• update and的坑


    开发那边抛出个有意思的问题,下面的现象如何解释呢?

    mysql> select * from A;
    +------+------+
    | t1   | t2   |
    +------+------+
    |    1 |    1 | 
    |    2 |    2 | 
    |    3 |    3 | 
    +------+------+
    3 rows in set (0.00 sec)
    mysql> update A set t1=0 and t2=5; 
    Query OK, 3 rows affected (0.00 sec)
    Rows matched: 3  Changed: 3  Warnings: 0
    
    mysql> select * from A;           
    +------+------+
    | t1   | t2   |
    +------+------+
    |    0 |    1 | 
    |    0 |    2 | 
    |    0 |    3 | 
    +------+------+
    3 rows in set (0.00 sec)
    update  语句 and 怎么解释?
    

      

    Update的语法是:

    UPDATE [LOW_PRIORITY] [IGNORE] table_reference
        SET col_name1={expr1|DEFAULT} [, col_name2={expr2|DEFAULT}] ...
        [WHERE where_condition]
        [ORDER BY ...]
        [LIMIT row_count]
    
    Multiple-table syntax:
    
    UPDATE [LOW_PRIORITY] [IGNORE] table_references
        SET col_name1={expr1|DEFAULT} [, col_name2={expr2|DEFAULT}] ...
        [WHERE where_condition]
    

      

    select的语法:

    Name: 'SELECT'
    Description:
    Syntax:
    SELECT
        [ALL | DISTINCT | DISTINCTROW ]
          [HIGH_PRIORITY]
          [STRAIGHT_JOIN]
          [SQL_SMALL_RESULT] [SQL_BIG_RESULT] [SQL_BUFFER_RESULT]
          [SQL_CACHE | SQL_NO_CACHE] [SQL_CALC_FOUND_ROWS]
        select_expr [, select_expr ...]
        [FROM table_references
          [PARTITION partition_list]
        [WHERE where_condition]
        [GROUP BY {col_name | expr | position}
          [ASC | DESC], ... [WITH ROLLUP]]
        [HAVING where_condition]
        [ORDER BY {col_name | expr | position}
          [ASC | DESC], ...]
        [LIMIT {[offset,] row_count | row_count OFFSET offset}]
        [PROCEDURE procedure_name(argument_list)]
        [INTO OUTFILE 'file_name'
            [CHARACTER SET charset_name]
            export_options
          | INTO DUMPFILE 'file_name'
          | INTO var_name [, var_name]]
        [FOR UPDATE | LOCK IN SHARE MODE]]
    

      

    update语法是set后面以逗号区分

    mysql> select * from test where t1=0 and t2=5;
    Empty set (0.00 sec)

    使用and被解析成 t1=0 and t2=5 把后面作为一个整体,值变成0了

    变成这样了,update A set t1=(0 and t2=5),t2==5 and 0 

    换种写法更加明白了

    【参考资料】

    1、http://s.petrunia.net/blog/?p=85

    先记录下,后面整体再整理!!!

     

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  • 原文地址:https://www.cnblogs.com/gsblog/p/4045251.html
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