可以作为 LCT 维护子树信息的模板,写的还是比较优美的.
本地可过,bzoj 时限太紧,一直 TLE
#include<bits/stdc++.h> #define setIO(s) freopen(s".in","r",stdin) , freopen(s".out","w",stdout) #define maxn 100002 #define inf 100000000 #define isrt(x) (!(ch[f[x]][0]==x||ch[f[x]][1]==x)) #define get(x) (ch[f[x]][1]==x) #define lson ch[x][0] #define rson ch[x][1] using namespace std; int n,Q; multiset<int>S[maxn]; int ch[maxn][2],f[maxn],rev[maxn],sta[maxn],minv[maxn],mintot[maxn],minson[maxn],val[maxn]; void mark(int x) { if(!x) return; swap(lson,rson),rev[x]^=1; } void pushup(int x) { if(!x) return; minv[x]=mintot[x]=val[x],minson[x]=inf; minv[x]=min(minv[x],min(minv[lson],minv[rson])); minson[x]=min(min(minson[lson],minson[rson]),*S[x].begin()); mintot[x]=min(minv[x], minson[x]); } void pushdown(int x) { if(!x||!rev[x]) return; mark(lson),mark(rson),rev[x]^=1; } void rotate(int x) { int old=f[x],fold=f[old],which=get(x); if(!isrt(old)) ch[fold][ch[fold][1]==old]=x; ch[old][which]=ch[x][which^1],f[ch[old][which]]=old; ch[x][which^1]=old,f[old]=x,f[x]=fold; pushup(old),pushup(x); } void splay(int x) { int v=0,u=x,fa; for(sta[++v]=u;!isrt(u);u=f[u]) sta[++v]=f[u]; while(v) pushdown(sta[v--]); for(u=f[u];(fa=f[x])!=u;rotate(x)) if(f[fa]!=u) rotate(get(x)==get(fa)?fa:x); } void Access(int x) { int t=0; while(x) { splay(x); if(rson) S[x].insert(mintot[rson]); if(t) S[x].erase(S[x].lower_bound(mintot[t])); rson=t,t=x,x=f[x]; } } void makert(int x) { Access(x),splay(x),mark(x); } void link(int x,int y) { makert(x), f[x]=y, S[y].insert(mintot[x]); } int main() { int i,j,root=0; // setIO("input"); scanf("%d%d",&n,&Q); mintot[0]=minv[0]=minson[0]=val[0]=inf; for(i=0;i<=n;++i) S[i].insert(inf); for(i=1;i<=n;++i) { int a; scanf("%d%d",&a,&val[i]); if(a==0) { root=i; makert(i); pushup(i); } else link(a,i); } makert(root); while(Q--) { char opt[3]; int x,y; scanf("%s",opt); if(opt[0]=='V') { scanf("%d%d",&x,&y); Access(x), splay(x), val[x]=y, pushup(x); } if(opt[0]=='E') { scanf("%d",&root); makert(root); } if(opt[0]=='Q') { scanf("%d",&x); Access(x), splay(x); printf("%d ",min(val[x], *S[x].begin())); } } return 0; }