Valid Parentheses [LeetCode 20]

1- 问题描述

　　Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

　　The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.

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2- 思路分析^[1]

　　利用一个栈来保存前括号，然后有后括号来时弹出栈顶来判断。

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3- Python实现

class Solution:
    # @param {string} s
    # @return {boolean}
    def isValid(self, s):
        if not s: return False
        l = len(s)
        if l % 2 == 1: return False    # 长度为奇数返回False
        bracket = {'(':')', '[':']', '{':'}'}
        stack = []    # 栈保存前括号
        for i in range(l):
            if s[i] in bra:
                stack.append(s[i])    # 前括号则入栈
            else:
                try:
                    top = stack.pop()
                except:
                    return False    # 取不出前括号返回False
                if bracket[top] != s[i]:    # 比较是否与出栈前括号匹配
                    return False
        if not len(stack): return True    # 遍历完若栈为空，则完全匹配
        return False    # 栈内还有元素，则不匹配

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[1] [LeetCode] Valid Parentheses