Linux彩色输出

在linux下，可以使用一些宏，加上自定义格式输出，让输出更易于调试：

排版出来可能有些乱，注意do{ }while(0);是在一行里就可以了。

#include <stdio.h>
#include <stdlib.h>

#define DEBUG1( fmt,  arg  ... )
    do{printf("[DEBUG] " fmt ,  ##arg );  }while(0);
#define DEBUG2( fmt,  arg  ... )
    do{printf("[%s: %s: line %d]" fmt ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor1( fmt,  arg  ... )
    do{printf("33[30m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor2( fmt,  arg  ... )
    do{printf("33[31m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor3( fmt,  arg  ... )
    do{printf("33[32m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor4( fmt,  arg  ... )
    do{printf("33[33m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor5( fmt,  arg  ... )
    do{printf("33[34m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor6( fmt,  arg  ... )
    do{printf("33[35m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

#define PrintColor7( fmt,  arg  ... )
    do{printf("33[36m""[%s: %s: line %d]" fmt"33[0m" ,
        __FILE__, __FUNCTION__, __LINE__,  ##arg );  }while(0);

int main()
{
    printf("I AM IN macro.c
");

    DEBUG1("I AM IN macro.c
");
    DEBUG2("I AM IN macro.c
");

    PrintColor1("I AM IN macro.c
");
    PrintColor2("I AM IN macro.c
");
    PrintColor3("I AM IN macro.c
");
    PrintColor4("I AM IN macro.c
");
    PrintColor5("I AM IN macro.c
");
    PrintColor6("I AM IN macro.c
");
    PrintColor7("I AM IN macro.c
");

    return 0;
}

输出结果：

 

http://blog.csdn.net/xiangpingli/article/details/7914133