• 使用java实现单链表(转载自:https://www.cnblogs.com/zhongyimeng/p/9945332.html)


    使用java实现单链表----(java中的引用就是指针)转载自:https://www.cnblogs.com/zhongyimeng/p/9945332.html

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    //一直以为java中没有指针,其实java的引用就是指针,只不过堆栈中的引用储存了在堆中的地址,可以看做java中的指针。<br>public class sibgleLink<E> {
        // 结点内部类
        private class Node {
            private Object data;
            private Node next = null;
     
            public Node() {
                data = null;
            }
     
            // 带数据的构造函数
            public Node(E data) {
                this.data = data;
            }
     
        }
     
        private Node head; // 头引用(指针)
        private Node rear; // 尾引用(指针)
        private Node point; // 临时引用(指针)
        private int length = 1; // 链表长度
     
        // 带参数的构造函数
        public sibgleLink(E e) {
            head = new Node();
            head.data = e;
            rear = head;
            length = 1;
        }
     
        // 尾插法
        public void add(E elem) {
            point = new Node(elem);
            rear.next = point;
            rear = point;
            length++;
     
        }
     
        // 遍历节点
        public void traverse() {
            point = head; // 移动临时引用到头结点
            if (head != null)
                System.out.print("[" + head.data + "]");
            while (point.next != null) {
                System.out.print("->[" + point.next.data + "]");
                point = point.next;
            }
            System.out.println();
        }
     
        // 返回长度
        public int length() {
            return this.length;
        }
     
        // 清除
        public boolean clear() {
            while (head.next.next != null) {
     
                head.next = head.next.next;
            }
     
            head.next = null;
            rear = head;
            point = null;
            length = 1;
            return true;
     
        }
     
        // 插入元素
        public boolean insert(int x, E data) {
            // 工作节点
            point = head;
            int wz = 1;
            if (x == 1) {
                Node n = new Node(data);
                n.next = head;
                head = n;
                length++;
                return true;
     
            }
     
            if (x < 1 || x > this.length) {
                return false;
     
            } else {
     
                while (point.next != null && wz < x - 1) {
                    point = point.next;
                    wz++;
                }
     
                // 放入一个节点
                Node n = new Node(data);
                n.next = point.next;
                point.next = n;
                length++;
     
                return true;
     
            }
     
        }
     
        // 删除
        public boolean del(int x) {
            point = head;
            int wz = 1;
            if (x < 0 || x > length) {
                return false;
     
            } else if (x == length) {
                point = head;
                while (point.next != null) {
                    point = rear;
                    point.next = null;
                    length--;
     
                }
     
            } else {
     
                while (point.next != null && wz < x - 1) {
                    point = point.next;
                    wz++;
                }
                Node d = point.next;
                point.next = point.next.next;
                d = null;
     
                return true;
     
            }
     
            return false;
     
        }
     
        // 更改
        public boolean change(int x, E data) {
            point = head;
            int wz = 1;
            if (x < 0 || x > length) {
                return false;
     
            } else {
     
                while (point.next != null && wz < x) {
                    point = point.next;
                    wz++;
                }
                point.data = data;
     
                return true;
     
            }
     
        }
     
        // 移动指针
        private Node movePoint(int position) {
            if (position < 0)
                return head;
            if (position > length)
                return rear;
     
            if (position >= 0 && position <= length) {
                point = head;
                while (point != null) {
                    if (position == 0)
                        break;
                    position--;
                    point = point.next;
                }
            }
     
            return point;
     
        }
     
        public E find(int position) {
            if (position >= 0 && position < length) {
                Node tmp = movePoint(position);
                return (E) tmp.next.data;
            }
            return null;
        }
     
        // test
        public static void main(String[] args) {
     
            sibgleLink<Integer> si = new sibgleLink<Integer>(0);
            si.add(5);
            si.add(6);
            si.insert(2, 2);
            si.traverse();
            si.del(3);
            si.traverse();
            si.change(3, 77);
            si.traverse();
            System.out.println(si.length());
     
        }
     
    }

      结果:

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    [0]->[2]->[5]->[6]
    [0]->[2]->[6]
    [0]->[2]->[77]
    4
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  • 原文地址:https://www.cnblogs.com/gaolight/p/13107736.html
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