示的调用父类的复制构造函数，不然就会默认调用父类的无参构造函数
MyString operator +(MyString & op2)
{
string s1 = *this;
string s2 = op2;
string s = s1 + s2;
return *new MyString(s.c_str());
}
MyString & operator +(const char * cs2)
{
string str1 = *this;
string s = str1 + cs2;
return *new MyString(s.c_str());
}
MyString & operator()(int s, int l)
{
string str = substr(s, l);
return *new MyString(str.c_str());
}
};
MyString operator+(const char * op1, MyString & op2)
{
string st2 = op2;
string s = op1 + st2;
return *new MyString(s.c_str());
}
int CompareString(const void * e1, const void * e2)
{
MyString * s1 = (MyString *)e1;
MyString * s2 = (MyString *)e2;
if (*s1 < *s2) return -1;
else if (*s1 == *s2) return 0;
else if (*s1 > *s2) return 1;
}
int main()
{
MyString s1("abcd-"), s2, s3("efgh-");
MyString s4(s1);
MyString SArray[4] = { "big","me","about","take" };
//这里等号右边的赋值操作相当于调用了MyString的转换构造函数，其实就是单一非const classname&参数的构造函数可以直接接受参数类型的变量
cout << "1. " << s1 << s2 << s3 << s4 << endl;
s4 = s3;
//3.0 operator=可以直接用string类里面的
s3 = s1 + s3;
s1+s3;
cout << "2. " << s1 << endl;
cout << "3. " << s2 << endl;
cout << "4. " << s3 << endl;
cout << "5. " << s4 << endl;
cout << "6. " << s1[2] << endl;
s2 = s1;
s1 = "ijkl-";
s1[2] = 'A';
cout << "7. " << s2 << endl;
cout << "8. " << s1 << endl;
s1 += "mnop";
cout << "9. " << s1 << endl;
s4 = "qrst-" + s2;
cout << "10. " << s4 << endl;
s1 = s2 + s4 + " uvw " + "xyz";
cout << "11. " << s1 << endl;
qsort(SArray, 4, sizeof(MyString), CompareString);
for (int i = 0; i < 4; ++i)
cout << SArray[i] << endl;
cout << s1(0, 4) << endl;
cout << s1(5, 10) << endl;
return 0;
}
---------------------
作者：qq_23908539
来源：CSDN
原文：https://blog.csdn.net/qq_23908539/article/details/51454521
版权声明：本文为博主原创文章，转载请附上博文链接！
这一个解释的还算比较详细，贴在上面供以后复习使用。