• UVA 11992 Fast Matrix Operations


    线段树

      1 #include <iostream>
      2 using namespace std;
      3 
      4 const int maxn = 1000005;
      5 const int INF = 1000000009;
      6 
      7 struct node {
      8     int sum,ma,mi;
      9     int addv,setv;
     10     void init (int nsum,int nma,int nmi,int naddv,int nsetv){
     11         sum=nsum;ma=nma;mi=nmi;
     12         addv=naddv;setv=nsetv;
     13     }
     14 }tree[30][maxn*2];
     15 
     16 int r,c,m;
     17 
     18 void init (){
     19     for (int i=1;i<=r;i++){
     20         for (int j=1;j<=c*2;j++){
     21             tree[i][j].init (0,0,0,0,-1);
     22         }
     23         tree[i][1].setv=0;
     24     }
     25 }
     26 
     27 //int sum[30][maxn],ma[30][maxn],mi[30][maxn];
     28 //int addv[30][maxn],setv[30][maxn];
     29 
     30 void maintain (int o,int l,int r,int i){
     31     int lc=o<<1,rc=(o<<1)+1;
     32     if (r>l){
     33         tree[i][o].sum=tree[i][lc].sum+tree[i][rc].sum;
     34         tree[i][o].mi=min (tree[i][lc].mi,tree[i][rc].mi);
     35         tree[i][o].ma=max (tree[i][lc].ma,tree[i][rc].ma);
     36     }
     37         if (tree[i][o].setv!=-1){
     38             tree[i][o].mi=tree[i][o].setv;
     39             tree[i][o].ma=tree[i][o].setv;
     40             tree[i][o].sum=tree[i][o].setv*(r-l+1);
     41         }
     42         if (tree[i][o].addv){
     43             tree[i][o].mi+=tree[i][o].addv;
     44             tree[i][o].ma+=tree[i][o].addv;
     45             tree[i][o].sum+=tree[i][o].addv*(r-l+1);
     46         }
     47 }
     48 
     49 void pushdown (int o,int i){
     50     int lc=o<<1,rc=(o<<1)+1;
     51     if (tree[i][o].setv!=-1){
     52         tree[i][lc].setv=tree[i][rc].setv=tree[i][o].setv;
     53         tree[i][lc].addv=tree[i][rc].addv=0;
     54         tree[i][o].setv=-1;
     55     }
     56     if (tree[i][o].addv>0){
     57         tree[i][lc].addv+=tree[i][o].addv;
     58         tree[i][rc].addv+=tree[i][o].addv;
     59         tree[i][o].addv=0;
     60     }
     61 }
     62 
     63 void add (int o,int l,int r,int x1,int x2,int i,int v){
     64     int m=l+(r-l)/2,lc=o<<1,rc=(o<<1)+1;
     65     if (x1<=l&&r<=x2){
     66         tree[i][o].addv+=v;
     67     }
     68     else {
     69         pushdown (o,i);
     70         if (x1<=m) add (lc,l,m,x1,x2,i,v);else maintain (lc,l,m,i);
     71         if (m<x2) add (rc,m+1,r,x1,x2,i,v);else maintain (rc,m+1,r,i);
     72     }
     73     maintain (o,l,r,i);
     74     return ;
     75 }
     76 
     77 void set (int o,int l,int r,int x1,int x2,int i,int v){
     78     int m=l+(r-l)/2;
     79     int lc=o<<1,rc=(o<<1)+1;
     80     if (x1<=l&&r<=x2){
     81         tree[i][o].setv=v;
     82         tree[i][o].addv=0;
     83     }
     84     else {
     85         pushdown (o,i);
     86     if (x1<=m) set (lc,l,m,x1,x2,i,v);else maintain (lc,l,m,i);
     87     if (m<x2) set (rc,m+1,r,x1,x2,i,v);else maintain (rc,m+1,r,i);
     88     }
     89     maintain (o,l,r,i);
     90     return ;
     91 }
     92 int sum,ma,mi;
     93 int query (int o,int l,int r,int x1,int x2,int i,int addv){
     94     int m=l+(r-l)/2,lc=o<<1,rc=(o<<1)+1;
     95     if (tree[i][o].setv!=-1){
     96         int x=tree[i][o].setv+addv+tree[i][o].addv;
     97         sum+=x*(min(r,x2)-max(l,x1)+1);
     98         mi=min (mi,x);
     99         ma=max (ma,x);
    100         addv=0;
    101     }
    102     else if (x1<=l&&r<=x2){
    103         sum+=tree[i][o].sum+addv*(r-l+1);
    104         mi=min (mi,tree[i][o].mi+addv);
    105         ma=max (ma,tree[i][o].ma+addv);
    106     }
    107     else {
    108         if (x1<=m) query (lc,l,m,x1,x2,i,addv+tree[i][o].addv);
    109         if (x2>m) query (rc,m+1,r,x1,x2,i,addv+tree[i][o].addv);
    110     }
    111 }
    112 
    113 int main (){
    114     while (cin>>r>>c>>m){
    115         init ();
    116         while (m--){
    117             int f,x1,x2,y1,y2,v;
    118             cin>>f>>x1>>y1>>x2>>y2;
    119             if (f==1){
    120                 cin>>v;
    121                 for (int i=x1;i<=x2;i++)
    122                     add (1,1,c,y1,y2,i,v);
    123             }
    124             else if (f==2){
    125                 cin>>v;
    126                 for (int i=x1;i<=x2;i++)
    127                     set (1,1,c,y1,y2,i,v);
    128             }
    129             else if (f==3){
    130                 sum=0;ma=-INF;mi=INF;
    131                 for (int i=x1;i<=x2;i++)
    132                     query (1,1,c,y1,y2,i,0);
    133                 cout<<sum<<" "<<mi<<" "<<ma<<endl;
    134             }
    135         }
    136     }
    137     return 0;
    138 }
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  • 原文地址:https://www.cnblogs.com/gfc-g/p/3894203.html
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