• PTA 02-线性结构4 Pop Sequence (25分)


    题目地址

    https://pta.patest.cn/pta/test/16/exam/4/question/665

    5-3 Pop Sequence   (25分)

    Given a stack which can keep MM numbers at most. Push NN numbers in the order of 1, 2, 3, ..., NN and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop sequence of the stack. For example, if MM is 5 and NN is 7, we can obtain 1, 2, 3, 4, 5, 6, 7 from the stack, but not 3, 2, 1, 7, 5, 6, 4.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): MM (the maximum capacity of the stack), NN (the length of push sequence), and KK (the number of pop sequences to be checked). Then KK lines follow, each contains a pop sequence of NN numbers. All the numbers in a line are separated by a space.

    Output Specification:

    For each pop sequence, print in one line "YES" if it is indeed a possible pop sequence of the stack, or "NO" if not.

    Sample Input:

      

    5 7 5
    1 2 3 4 5 6 7
    3 2 1 7 5 6 4
    7 6 5 4 3 2 1
    5 6 4 3 7 2 1
    1 7 6 5 4 3 2
    

    Sample Output:

    YES
    NO
    NO
    YES
    NO
    /*
    评测结果
    时间	结果	得分	题目	编译器	用时(ms)	内存(MB)	用户
    2017-07-08 15:55	答案正确	25	5-3	gcc	3	1	
    测试点结果
    测试点	结果	得分/满分	用时(ms)	内存(MB)
    测试点1	答案正确	15/15	2	1
    测试点2	答案正确	3/3	2	1
    测试点3	答案正确	2/2	2	1
    测试点4	答案正确	2/2	3	1
    测试点5	答案正确	1/1	2	1
    测试点6	答案正确	2/2	1	1
    
    */
    #include<stdio.h>
    #define MAXLEN 1000
    
    /*下面这段代码只能拿18/25分 
    int main()
    {
    	int i,j,m,n,k,last,flag,temp;
    	scanf("%d %d %d",&m,&n,&k);
    	for (i=0;i<k;i++){
    		flag=1;
    		last=0;
    		for(j=0;j<n;j++){
    			scanf("%d",&temp);
    			if (temp-last>m) flag=0;
    			last=temp;
    		}
    		if(flag==0) printf("NO
    ");
    		else printf("YES
    ");
    			
    	}
    }
    */
    
    struct stack{
    	int data[MAXLEN];
    	int top;
    	int max;
    };
    
    struct stack workstack;
    
    
    int GetTop(struct stack stc)
    {
    	if(stc.top>=0) return stc.data[stc.top];
    	else return 0;
    }
    
    int Push(struct stack *stc,int item)
    {
    	if (stc->top==MAXLEN-1) return 0;
    	else {
    		stc->data[++(stc->top)]=item;
    //		printf("--PUSH %d,%d
    ",stc->data[(stc->top)],stc->top);//test
    		return 1;
    	}
    }
    
    int Pop(struct stack *stc)
    {
    	if(stc->top<0) return 0;
    	else{
    //		printf("--POP %d,%d
    ",stc->data[(stc->top)],stc->top);//test
    		return stc->data[(stc->top)--];
    	}
    }
    
    int main()
    {	
    	int i,j,m,n,k,numforpush,errorflag,temp;
    	scanf("%d %d %d",&m,&n,&k);
    	workstack.max=m;
    	for (i=0;i<k;i++){
    		errorflag=0;
    		numforpush=1;
    		workstack.top=-1;
    		for(j=0;j<n;j++){
    			scanf("%d",&temp);
    			if (errorflag==1) continue;
    //			printf("--GET %d
    ",temp);//test
    			while(workstack.top<workstack.max-1 && numforpush<=n && GetTop(workstack)!=temp){
    //				printf("--IN WHILE workstack.top=%d,max=%d,numforpush=%d
    ",workstack.top,workstack.max,numforpush);//test
    				Push(&workstack,numforpush);
    				numforpush++;
    			}
    			
    			if(GetTop(workstack)==temp){
    				Pop(&workstack);
    			}
    			else{
    				errorflag=1;
    			}
    			
    		}
    		if(errorflag==1)
    			printf("NO");
    		else
    			printf("YES");
    		if(i!=k-1) putchar('
    ');
    	}
    	
    	
    }
    


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  • 原文地址:https://www.cnblogs.com/gk2017/p/7140524.html
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