• Last Occurrence


    Given a target integer T and an integer array A sorted in ascending order, find the index of the last occurrence of T in A or return -1 if there is no such index.

    Assumptions

    • There can be duplicate elements in the array.

    Examples

    • A = {1, 2, 3}, T = 2, return 1
    • A = {1, 2, 3}, T = 4, return -1
    • A = {1, 2, 2, 2, 3}, T = 2, return 3

    Corner Cases

    • What if A is null or A is array of zero length? We should return -1 in this case.

    time: O(log(n)), space: O(1)

    public class Solution {
      public int lastOccur(int[] array, int target) {
        // Write your solution here
        if(array == null || array.length == 0) return -1;
        int left = 0, right = array.length - 1;
        while(left + 1 < right) {
          int mid = left + (right - left) / 2;
          if(array[mid] == target)
            left = mid;
          else if(array[mid] > target)
            right = mid;
          else
            left = mid;
        }
        if(array[right] == target)
          return right;
        else if(array[left] == target)
          return left;
        else
          return -1;
      }
    }
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  • 原文地址:https://www.cnblogs.com/fatttcat/p/10125617.html
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