【LeetCode】58. Length of Last Word

Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

用ret记录上一个单词的长度，用cur记录当前单词的长度。

每遇到空白符，将cur赋给ret，然后cur置零。

如果以字母结尾，返回cur

如果以空格结尾，返回ret(此时cur为0)

class Solution {
public:
    int lengthOfLastWord(const char *s) {
        int ret = 0;
        int cur = 0;
        while(*s != 0)
        {
            while(*s != 0 && *s == ' ')
                s ++;
            if(*s == 0)
                return ret;
                
            while(*s != 0 && *s != ' ')
            {
                cur ++;
                s ++;
            }
            
            if(*s == 0)
                return cur;
            else
            {
                ret = cur;
                cur = 0;
            }
        }
    }
};