• 用Group by分组后,取每组的前几条记录


    http://community.csdn.net/Expert/topic/4494/4494002.xml?temp=.1675836
    --给个例子参考
    --查询每门课程的前2名成绩

    CREATE TABLE StudentGrade(
    stuId CHAR(4),    --学号
    subId INT,        --课程号
    grade INT,        --成绩
    PRIMARY KEY (stuId,subId)
    )
    GO
    --表中数据如下
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('001',1,97);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('001',2,50);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('001',3,70);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('002',1,92);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('002',2,80);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('002',3,30);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('003',1,93);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('003',2,95);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('003',3,85);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('004',1,73);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('004',2,78);
    INSERT INTO StudentGrade(stuId,subId,grade) VALUES('004',3,87);
    GO
    /*
    要查询每门课程的前2名成绩
    001 1 97
    003 1 93
    003 2 95
    002 2 80
    004 3 87
    003 3 85
    如何实现?
    */
    --查看数据
    select * from StudentGrade


    --假如出现并列时,也只取两个同学的话。
    --方法一:
    select distinct *
    from studentgrade as t1
    where stuid in
    (select top 2 stuid
     from studentgrade as t2
     where t1.subid=t2.subid
             order by t2.grade desc)
    order by subid, grade desc

    --方法二:
    select * from StudentGrade a where (select count(1) from studentGrade where subId=a.subId and grade>=a.grade)<=2

    --方法三:
    select * from StudentGrade t
    where (select count(1) from StudentGrade where subid=t.subid and grade>t.grade)<=1
    order by subId,grade desc

    --结果
    /*
    stuId subId       grade      
    ----- ----------- -----------
    001   1           97
    003   1           93
    003   2           95
    002   2           80
    004   3           87
    003   3           85

    (6 row(s) affected)
    */

    drop table StudentGrade

  • 相关阅读:
    图片轮显效果大全
    firefox 对WebRTC支持
    Android AES加密算法及事实上现
    怎样以学习单片机为契机,逐步成为优秀的project师
    HTML中Select的使用具体解释
    POJ 3602 Typographical Ligatures
    远程控制编写之屏幕传输 MFC实现 屏幕截图 发送bmp数据 显示bmp图像
    blend
    POJ3187 Backward Digit Sums
    牛腩公布系统--HTTP 错误 403.14
  • 原文地址:https://www.cnblogs.com/flyfish/p/362984.html
Copyright © 2020-2023  润新知