• oracle 长连接、锁查询


    SELECT *
      FROM (SELECT N.SID SID_,
                   N.USERNAME 实例名,
                   N.LOGON_TIME 登录打开页面时间,
                   N.SQL_EXEC_START 当前语句开始执行时间,
                   N.SQL_ID 当前SQLID,
                   L.SQL_TEXT 当前SQL内容,
                   L.SQL_FULLTEXT 当前SQL完整内容,
                   N.EVENT 当前等待事件,
                   N.FINAL_BLOCKING_SESSION 锁源头,
                   N.MACHINE 机器名,
                   N.INST_ID 节点,
                   N.*,
                   ROW_NUMBER() OVER(PARTITION BY N.SID ORDER BY N.LOGON_TIME, N.PREV_EXEC_START) RN
              FROM GV$SESSION N
              JOIN GV$SQL L
                ON L.SQL_ID = N.SQL_ID
             WHERE N.STATUS = 'ACTIVE'
               AND N.SCHEMANAME <> 'SYS'
             ORDER BY N.LOGON_TIME, N.PREV_EXEC_START) T
     WHERE T.RN = 1
     ORDER BY T.SQL_EXEC_START;
    ---长事务
    set linesize 200
    set pagesize 5000
    col transaction_duration format a45
     
    with transaction_details as
    ( select inst_id
      , ses_addr
      , sysdate - start_date as diff
      from gv$transaction
    )
    select s.username
    , to_char(trunc(t.diff))
                 || ' days, '
                 || to_char(trunc(mod(t.diff * 24,24)))
                 || ' hours, '
                 || to_char(trunc(mod(t.diff * 24 * 60,24)))
                 || ' minutes, '
                 || to_char(trunc(mod(t.diff * 24 * 60 * 60,60)))
                 || ' seconds' as transaction_duration
    , s.program
    , s.terminal
    , s.status
    , s.sid
    , s.serial#
    from gv$session s
    , transaction_details t
    where s.inst_id = t.inst_id
    and s.saddr = t.ses_addr
    order by t.diff desc
    --长连接
    select distinct g.INST_ID,
    machine,
    sid,
    g.SERIAL#,
    event,
    g.sql_id,
    (last_call_et) / 60,
    v.SQL_TEXT,
    g.status
    from gv$session g
    join gv$sqlarea v
    on g.SQL_ID = v.SQL_ID
    where status in ( 'ACTIVE', 'INACTIVE')
    and username != 'SYS'

     select * from gv$session where sid=4720;

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  • 原文地址:https://www.cnblogs.com/feiye512/p/15386442.html
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