• LeetCode Pascal's Triangle && Pascal's Triangle II Python


    Pascal's Triangle

    Given numRows, generate the first numRows of Pascal's triangle.

    For example, given numRows = 5,
    Return

    [
         [1],
        [1,1],
       [1,2,1],
      [1,3,3,1],
     [1,4,6,4,1]
    ]
    class Solution:
        # @return a list of lists of integers
        
            
        def generate(self, numRows):
            def g(ls):
                res = [1]
                left = 1
                for i in range(1,len(ls)):
                    res.append(left+ls[i])
                    left = ls[i]
                res.append(1)
                return res
            
            res = []
            if numRows < 3:
                if numRows == 0:
                    return res
                for i in range(1,numRows+1):
                    res.append([1]*i)
            else:
                res.append([1])
                res.append([1,1])
                
                for i in range(2,numRows):
                    res.append(g(res[i-1]))
            return res
            

     

    Pascal's Triangle II

    Given an index k, return the kth row of the Pascal's triangle.

    For example, given k = 3,
    Return [1,3,3,1].

    Note:
    Could you optimize your algorithm to use only O(k) extra space?

    class Solution:
        # @return a list of integers
        def getRow(self, rowIndex):
            def g(ls):
                res = [1]
                left = 1
                for i in range(1,len(ls)):
                    res.append(left+ls[i])
                    left = ls[i]
                res.append(1)
                return res
            
            res = []
            if rowIndex< 2:
                res = [1]*(rowIndex+1)
            else:
                res.append([1,1])
                for i in range(rowIndex):
                    res = (g(res))
            return res
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  • 原文地址:https://www.cnblogs.com/fyymonica/p/4371576.html
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