• leetcode@ [310] Minimum Height Trees


    For a undirected graph with tree characteristics, we can choose any node as the root. The result graph is then a rooted tree. Among all possible rooted trees, those with minimum height are called minimum height trees (MHTs). Given such a graph, write a function to find all the MHTs and return a list of their root labels.

    Format
    The graph contains n nodes which are labeled from 0 to n - 1. You will be given the number n and a list of undirected edges (each edge is a pair of labels).

    You can assume that no duplicate edges will appear in edges. Since all edges are undirected, [0, 1] is the same as [1, 0] and thus will not appear together in edges.

    Example 1:

    Given n = 4, edges = [[1, 0], [1, 2], [1, 3]]

            0
            |
            1
           / 
          2   3
    

    return [1]

    Example 2:

    Given n = 6, edges = [[0, 3], [1, 3], [2, 3], [4, 3], [5, 4]]

         0  1  2
           | /
            3
            |
            4
            |
            5
    

    return [3, 4]

    Hint:

    Show Hint

    1. How many MHTs can a graph have at most?

    Note:

    (1) According to the definition of tree on Wikipedia: “a tree is an undirected graph in which any two vertices are connected by exactly one path. In other words, any connected graph without simple cycles is a tree.”

    (2) The height of a rooted tree is the number of edges on the longest downward path between the root and a leaf.

    public class Solution {
        
        /** return the height of tree if let s to be the root of the tree */
        public static int bfs(ArrayList<ArrayList<Integer> > g, int s) {
            
            HashSet<Integer> upper = new HashSet<Integer> ();
            HashSet<Integer> lower = new HashSet<Integer> ();
            HashSet<Integer> vis = new HashSet<Integer> ();
            
            upper.add(s);
            vis.add(s);
            int lv = 1;
            
            while(!upper.isEmpty()) {
                
                for(int u: upper) {
                    ArrayList<Integer> adj = g.get(u);
                    for(int i=0; i<adj.size(); ++i) {
                        int adj_node = adj.get(i);
                        if(!vis.contains(adj_node)) {
                            lower.add(adj_node);
                        }
                    }
                }
                
                if(!lower.isEmpty()) {
                    ++lv;
                }
                
                upper.clear();
                for(int c: lower) {
                    vis.add(c);
                    upper.add(c);
                }
                lower.clear();
            }
            
            return lv;
        }
        
        public static ArrayList<Integer> topologicalSort(int n, int[][] edges, ArrayList<ArrayList<Integer> > g) {
            
            ArrayList<Integer> topo = new ArrayList<Integer> ();
            int[] d = new int[n];
            
            for(int i=0; i<edges.length; ++i) {
                int u = edges[i][0], v = edges[i][1];
                ++d[u]; ++d[v];
            }
            
            LinkedList<Integer> queue = new LinkedList<Integer> ();
            for(int i=0; i<n; ++i) {
                if(d[i] == 1) {
                    queue.addLast(i);
                }
            }
            
            while(!queue.isEmpty()) {
                int top = queue.pollFirst();
                topo.add(top);
                
                ArrayList<Integer> adj = g.get(top);
                for(int next: adj) {
                    d[next]--;
                    if(d[next] == 1) {
                        queue.addLast(next);
                    }
                }
            }
            
            return topo;
        }
    
        public List<Integer> findMinHeightTrees(int n, int[][] edges) {
            
            List<Integer> rs = new ArrayList<Integer> ();
            if(n == 1) {
                rs.add(0);
                return rs;
            }
            
            ArrayList<ArrayList<Integer> > g = new ArrayList<ArrayList<Integer> > ();
            for(int i=0; i<n; ++i) {
                ArrayList<Integer> row = new ArrayList<Integer> ();
                g.add(row);
            }
            for(int i=0; i<edges.length; ++i) {
                int u = edges[i][0];
                int v = edges[i][1];
                
                g.get(u).add(v);
                g.get(v).add(u);
            }
        
            HashMap<Integer, Integer> mapping = new HashMap<Integer, Integer> ();
            ArrayList<Integer> topo = topologicalSort(n, edges, g);
            
            int idx = topo.get(topo.size()-1);
            int min_lv = bfs(g, idx);
            rs.add(idx);
            
            if(topo.size() >= 2) {
                int indice = topo.get(topo.size()-2);
                if(bfs(g, indice) == min_lv) {
                    rs.add(indice);
                }
            }
        
            return rs;
            
        }
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/fu11211129/p/5501059.html
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