lintcode735. Replace With Greatest From Right

Given an array of integers, replace every element with the next greatest element (greatest element on the right side) in the array. Since there is no element next to the last element, replace it with -1. For example, if the array is [16, 17, 4, 3, 5, 2], then it should be modified to [17, 5, 5, 5, 2, -1].

最初的思路代码（超时）

class Solution {
public:
    /*
     * @param : An array of integers.
     * @return: nothing
     */
    void arrayReplaceWithGreatestFromRight(vector<int> &nums) {
        // Write your code here.
        int len = nums.size();
        int max = nums[len - 1];
        nums[len - 1] = -1;
        for (int i = len - 2; i >= 0; i--) {
            int temp = nums[i];
            nums[i] = max;
            if (temp > max) {
                max = temp;
            }
        }

    }
};

从后往前的方法：

class Solution {
public:
    /*
     * @param : An array of integers.
     * @return: nothing
     */
    void arrayReplaceWithGreatestFromRight(vector<int> &nums) {
        // Write your code here.
        int len = nums.size();
        int max = nums[len - 1];
        nums[len - 1] = -1;
        for (int i = len - 2; i >= 0; i--) {
            int temp = nums[i];
            nums[i] = max;
            if (temp > max) {
                max = temp;
            }
        }

    }
};

目前一直是79%数据通过。。。一直没有到最后结果。可能是网络有问题，晚上再试。