Given a nested list of integers, return the sum of all integers in the list weighted by their depth.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Input: [[1,1],2,[1,1]]
Output: 10
Explanation: Four 1's at depth 2, one 2 at depth 1.
Example 2:
Input: [1,[4,[6]]]
Output: 27
Explanation: One 1 at depth 1, one 4 at depth 2, and one 6 at depth 3; 1 + 4*2 + 6*3 = 27.
dfs,设置一个depth即可
base case是:当某个元素为integer的时候,sum加上depth * n
否则继续dfs,depth加一
time: O(n) -- n: # of elements of input, space: O(k) -- k: depth of input
/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * public interface NestedInteger { * // Constructor initializes an empty nested list. * public NestedInteger(); * * // Constructor initializes a single integer. * public NestedInteger(int value); * * // @return true if this NestedInteger holds a single integer, rather than a nested list. * public boolean isInteger(); * * // @return the single integer that this NestedInteger holds, if it holds a single integer * // Return null if this NestedInteger holds a nested list * public Integer getInteger(); * * // Set this NestedInteger to hold a single integer. * public void setInteger(int value); * * // Set this NestedInteger to hold a nested list and adds a nested integer to it. * public void add(NestedInteger ni); * * // @return the nested list that this NestedInteger holds, if it holds a nested list * // Return null if this NestedInteger holds a single integer * public List<NestedInteger> getList(); * } */ class Solution { public int depthSum(List<NestedInteger> nestedList) { return dfs(nestedList, 1); } private int dfs(List<NestedInteger> nestedList, int depth) { int sum = 0; for(NestedInteger n : nestedList) { if(n.isInteger()) sum += depth * n.getInteger(); else sum += dfs(n.getList(), depth + 1); } return sum; } }