• 模板-高精度BigInteger


    #include <bits/stdc++.h>
    using namespace std;
    struct BigInteger {
      static const int BASE = 100000000;
      static const int WIDTH = 8;
      vector<int> s;
      BigInteger(long long num = 0) { *this = num; } // 构造函数
      BigInteger operator = (long long num) { // 赋值运算符
        s.clear();
        do {
          s.push_back(num % BASE);
          num /= BASE;
        } while(num > 0);
        return *this;
      }
      BigInteger operator = (const string& str) { // 赋值运算符
        s.clear();
        int x, len = (str.length() - 1) / WIDTH + 1;
        for(int i = 0; i < len; i++) {
          int end = str.length() - i*WIDTH;
          int start = max(0, end - WIDTH);
          sscanf(str.substr(start, end-start).c_str(), "%d", &x);
          s.push_back(x);
        }
        return *this;
      }
      BigInteger operator + (const BigInteger& b) const {
        BigInteger c;
        c.s.clear();
        for(int i = 0, g = 0; ; i++) {
          if(g == 0 && i >= s.size() && i >= b.s.size()) break;
          int x = g;
          if(i < s.size()) x += s[i];
          if(i < b.s.size()) x += b.s[i];
          c.s.push_back(x % BASE);
          g = x / BASE;
        }
        return c;
      }
      BigInteger operator * (const BigInteger& b) const {
        BigInteger c;
        c.s.clear();
        for(int i = 0, g = 0; ; i++) {
          if(g == 0 && i >= s.size() && i >= b.s.size()) break;
          int x = 1;
          if(i < s.size()) x *= s[i];
          if(i < b.s.size()) x *= b.s[i];
          x+=g;
          c.s.push_back(x % BASE);
          g = x / BASE;
        }
        return c;
      }
    };
    ostream& operator << (ostream &out, const BigInteger& x) {
      out << x.s.back();
      for(int i = x.s.size()-2; i >= 0; i--) {
        char buf[20];
        sprintf(buf, "%08d", x.s[i]);
        for(int j = 0; j < strlen(buf); j++) out << buf[j];
      }
      return out;
    }
    istream& operator >> (istream &in, BigInteger& x) {
      string s;
      if(!(in >> s)) return in;
      x = s;
      return in;
    }
    int main() {
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/gengchen/p/6038241.html
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