• java leetcode TreeNode类、ListNode类的实现



    TreeNode类

      1 package data.structure;
      2 
      3 import java.util.ArrayList;
      4 
      5 public class TreeNode {
      6     public int val;
      7     public TreeNode left;
      8     public TreeNode right;
      9     public TreeNode(int x) { val = x; }
     10 
     11     public static TreeNode makeTree(Integer[] trees) {
     12         if (trees.length == 0)
     13             return null;
     14         TreeNode[] treeNodes = new TreeNode[trees.length + 1];
     15         for (int i = 1; i < treeNodes.length; i++) {
     16             if (trees[i - 1] == null) {
     17                 treeNodes[i] = null;
     18             } else {
     19                 treeNodes[i] = new TreeNode(trees[i - 1]);
     20             }
     21         }
     22 
     23         TreeNode treeNode = null;
     24         //这个只适用于完全二叉树
     25 //        for (int i = 1; i < treeNodes.length; i++) {
     26 //            treeNode = treeNodes[i];
     27 //            if (treeNode == null) continue;
     28 //            if (2 * i < treeNodes.length)
     29 //                treeNode.left = treeNodes[2 * i];
     30 //            if (2 * i + 1 < treeNodes.length)
     31 //                treeNode.right = treeNodes[2 * i + 1];
     32 //        }
     33         for (int i = 1, index = 2; i < treeNodes.length && index < treeNodes.length; i++) {
     34             treeNode = treeNodes[i];
     35             if (treeNode == null) continue;
     36             treeNode.left = treeNodes[index];
     37             if (index + 1 < treeNodes.length)
     38                 treeNode.right = treeNodes[index + 1];
     39             index += 2;
     40         }
     41         return treeNodes[1];
     42     }
     43 
     44     //中序遍历(左->根->右)
     45     public static ArrayList<Integer> middleTraverse(TreeNode treeNode) {
     46         ArrayList<Integer> arrayList = new ArrayList<>();
     47         if (treeNode == null) {
     48             arrayList.add(null);
     49         }else if (treeNode.left == null && treeNode.right == null) {
     50             arrayList.add(treeNode.val);
     51         } else {
     52             arrayList.addAll(middleTraverse(treeNode.left));
     53             arrayList.add(treeNode.val);
     54             arrayList.addAll(middleTraverse(treeNode.right));
     55         }
     56         return arrayList;
     57     }
     58 
     59     //前序遍历(根->左->右)
     60     public static ArrayList<Integer> beforeTraverse(TreeNode treeNode) {
     61         ArrayList<Integer> arrayList = new ArrayList<>();
     62         if (treeNode == null) {
     63             arrayList.add(null);
     64         }else if (treeNode.left == null && treeNode.right == null) {
     65             arrayList.add(treeNode.val);
     66         } else {
     67             arrayList.add(treeNode.val);
     68             arrayList.addAll(beforeTraverse(treeNode.left));
     69             arrayList.addAll(beforeTraverse(treeNode.right));
     70         }
     71         return arrayList;
     72     }
     73 
     74     //后序遍历(左->右->根)
     75     public static ArrayList<Integer> afterTraverse(TreeNode treeNode) {
     76         ArrayList<Integer> arrayList = new ArrayList<>();
     77         if (treeNode == null) {
     78             arrayList.add(null);
     79         }else if (treeNode.left == null && treeNode.right == null) {
     80             arrayList.add(treeNode.val);
     81         } else {
     82             arrayList.addAll(afterTraverse(treeNode.left));
     83             arrayList.addAll(afterTraverse(treeNode.right));
     84             arrayList.add(treeNode.val);
     85         }
     86         return arrayList;
     87     }
     88 
     89     //层序遍历
     90     public static ArrayList<Integer> sequenceTraverse(TreeNode root) {
     91         ArrayList<Integer> arrayList = new ArrayList<>();
     92         ArrayList<TreeNode> treeNodes = new ArrayList<>();
     93         treeNodes.add(root);
     94         arrayList.add(root.val);
     95         while (treeNodes.size() > 0) {
     96             ArrayList<TreeNode> subTreeNodes = new ArrayList<>();
     97             for (TreeNode value : treeNodes) {
     98                 if (value.left != null || value.right != null) {
     99                     if (value.left != null) {
    100                         subTreeNodes.add(value.left);
    101                         arrayList.add(value.left.val);
    102                     } else {
    103                         arrayList.add(null);
    104                     }
    105                     if (value.right != null) {
    106                         subTreeNodes.add(value.right);
    107                         arrayList.add(value.right.val);
    108                     } else {
    109                         arrayList.add(null);
    110                     }
    111                 }
    112             }
    113             treeNodes = subTreeNodes;
    114         }
    115         return arrayList;
    116     }
    117 }

