• poj 2029 Get Many Persimmon Trees


    http://poj.org/problem?id=2029

     1 #include <cstdio>
     2 #include <cstring>
     3 #include <algorithm>
     4 #define maxn 200
     5 using namespace std;
     6 
     7 int dp[maxn][maxn];
     8 int n,s,t,w,h;
     9 int a[maxn][maxn];
    10 
    11 int main()
    12 {
    13     while(scanf("%d",&n)!=EOF)
    14     {
    15         if(n==0) break;
    16         scanf("%d%d",&w,&h);
    17         memset(dp,0,sizeof(dp));
    18         memset(a,0,sizeof(a));
    19         for(int i=1; i<=n; i++)
    20         {
    21             int x,y;
    22             scanf("%d%d",&x,&y);
    23             a[x][y]=1;
    24         }
    25         scanf("%d%d",&s,&t);
    26         for(int i=1; i<=w; i++)
    27         {
    28             for(int j=1; j<=h; j++)
    29             {
    30                 dp[i][j]=dp[i-1][j]+dp[i][j-1]-dp[i-1][j-1]+a[i][j];
    31             }
    32         }
    33         int ans=-1;
    34         for(int i=1; i<=w; i++)
    35         {
    36             for(int j=1; j<=h; j++)
    37             {
    38                 int x1=i-s+1;
    39                 int y1=j-t+1;
    40                 if(x1<1||y1<1) continue;
    41                 ans=max(ans,dp[i][j]-dp[x1-1][j]-dp[i][y1-1]+dp[x1-1][y1-1]);
    42             }
    43         }
    44         printf("%d
    ",ans);
    45     }
    46     return 0;
    47 }
    View Code
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  • 原文地址:https://www.cnblogs.com/fanminghui/p/3801506.html
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