• mysql 表查询


    目录

      单表查询

      多表查询

      子查询

     

    建立表:

    #创建表
    create table employee(
    id int not null unique auto_increment,
    emp_name varchar(20) not null,
    sex enum('male','female') not null default 'male', #大部分是男的
    age int(3) unsigned not null default 28,
    hire_date date not null,
    post varchar(50),
    post_comment varchar(100),
    salary double(15,2),
    office int, #一个部门一个屋子
    depart_id int
    );
    
    
    #三个部门:教学,销售,运营
    insert into employee(emp_name,sex,age,hire_date,post,salary,office,depart_id) values
    ('egon','male',18,'20170301','老男孩驻沙河办事处外交大使',7300.33,401,1), #以下是教学部
    ('alex','male',78,'20150302','teacher',1000000.31,401,1),
    ('wupeiqi','male',81,'20130305','teacher',8300,401,1),
    ('yuanhao','male',73,'20140701','teacher',3500,401,1),
    ('liwenzhou','male',28,'20121101','teacher',2100,401,1),
    ('jingliyang','female',18,'20110211','teacher',9000,401,1),
    ('jinxin','male',18,'19000301','teacher',30000,401,1),
    ('成龙','male',48,'20101111','teacher',10000,401,1),
    
    ('歪歪','female',48,'20150311','sale',3000.13,402,2),#以下是销售部门
    ('丫丫','female',38,'20101101','sale',2000.35,402,2),
    ('丁丁','female',18,'20110312','sale',1000.37,402,2),
    ('星星','female',18,'20160513','sale',3000.29,402,2),
    ('格格','female',28,'20170127','sale',4000.33,402,2),
    
    ('张野','male',28,'20160311','operation',10000.13,403,3), #以下是运营部门
    ('程咬金','male',18,'19970312','operation',20000,403,3),
    ('程咬银','female',18,'20130311','operation',19000,403,3),
    ('程咬铜','male',18,'20150411','operation',18000,403,3),
    ('程咬铁','female',18,'20140512','operation',17000,403,3)

    单表查询

    where 条件查询

    # where 条件查询
    # 功能: 对表中的数据进行过滤筛选
    1, 判断符号: =  >  <  >=  <=  !=  <>(不等于)
        # (1) 单条件的查询
        # 查询部门是sale 的所有员工姓名
        #   select emp_name from employee where post = "sale";
        
    2, 拼接添加的关键字:  and  or  not
        # (2) 多条件的查询
        # 部门是teacher , 收入大于10000的所有数据
        #   select * from employee where post="teacher" and salary > 10000;
        
    3, 查询范围与区间:  betweeh    小值 and 大值 [小值,大值] 查询两者之间的这个范围所有数据
        # (3) between .. and ..
        # 收入在1万~2万之间的所有员工姓名和收入
        #   select emp_name,salary from employee where salary between 10000 and 20000;
        # 收入不在1万~2万之间的所有员工姓名和收入
        #   select emp_name,salary from employee where salary not between 10000 and 20000;
        
    4, 查询某个值在具体某个范围里: in    in(1,2,3,4)
    # (4) null 关键字 在查询时候,需要使用is进行判断 ,不能用=
    #   select * from employee where post_comment = null;
    #   select * from employee where post_comment = '';
    #   select * from employee where post_comment is null;
    #   select * from employee where post_comment is not null;    
    # (5) in  在  ... 之中
    # 查询收入是 3000 ,4000,5000 ,8300所有原型的姓名和收入
    #   select emp_name,salary from employee where salary in (3000,4000,5000,8300) # (推荐)
    #   select emp_name,salary from employee where salary = 3000 or salary=4000 or salary=5000 or salary=8300;
    # not .. in ..
    #   select emp_name,salary from employee where salary not in (3000,4000,5000,8300);
    5, 模糊查询 like "%" "_" 通配符        
        like "%xx"  匹配以 xx 结尾的任意长度的字符串
        like "xx%"  匹配以 xx 开头的任意长度的字符串  
        like "%xx%" 匹配含有 xx 字母的任意长度的字符串
        like "_a"  个数一共是2个字符,必须以a结尾,前面字符随意
        like "a__" 个数一共是3个字符,必须以a开头,后面字符随意
    # (1) 匹配员工姓名 以on结尾的.  "%" 通配符 
    #   select emp_name from employee where emp_name like "%on";
    # (2) "_"通配符 限定字符长度使用_
    #   select emp_name from employee where emp_name like "a_e_";
    # (3) concat  (as 起别名)
    #   select  concat("姓名:",emp_name,"工资:",salary) as ceshi  from employee;
    # (4) concat_ws(拼接的符号, 参数1,参数2,参数3 .. .. )
    #   select  concat_ws(" : " , emp_name , salary) as ceshi  from employee;
    # (5) 计算每个人的年薪 可以在mysql使用四则运算(+ - * / )
    #   select  concat_ws(" : " , emp_name,  salary * 12) as ceshi200 from employee;

    group by 分组分类 查询

    # group by 分组分类 查询
    #功能: group by 字段 对当前字段进行分类 , by后面接什么字段,select 就搜什么字段
    #   select sex from employee group by sex;
    #   select post from employee group by post;
    # group_concat 按照分类的形式进行字段的拼接
    #   select group_concat(emp_name) from employee group by post;

