• [LeetCode] Range Sum Query


    Range Sum Query - Immutable

    Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.

    Example:

    Given nums = [-2, 0, 3, -5, 2, -1]
    
    sumRange(0, 2) -> 1
    sumRange(2, 5) -> -1
    sumRange(0, 5) -> -3

    Note:

    1. You may assume that the array does not change.
    2. There are many calls to sumRange function.
     1 class NumArray {
     2 private:
     3     vector<int> acc;
     4     
     5 public:
     6     NumArray(vector<int> &nums) {
     7         acc.push_back(0);
     8         for (auto n : nums) {
     9             acc.push_back(acc.back() + n);
    10         }
    11     }
    12 
    13     int sumRange(int i, int j) {
    14         return acc[j + 1] - acc[i];
    15     }
    16 };
    17 
    18 
    19 // Your NumArray object will be instantiated and called as such:
    20 // NumArray numArray(nums);
    21 // numArray.sumRange(0, 1);
    22 // numArray.sumRange(1, 2);

    Range Sum Query 2D - Immutable

    Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2).

    Range Sum Query 2D
    The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which contains sum = 8.

    Example:

    Given matrix = [
      [3, 0, 1, 4, 2],
      [5, 6, 3, 2, 1],
      [1, 2, 0, 1, 5],
      [4, 1, 0, 1, 7],
      [1, 0, 3, 0, 5]
    ]
    
    sumRegion(2, 1, 4, 3) -> 8
    sumRegion(1, 1, 2, 2) -> 11
    sumRegion(1, 2, 2, 4) -> 12

    Note:

    1. You may assume that the matrix does not change.
    2. There are many calls to sumRegion function.
    3. You may assume that row1 ≤ row2 and col1 ≤ col2.

     

     1 class NumMatrix {
     2 private:
     3     vector<vector<int>> acc;
     4 public:
     5     NumMatrix(vector<vector<int>> &matrix) {
     6         if (matrix.empty()) return;
     7         int n = matrix.size(), m = matrix[0].size();
     8         acc.resize(n + 1, vector<int>(m + 1));
     9         for (int i = 0; i <= n; ++i) acc[i][0] = 0;
    10         for (int j = 0; j <= m; ++j) acc[0][j] = 0;
    11         for (int i = 1; i <= n; ++i) {
    12             for (int j = 1; j <= m; ++j) {
    13                 acc[i][j] = acc[i][j-1] + acc[i-1][j] - acc[i-1][j-1] + matrix[i-1][j-1];
    14             }
    15         } 
    16     }
    17 
    18     int sumRegion(int row1, int col1, int row2, int col2) {
    19         return acc[row2+1][col2+1] - acc[row1][col2+1] - acc[row2+1][col1] + acc[row1][col1];
    20     }
    21 };
    22 
    23 
    24 // Your NumMatrix object will be instantiated and called as such:
    25 // NumMatrix numMatrix(matrix);
    26 // numMatrix.sumRegion(0, 1, 2, 3);
    27 // numMatrix.sumRegion(1, 2, 3, 4);
  • 相关阅读:
    Lua 数组
    javascript debugger
    Lua 字符串
    警告
    Lua中获取table长度
    Lua 运算符
    Lua 函数
    lua if 流程控制
    pairs 和 ipairs 的区别
    Lua 循环
  • 原文地址:https://www.cnblogs.com/easonliu/p/4969767.html
Copyright © 2020-2023  润新知