pat 1028

1028 List Sorting (25分)

 

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:

Each input file contains one test case. For each case, the first line contains two integers N (≤100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1:

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60

Sample Output 1:

Sample Input 2:

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98

Sample Output 2:

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60

Sample Input 3:

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90

Sample Output 3:

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

题意：模拟excel按照要求排序记录

思路：会sort函数就行

代码如下：

#include<cstdio>
#include<algorithm>
#include<vector>
#include<cstring>
using namespace std;
typedef struct node{
    int id;
    char name[10];
    int score;
}node;
node stu[100005];
bool cmp1(node a,node b){
    if(a.id<b.id)
        return true;
    else
        return false;
}
bool cmp2(node a,node b){
    if(strcmp(a.name,b.name)<0)
        return true;
    else if(strcmp(a.name,b.name)>0)
        return false;
    else
        return a.id<b.id;
}
bool cmp3(node a,node b){
    if(a.score!=b.score)
        return a.score<b.score;
    else
        return a.id<b.id;
}
int main(){
    int n,c;
    scanf("%d%d",&n,&c);
    for(int i=0;i<n;i++){
        scanf("%d%s%d",&stu[i].id,stu[i].name,&stu[i].score);
    }
    if(c==1){
        sort(&stu[0],&stu[n],cmp1);
    }
    else if(c==2){
        sort(&stu[0],&stu[n],cmp2);
    }
    else if(c==3){
        sort(&stu[0],&stu[n],cmp3);
    }
    for(int i=0;i<n;i++){
        printf("%06d %s %d
",stu[i].id,stu[i].name,stu[i].score);
    }
    return 0;
}