• Oracle按日期季度查询


    如下表table1:
      日期(exportDate)               数量(amount)
      --------------                    -----------
      14-2月 -08                       20
      10-3月 -08                       2
      14-4月 -08                       6
      14-6月 -08                       75
      24-10月-09                      23
      14-11月-09                      45
      04-8月 -10                       5
      04-9月 -10                       44
      04-10月-10                      88

    2.按月份分组
      select to_char(exportDate,'yyyy-mm'),sum(amount) from table1 group by to_char(exportDate,'yyyy-mm')
      order by to_char(exportDate,'yyyy-mm');
      月份           数量
      -----------------------------
      2008-02    20
      2008-03    2
      2008-04    6
      2008-06    75
      2009-10    23
      2009-11    45
      2010-08    5
      2010-09    44
      2010-10    88

    -------------------------------------------------------

    1.按年份分组
      select to_char(exportDate,'yyyy'),sum(amount) from table1 group by to_char(exportDate,'yyyy');
      年份      数量
      -----------------------------
      2009    68
      2010    137
      2008    103

    -------------------------------------------

    3.按季度分组
      select to_char(exportDate,'yyyy-Q'),sum(amount) from table1 group by to_char(exportDate,'yyyy-Q')
      order by to_char(exportDate,'yyyy-Q');
      季度          数量
      ------------------------------
      2008-1    22
      2008-2    81
      2009-4    68
      2010-3    49
      2010-4    88
      4.按周分组
      select to_char(exportDate,'yyyy-IW'),sum(amount) from table1 group by to_char(exportDate,'yyyy-IW')
      order by to_char(exportDate,'yyyy-IW');
      周             数量
      ------------------------------
      2008-07    20
      2008-11    2
      2008-16    6
      2008-24    75
      2009-43    23
      2009-46    45
      2010-31    5
      2010-35    44
      2010-40    88
      补充:
      按季度分组还有个比较笨的方法(参考网络资源)
      select  to_char(exportDate,'yyyy'),
      sum(decode(to_char(exportDate,'mm'),'01',amount,'02',amount,'03',amount,0)) as 第一季,
      sum(decode(to_char(exportDate,'mm'),'04',amount,'05',amount,'06',amount,0)) as 第二季,
      sum(decode(to_char(exportDate,'mm'),'07',amount,'08',amount,'09',amount,0)) as 第三季,
      sum(decode(to_char(exportDate,'mm'),'10',amount,'11',amount,'12',amount,0)) as 第四季
      from table1
      group by to_char(exportDate,'yyyy');
      年份        第一季     第二季     第三季     第四季
      --------------------------------------------------
      2009         0            0            0          68
      2010         0            0            49        88
      2008         22          81          0          0

    转自 http://www.233.com/oracle/zonghe/20101026/114104335.html

  • 相关阅读:
    Fizz Buzz 问题
    旋转字符串
    合并排序数组
    尾部的零
    A + B 问题
    CentOS6.x安装RabbitMQ
    MySql游标
    MySql存储过程
    找出n个自然数(1,2,3,……,n)中取r个数的组合
    正则表达式
  • 原文地址:https://www.cnblogs.com/fgm119/p/3603113.html
Copyright © 2020-2023  润新知