    聚合函数

        # count 统计总数  *所有
        select count(*) from employee;
        # max   统计最大值
        select max(salary) from employee;
        # min   统计最小值
        select min(salary) from employee;
        # avg   统计平均值
        select avg(salary) from employee;
        # sum   统计总和
        select sum(salary) from employee;
        
    # 1. 查询部门名以及各部门的平均薪资 聚合函数 + 分组  配合使用
    select post,avg(salary) from employee  group by post
    
    # 2. 查询部门名以及各部门的最高薪资
    select post,max(salary) from employee  group by post
    
    # 3. 查询部门名以及各部门的最低薪资
    select post,min(salary) from employee  group by post
    
    # 4. 查询公司内男员工和女员工的个数
    select sex, count(*) from employee group by sex
    
    # 5. 查询部门名以及部门包含的所有员工名字
    select post,group_concat(emp_name)  from employee group by post
    # 可以group by 两个字段,搜索2个字段
    select post , emp_name from employee group by post , emp_name

    having 数据在分类分组之后,进行二次数据过滤,

    一般情况下配合聚合函数一起使用,分组之后过滤

    # 三.having 数据在分类分组之后,进行二次数据过滤,一般是配合group by 使用,分组之后过滤
    # 找平均薪资大于10000以上的所有部门
    select post,avg(salary) from employee group by post having avg(salary) > 10000
    
    # 1.查询各岗位内包含的员工个数小于2的岗位名、岗位内包含员工名字、个数
    select post , group_concat(emp_name) , count(*) from employee group by post having count(*) < 2 ; 
    
    # 2.查询各岗位平均薪资小于10000的岗位名、平均工资
    select post,avg(salary) from employee group by post having avg(salary) < 10000;
        
    # 3.查询各岗位平均薪资大于10000且小于20000的岗位名、平均工资
    select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) < 20000;

     order by 排序, 按照什么字段进行排序

    # asc  升序: 从小到大 (默认)
    # desc 降序: 从大到小
    select * from employee order by age #(默认是asc升序)
    select * from employee order by age desc #(默认是desc 倒序)
    
    # 1. 查询所有员工信息,先按照age升序排序,如果age相同则按照hire_date降序排序
    select * from employee order by age  , hire_date desc;
    # 2. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列
    select post, avg(salary) from employee  group by post having avg(salary) > 10000 order by avg(salary) 
    # 3. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资降序排列
    select post, avg(salary) from employee  group by post having avg(salary) > 10000 order by avg(salary) desc

    limit 限制查询条数 (数据分页)

    """limit m,n m代表从第几条数据进行查询,0代表第一条,n代表的查询几条"""
    select * from employee limit 0,5  # 从第一条数据开始搜, 搜5条数据
    select * from employee limit 5,5  # 从第六条数据开始搜, 搜5条数据    
    # 只搜索一条数据
    select * from employee limit 1
    # 只搜索3条数据
    select * from employee limit 3
    # 搜索这个表中最后一条数据
    select * from employee order by id desc limit 1

    (了解)可以使用正则表达式查询数据 (不推荐,效率不高)

        select * from employee where emp_name regexp ".*on$"; # .*? 这个?号 mysql 不识别
        select * from employee where emp_name regexp "";
        select * from employee where emp_name regexp "程.*金";

     

    多表查询

    # ### part2 多表查询
    # 内连接 : (inner join ) -> 两表或者多表满足条件的所有数据查询出来(两表之间的共有数据)
    """
    # 两表查询
    select 字段 from 表1 inner join 表2 on 必要的关联条件
    # 多表查询
    select 字段 from 表1 inner join 表2 on 必要的关联条件1 inner join 表3 on  必要的关联条件2 ... 
    """
    
    # 基本语法 inner join on + 条件
    select * from employee inner join department on employee.dep_id = department.id;
    # 用as 起别名(推荐)
    select * from employee as e inner join department as d on e.dep_id = d.id;
    # as 可以省略
    select * from employee e inner join department d on e.dep_id = d.id;
        
    # where 默认实现的就是内联查询的效果
    select * from employee , department where employee.dep_id = department.id;
    select * from employee as e , department as d where e.dep_id = d.id;
        
    # 外连接:    
        # 1.左连接(左联查询 left join )  以左表为主,右表为辅,完整查询左表所有数据,右表没有的补null
        select * from employee left join department on employee.dep_id = department.id;
        # 2.右连接(右联查询 right join ) 以右表为主,左表为辅,完整查询右表所有数据,左表没有的补null
        select * from employee right join department on employee.dep_id = department.id;
        # 3.全连接
        select * from employee left join department on employee.dep_id = department.id
        union
        select * from employee right join department on employee.dep_id = department.id