    ListNode类

     1 package data.structure;
     2 
     3 import java.util.ArrayList;
     4 
     5 public class ListNode {
     6     public int val;
     7     public ListNode next;
     8     public ListNode(int x) {
     9         val = x;
    10         next = null;
    11     }
    12 
    13     //创建单链表
    14     public static ListNode makeNode(int[] nums) {
    15         if (nums.length == 0) return null;
    16         ListNode listNode = new ListNode(nums[0]);
    17         ListNode head = listNode;
    18         for (int i = 1; i < nums.length; i++) {
    19             ListNode node = new ListNode(nums[i]);
    20             listNode.next = node;
    21             listNode = node;
    22         }
    23         return head;
    24     }
    25 
    26     //创建循环链表
    27     public static ListNode makeNode(int[] nums, int pos) {
    28         if (nums.length == 0) return null;
    29         ListNode[] listNodes = new ListNode[nums.length];
    30         for (int i = 0; i < nums.length; i++) {
    31             listNodes[i] = new ListNode(nums[i]);
    32         }
    33 
    34         ListNode listNode = listNodes[0];
    35         for (int i = 1; i < listNodes.length; i++) {
    36             listNode.next = listNodes[i];
    37             listNode = listNodes[i];
    38         }
    39         if (pos >= 0 && pos < nums.length) {
    40             listNode.next = listNodes[pos];
    41         }
    42         return listNodes[0];
    43     }
    44 
    45     //创建两条相交链表
    46     public static ListNode[] makeIntersectNode(int[] listA, int skipA, int[] listB, int skipB) {
    47         if (listA.length == 0 || listB.length == 0) return null;
    48         ListNode[] nodesA = new ListNode[listA.length];
    49         for (int i = 0; i < nodesA.length; i++) {
    50             nodesA[i] = new ListNode(listA[i]);
    51         }
    52         ListNode nodeA = nodesA[0];
    53         for (int i = 1; i < nodesA.length; i++) {
    54             nodeA.next = nodesA[i];
    55             nodeA = nodesA[i];
    56         }
    57 
    58         ListNode[] nodesB = new ListNode[listB.length];
    59         for (int i = 0; i < nodesB.length; i++) {
    60             nodesB[i] = new ListNode(listB[i]);
    61         }
    62         ListNode nodeB = nodesB[0];
    63         for (int i = 1; i < nodesB.length; i++) {
    64             nodeB.next = nodesB[i];
    65             nodeB = nodesB[i];
    66         }
    67 
    68         if (skipA < listA.length && skipB < listB.length && listA[skipA] == listB[skipB]) {
    69             nodesB[skipB].next = nodesA[skipA];
    70         }
    71 
    72         ListNode[] nodes = new ListNode[2];
    73         nodes[0] = nodesA[0];
    74         nodes[1] = nodesB[0];
    75         return nodes;
    76     }
    77 
    78     //遍历链表
    79     public static ArrayList<Integer> traverse(ListNode head) {
    80         ArrayList<Integer> arrayList = new ArrayList<>();
    81         while (head != null) {
    82             arrayList.add(head.val);
    83             head = head.next;
    84         }
    85         return arrayList;
    86     }
    87 }
     
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  • 原文地址:https://www.cnblogs.com/grein/p/11943816.html
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