题目大意
题解
显然是二分图匹配。
用一些方法建图就好了。
要注意的是:
本题有多组数据!!!
初始化一定要注意!!!
代码
#include <bits/stdc++.h>
using namespace std;
const int maxn = 505;
const int inf = 0x3f3f3f;
int n;
// 1~n:学生
// n+1~n+k:床位
int isbed[maxn], insch[maxn];
int dist[maxn * 2], iter[maxn * 2];
struct edge {
int to, cap, rev;
};
vector<edge> G[maxn];
void add_edge(int from, int to, int cap) {
G[from].push_back((edge){to, cap, G[to].size()});
G[to].push_back((edge){from, 0, G[from].size() - 1});
}
int cnt = 0;
void read() {
scanf("%d", &n);
memset(isbed, 0, sizeof(isbed));
for (int i = 0; i <= 2 * n + 1; i++) {
G[i].clear();
}
cnt = 0;
for (int i = 1; i <= n; i++) {
scanf("%d", &isbed[i]);
}
for (int i = 1; i <= n; i++) {
scanf("%d", &insch[i]);
insch[i] = insch[i] ^ 1;
}
for (int i = 1; i <= n; i++) {
if (isbed[i])
add_edge(i, i + n, 1);
for (int j = 1; j <= n; j++) {
int x;
scanf("%d", &x);
if (x && isbed[j]) {
if (!(isbed[i]) || (isbed[i] && insch[i])) {
add_edge(i, n + j, 1);
}
}
}
if (!(isbed[i]) || (isbed[i] && insch[i])) {
cnt++;
add_edge(0, i, 1);
}
if (isbed[i])
add_edge(n + i, 2 * n + 1, 1);
}
}
void bfs(int from) {
memset(dist, -1, sizeof(dist));
dist[from] = 0;
queue<int> q;
q.push(from);
while (!q.empty()) {
int u = q.front();
q.pop();
for (int i = 0; i < G[u].size(); i++) {
edge &e = G[u][i];
if (dist[e.to] < 0 && e.cap > 0) {
dist[e.to] = dist[u] + 1;
q.push(e.to);
}
}
}
}
int dfs(int from, int to, int f) {
if (from == to)
return f;
for (int &i = iter[from]; i < G[from].size(); i++) {
edge &e = G[from][i];
if (e.cap > 0 && dist[e.to] > dist[from]) {
int d = dfs(e.to, to, min(f, e.cap));
if (d > 0) {
e.cap -= d;
G[e.to][e.rev].cap += d;
return d;
}
}
}
return 0;
}
int max_flow(int from, int to) {
int flow = 0;
for (;;) {
bfs(from);
if (dist[to] < 0)
return flow;
memset(iter, 0, sizeof(iter));
int f;
while ((f = dfs(from, to, inf) > 0))
flow += f;
}
}
int main() {
// freopen("input", "r", stdin);
int T;
scanf("%d", &T);
while (T--) {
cnt = 0;
read();
int ans = max_flow(0, 2 * n + 1);
if (ans == cnt)
printf("^_^
");
else
printf("T_T
");
}
return 0;
}