• POJ 1459


      1 #include<iostream>
      2 #define MAXN 105
      3 #include"queue"
      4 #define big_num 100000000
      5 using namespace std;
      6 
      7 int _m[MAXN][MAXN];
      8 int Ford_fulkerson(int n, int s, int t, int &F,int g[][MAXN]);
      9 int main()
     10 {
     11     //freopen("acm.acm","r",stdin);
     12     int point;
     13     int np;
     14     int nc;
     15     int edge;
     16     char left;
     17     char right;
     18     char space;
     19     int flow;
     20     int u;
     21     int v;
     22     int i;
     23     int node;
     24     while(cin>>point>>np>>nc>>edge)
     25     {
     26         memset(_m,0,sizeof(_m));
     27         for(i = 0; i < edge; ++ i)
     28         {
     29             cin>>left;
     30             cin>>u;
     31             cin>>space;
     32             cin>>v;
     33             cin>>right;
     34             cin>>flow;
     35             ++ u;
     36             ++ v;
     37             _m[u][v] = flow;
     38         }
     39         for(i = 0; i < np; ++ i)
     40         {
     41             cin>>left;
     42             cin>>u;
     43             cin>>right;
     44             cin>>flow;
     45             ++ u;
     46             _m[0][u] = flow;
     47         }
     48         for(i = 0; i < nc; ++ i)
     49         {
     50             cin>>left; 
     51             cin>>u;
     52             cin>>right;
     53             cin>>flow;
     54             ++ u;
     55             _m[u][point+1] = flow;
     56         }
     57         int F = 0;
     58         while(Ford_fulkerson(point+2,0,point + 1,F,_m));        
     59         cout<<F<<endl;
     60     }
     61 }
     62 
     63 
     64 
     65 int find_path(int m, int s,int t,int pre[MAXN],int g[][MAXN])
     66 {
     67     queue<int> q;        
     68     int * mark = new int[m];
     69     memset(mark,0,sizeof(int)*m);
     70     int x;
     71     mark[s] = 1;               
     72     int i;
     73     q.push(s);                   
     74     while(!q.empty())        
     75     {
     76         x = q.front();            
     77         for(i = 0; i < m; i++)
     78         {
     79             if(g[x][i] > 0 && mark[i] == 0)
     80             {                        
     81                 mark[i] = 1;
     82                 pre[i] = x;    
     83                 if(i == t)            
     84                     return 1;
     85                 q.push(i);        
     86             }
     87         }
     88     q.pop();
     89     }
     90     delete [] mark;
     91     return 0;
     92 }
     93 int Ford_fulkerson(int n, int s, int t, int &F,int g[][MAXN])
     94 {
     95     int i;
     96     int min;
     97     int * pre = new int[n];                    
     98     if(find_path(n,s,t,pre, g) == 0)
     99     {
    100         delete [] pre;
    101         return 0;
    102     }
    103     min = big_num;                
    104     for(i = t; i != s; i = pre[i])
    105         if(g[pre[i]][i] < min)
    106         {
    107             min = g[pre[i]][i];
    108         }
    109     for(i = t; i != s; i = pre[i])
    110     {
    111         g[pre[i]][i] -= min;
    112         g[i][pre[i]] += min;
    113     }
    114     F += min;    
    115     delete []pre;
    116     return 1;
    117 }

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  • 原文地址:https://www.cnblogs.com/gavinsp/p/4563405.html
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