Problem A
A Special "[H]appy Birthday" Song!!!
There are n people (excluding myself) in my 30th birthday party. They sing the traditional "happy birthday" song:
Happy birthday to you! Happy birthday to you! Happy birthday to Rujia! Happy birthday to you!!!
Since I love music, I want to hear something more interesting, not that everyone sings together. Ah yes, I want one person to sing one word!
For example, there are three people: Mom, Dad, Girlfriend, I'd like them to sing like this:
Mom: Happy Dad: birthday Girlfriend: to Mom: you Dad: Happy Girlfriend: birthday Mom: to Dad: you Girlfriend: Happy Mom: birthday Dad: to Girlfriend: Rujia Mom: Happy Dad: birthday Girlfriend: to Mom: you
Very nice, right? What if there are more than 16 people? That's easy: repeat the song until everyone has sung at least once :)
Please, don't stop in the middle of the song.
Input
There is only one test case. The first line contains a single integer n (1<=n<=100). Then each of the next n lines contains a capitalized name (i.e. one upper-case letter followed by zero or more lower-case letters). Each name contains at most 100 characters and do not have whitespace characters inside.
Output
Output the song, formatted as above.
Sample Input
3 Mom Dad Girlfriend
Output for the Sample Input
Mom: Happy Dad: birthday Girlfriend: to Mom: you Dad: Happy Girlfriend: birthday Mom: to Dad: you Girlfriend: Happy Mom: birthday Dad: to Girlfriend: Rujia Mom: Happy Dad: birthday Girlfriend: to Mom: you
#include<stdio.h> #include<math.h> int main() { int n,p,i,j,k; char s[100][100]; char c[16][100]={"Happy","birthday","to","you","Happy","birthday","to","you","Happy","birthday","to","Rujia","Happy","birthday","to","you"}; while(scanf("%d",&n)) { for(i=0;i<n;i++) scanf("%s",s[i]); if(n>16) p=ceil(n/16)+1; for(i=0,j=0,k=0;j<16*p;i++,j++,k++) { if(i==n) i=0; if(j==16) k=0; printf("%s: %s\n",s[i],c[k]); } } return 0; }