枚举年份,从(1000)枚举到(9999),构造回文日期,判断是否在给定日期范围内,以及判断日期是否合法。
int month[2][13]={
{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}
};
int st,ed;
bool isLeap(int year)
{
return (year % 4 == 0 && year % 100) || year % 400 == 0;
}
bool check(int date)
{
if(date > ed || date < st) return false;
int yy=date/10000,mm=date%10000/100,dd=date%100;
bool isleap=isLeap(yy);
if(mm == 0 || mm > 12) return false;
if(dd == 0 || dd > month[isleap][mm]) return false;
return true;
}
int main()
{
cin>>st>>ed;
int res=0;
for(int i=1000;i<10000;i++)
{
int date=i,t=i;
while(t)
{
date=date*10+t%10;
t/=10;
}
if(check(date)) res++;
}
cout<<res<<endl;
//system("pause");
return 0;
}