Problem:
Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array.
Note:
The array size can be very large. Solution that uses too much extra space will not pass the judge.
Example:
int[] nums = new int[] {1,2,3,3,3};
Solution solution = new Solution(nums);
// pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning.
solution.pick(3);
// pick(1) should return 0. Since in the array only nums[0] is equal to 1.
solution.pick(1);
思路:
Solution (C++):
vector<int> _nums;
Solution(vector<int>& nums) {
_nums = nums;
}
int pick(int target) {
int count = 0, res = -1;
for (int i = 0; i < _nums.size(); ++i) {
if (_nums[i] != target) continue;
if (count == 0) { res = i; ++count; }
else {
++count;
if (rand()%count == 0) res = i;
}
}
return res;
}
性能:
Runtime: 96 ms Memory Usage: 16.4 MB
思路:
Solution (C++):
性能:
Runtime: ms Memory Usage: MB