/*
ID:kevin_s1
PROG:sprime
LANG:C++
*/
//N = 1仅仅可能为2,3。5。7。N > 1仅仅可能为1。3,7。9. N = i,到N = i + 1递推假设是素数就扩展。相似于BFS
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <vector>
#include <map>
#include <set>
#include <algorithm>
#include <cstdlib>
#include <list>
#include <cmath>
using namespace std;
//gobal variable====
vector<vector<int> > prime(9);
int N;
//==================
//function==========
bool isPrime(int i)
{
bool tag = true;
int place = (int)sqrt((double)i);
int value;
for(int j = 3; j <= place; j+=2)//质数判别
{
if(i % j == 0)
{
tag = false;
break;
}
}
return tag;
}
//==================
int main(){
freopen("sprime.in","r",stdin);
freopen("sprime.out","w",stdout);
cin>>N;
prime[1].push_back(2);
prime[1].push_back(3);
prime[1].push_back(5);
prime[1].push_back(7);
for(int i = 2; i <= N; i++){
for(int j = 0; j < prime[i - 1].size(); j++){
long long num = prime[i - 1][j] * 10;
if(isPrime(num + 1))
prime[i].push_back(num + 1);
if(isPrime(num + 3))
prime[i].push_back(num + 3);
if(isPrime(num + 7))
prime[i].push_back(num + 7);
if(isPrime(num + 9))
prime[i].push_back(num + 9);
}
}
for(int i = 0; i < prime[N].size(); i++){
cout<<prime[N][i]<<endl;
}
return 0;
}