php 报错如下：Notice: Trying to get property of non-object

参考文档如下解决：

https://stackoverflow.com/questions/5891911/trying-to-get-property-of-non-object-in

问题如下：

This question already has an answer here:

• Call to a member function on a non-object [duplicate] 8 answers

on Control page:

<?php
  include 'pages/db.php'; 
  $results = mysql_query("SELECT * FROM sidemenu WHERE `menu_id`='".$menu."' ORDER BY `id` ASC LIMIT 1", $con);
  $sidemenus = mysql_fetch_object($results);
?>

on View Page:

<?php foreach ($sidemenus as $sidemenu): ?>
  <?php echo $sidemenu->mname."<br />";?>
<?php endforeach; ?>

Error is:

Notice: Trying to get property of non-object in C:wampwwwphonepagesinit.php on line 22

Can you fix it? I don't have any idea what happened.

解决如下：

Check the manual for mysql_fetch_object(). It returns an object, not an array of objects.

I'm guessing you want something like this

$results = mysql_query("SELECT * FROM sidemenu WHERE `menu_id`='".$menu."' ORDER BY `id` ASC LIMIT 1", $con);

$sidemenus = array();
while ($sidemenu = mysql_fetch_object($results)) {
    $sidemenus[] = $sidemenu;
}

---

Might I suggest you have a look at PDO. PDOStatement::fetchAll(PDO::FETCH_OBJ) does what you assumed mysql_fetch_object() to do