Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array [2,3,1,2,4,3]
and s = 7
,
the subarray [4,3]
has the minimal length under the problem constraint.
Credits:
Special thanks to @Freezen for adding this problem and creating all test cases.
1 public class Solution { 2 public int minSubArrayLen(int s, int[] nums) { 3 if(nums == null || nums.length == 0) return 0; 4 int b = 0,e = 0,minlen = Integer.MAX_VALUE,sum = 0; 5 while(e < nums.length){ 6 sum += nums[e++]; 7 while(sum >= s){ 8 minlen = Math.min(minlen,e-b); 9 sum -= nums[b++]; 10 } 11 } 12 return minlen == Integer.MAX_VALUE ? 0:minlen; 13 } 14 }
用两个指针,begin, end从前往后遍历。