• 【python】解析sql语句使用的表名


    脚本内容如下:

    import ply.lex as lex, re
    
    
    def extract_table_name_from_sql(sql_str):
    
        # remove the /* */ comments
        q = re.sub(r"/\*[^*]*\*+(?:[^*/][^*]*\*+)*/", "", sql_str)
    
        # remove whole line -- and # comments
        lines = [line for line in q.splitlines() if not re.match("^\s*(--|#)", line)]
    
        # remove trailing -- and # comments
        q = " ".join([re.split("--|#", line)[0] for line in lines])
    
        # split on blanks, parens and semicolons
        tokens = re.split(r"[\s)(;]+", q)
    
        # scan the tokens. if we see a FROM or JOIN, we set the get_next
        # flag, and grab the next one (unless it's SELECT).
    
        result = set()
        get_next = False
        for token in tokens:
            if get_next:
                if token.lower() not in ["", "select"]:
                    result.add(token)
                get_next = False
            get_next = token.lower() in ["from", "join"]
    
        return result
    
    sql2="SELECT a.time_updated_server/1000,content,nick,name FROM      " \
         "table1 a JOIN   " \
         "table2 b ON a.sender_id = b.user_id JOIN table3 c ON a.channel_id = c.channel_id JOIN table4 d ON c.store_id = d.store_id WHERE sender_id NOT IN(SELECT user_id FROM table5 WHERE store_id IN ('agent_store:1', 'ask:1')) AND to_timestamp(a.time_updated_server/1000)::date >= '2014-05-01' GROUP BY 1,2,3,4 HAVING sum(1) > 500 ORDER BY 1 ASC"
    print(extract_table_name_from_sql(sql2))
    

    本文转自:
    https://blog.csdn.net/onwingsofsong/article/details/83546768?utm_medium=distribute.pc_relevant.none-task-blog-2%7Edefault%7EBlogCommendFromMachineLearnPai2%7Edefault-7.control&depth_1-utm_source=distribute.pc_relevant.none-task-blog-2%7Edefault%7EBlogCommendFromMachineLearnPai2%7Edefault-7.control

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  • 原文地址:https://www.cnblogs.com/erlou96/p/16878338.html
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