    子查询

    子查询: 嵌套查询
     (1) sql语句当中又嵌套了另外一条sql语句,用()括号抱起来,表达一个整体
     (2) 一般应用在from 字符后面(表达一张表),where 子句后面(表达一个条件)
     (3) 查询速度从快到慢 : 单表查询 -> 联表速度 -> 子查询

      一.找出平均年龄大于25岁以上的部门 

    # (1) 普通where
    select 
        d.id,d.name
    from 
        employee as e,department as d
    where 
        e.dep_id = d.id
    group by 
        d.id,d.name
    having 
        avg(e.age) > 25;
        
    # (2) inner join 
    select 
        d.id,d.name
    from 
        employee as e inner join department as d on e.dep_id = d.id
    group by 
        d.id,d.name
    having 
        avg(e.age) > 25;
        
    # (3)子查询
    # 1.先选出平均年龄大于25岁的部门id
    select dep_id from employee group by dep_id having avg(age) > 25; # 201 202
    # 2.通过部门id,找部门的名字
    select name  from department where id in (201,202);
    # 3.综合拼接
    select id,name  from department where id in (select dep_id from employee group by dep_id having avg(age) > 25);

     

      二.查看技术部门员工姓名

    # (1) 普通where
    select 
        e.name,d.name
    from    
        employee as e , department as d
    where 
        e.dep_id = d.id
        and
        d.name = "技术"
    
    # (2) inner join 写法
    select 
        e.name,d.name
    from    
        employee as e inner join department as d  on e.dep_id = d.id
    where     
        # 非必要条件写在where字句中
        d.name = "技术"
    
    # (3) 子查询
    # 1.找计数部门对应的id
    select id from department where name ="技术"
    # 2.通过id找员工姓名
    select name from employee where dep_id = 200;
    # 3.综合拼接
    select name,dep_id from employee where dep_id = (select id from department where name ="技术");

      三.查看哪个部门没员工

    # 联表差生null值,谁是null谁就没员工
    select 
        d.id,d.name
    from 
        department as d left join  employee as e on e.dep_id = d.id
    where
        e.id is null
    
    
    # 1.查询员工都在哪些部门 (200 , 201 202 204)
    select dep_id from employee group by dep_id 
    # 2.把不在这些部门的数据找出来
    select id from department where id not in (200,201,202,204)
    # 3.综合拼接
    select id,name  from department where id not in (select dep_id from employee group by dep_id );

      四.查询大于平均年龄的员工名与年龄

    # 如果平均年龄是25;
    select name,age from employee where age > 25
    # 计算平均年龄
    select avg(age) from employee
    # 综合拼接
    select name,age from employee where age > (select avg(age) from employee);

      五.把大于其本部门平均年龄的员工名和姓名查出来

    # 1.先计算各部门平均年龄是多少
    select dep_id,avg(age) as avg_age from employee group by dep_id
    
    # 2.把查询各部门的平均年龄和过去employee做联表,变成更大的表方便后期做单表查询;
    select 
    *
    from 
        employee as t1 inner join (1号数据) as t2 on t1.dep_id = t2.dep_id
        
    # 3.综合拼接
    select 
    *
    from 
        employee as t1 inner join (select dep_id,avg(age) as avg_age from employee group by dep_id) as t2 on t1.dep_id = t2.dep_id
    
    # 4.做最后的条件帅选
    select 
    *
    from 
        employee as t1 inner join (select dep_id,avg(age) as avg_age from employee group by dep_id) as t2 on t1.dep_id = t2.dep_id
    where 
        t1.age > t2.avg_age

      六.查询每个部门最新入职的那位员工  # 利用上一套数据表进行查询

    # 1.找每个部门最大的入职时间
    select post , max(hire_date) as max_date from employee group by post;
    # 2.把子查询搜索出来的数据和 employee 联合成一张更大的表,做一次单表查询
    select 
        *
    from 
        employee as t1 inner join  (1号查询出来的数据) as t2 on t1.post = t2.post
    where
        t1.hire_date = t2.max_date
    
    # 综合拼接
    select 
        t1.emp_name,t1.hire_date
    from 
        employee as t1 inner join  (select post , max(hire_date) as max_date from employee group by post) as t2 on t1.post = t2.post
    where
        t1.hire_date = t2.max_date

      七.带EXISTS关键字的子查询

    """
    EXISTS 关键字,表达存在
        如果内层sql 能够查询到数据,返回True ,外层sql执行查询语句
        如果内层sql 不能够查询到数据,返回False ,外层sql不执行查询语句
    """
    select * from employee where exists ( select * from employee where id = 100);
    """
    子查询总结:
        子查询可以单独作为一个临时数据表,临时数据,临时字段
        一般用在 from where select 子句后面
        可以通过查询出来的临时数据和另外的表做一次联表,变成更大的表,然后做单表查询,以得到想要的结果.    
    """
    # 额外 distinct 去重[尝试操作]
    select distinct depart_id from employee;10.11 
    好好学习,天天向上。
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  • 原文地址:https://www.cnblogs.com/f211/p/13814608.html
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