• C#大数计算 .Net Framework4.0以下


     在.net framework4.0以下的框架中C#不支持大数计算.若是需要对大数进行计算就需要自己实现计算方法,本类借鉴网上开源的算法.重载了如下运算符.    +,++,-,--,*,<<,>>,~,-,==,!=,>,<,>=,<=,/,%,&,|,^
    实现了如下函数: Abs(),ToString(),ToHexString(),BitCount(),Sqrt()
            对于使用.net framework 4.0及以上版本的小伙伴可以使用微软提供的API来实现,听说效率高到爆.
    https://msdn.microsoft.com/zh-cn/library/system.numerics.biginteger(v=vs.110).aspx

    /// <summary>
            /// 求 BigInteger 的绝对值
            /// </summary>
            /// <returns>返回 BigInteger 的绝对值</returns>
            public BigInteger Abs()
            /// <summary>
            ///  返回一个字符串,表示符号和大小的 BigInteger 在10进制数格式.
            /// </summary>
            /// <returns>表示符号和大小的 BigInteger 在10进制数格式</returns>
            public override string ToString()
            /// <summary>
            /// 返回一个字符串, 表示符号和大小的 BigInteger指定进制数的格式.
            /// </summary>
            /// <param name="radix">进制数2-36</param>
            /// <returns>
            ///如果 BigInteger 的值在 10进制 中为-255, 则ToString (16) 返回 "-FF"
            ///</returns>
            public string ToString(int radix)
            /// <summary>
            /// 返回BigInteger的十六进制字符串
            /// </summary>
            /// <returns>
            /// 1) 如果 BigInteger 的值为255在 10进制 中, 则ToHexString () 返回 "FF"
            /// 2) 如果 BigInteger 的值为-255 在 10进制 中, 则ToHexString () 返回 "..。FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF01 ",           这是2的补语表示-255。
            /// </returns>
            public string ToHexString()
            /// <summary>
            /// 返回 BigInteger 中最重要位的位置。
            /// 结果为 0, 如果 BigInteger 的值为 0... 0000 0000
            /// 结果为 1, 如果 BigInteger 的值为 0... 0000 0001
            /// 结果为 2, 如果 BigInteger 的值为 0... 0000 0010
            /// 结果为 3, 如果 BigInteger 的值为 0... 0000 0011
            /// </summary>
            /// <returns></returns>
            public int BitCount()   /// <summary>
            /// 返回 BigInteger 中最重要位的位置。
            /// 结果为 0, 如果 BigInteger 的值为 0... 0000 0000
            /// 结果为 1, 如果 BigInteger 的值为 0... 0000 0001
            /// 结果为 2, 如果 BigInteger 的值为 0... 0000 0010
            /// 结果为 3, 如果 BigInteger 的值为 0... 0000 0011
            /// </summary>
            /// <returns></returns>
            public int BitCount()
            /// <summary>
            /// 计算当前BigInteger的平方根
            /// </summary>
            /// <returns>返回一个等效于 BigInteger 的整数平方根的值。</returns>
            public BigInteger Sqrt()
    namespace BigInteger
    {
        using System;
        /// <summary>
        /// 大数之间的常用数据运算
        /// </summary>
        public class BigInteger
        {
            private const int maxLength = 70;
            public static readonly int[] primesBelow2000 = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997, 1009, 1013, 1019, 1021, 1031, 1033, 1039, 1049, 1051, 1061, 1063, 1069, 1087, 1091, 1093, 1097, 1103, 1109, 1117, 1123, 1129, 1151, 1153, 1163, 1171, 1181, 1187, 1193, 1201, 1213, 1217, 1223, 1229, 1231, 1237, 1249, 1259, 1277, 1279, 1283, 1289, 1291, 1297, 1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399, 1409, 1423, 1427, 1429, 1433, 1439, 1447, 1451, 1453, 1459, 1471, 1481, 1483, 1487, 1489, 1493, 1499, 1511, 1523, 1531, 1543, 1549, 1553, 1559, 1567, 1571, 1579, 1583, 1597, 1601, 1607, 1609, 1613, 1619, 1621, 1627, 1637, 1657, 1663, 1667, 1669, 1693, 1697, 1699, 1709, 1721, 1723, 1733, 1741, 1747, 1753, 1759, 1777, 1783, 1787, 1789, 1801, 1811, 1823, 1831, 1847, 1861, 1867, 1871, 1873, 1877, 1879, 1889, 1901, 1907, 1913, 1931, 1933, 1949, 1951, 1973, 1979, 1987, 1993, 1997, 1999 };
            private uint[] data = null;
            public int dataLength;
            /// <summary>
            /// 构造函数 (BigInteger 的默认值为 0)
            /// </summary>
            public BigInteger()
            {
                data = new uint[maxLength];
                dataLength = 1;
            }
            /// <summary>
            /// 构造函数 (由 long 提供的默认值)
            /// </summary>
            /// <param name="value"></param>
            public BigInteger(long value)
            {
                data = new uint[maxLength];
                long tempVal = value;
                dataLength = 0;
                while (value != 0 && dataLength < maxLength)
                {
                    data[dataLength] = (uint)(value & 0xFFFFFFFF);
                    value >>= 32;
                    dataLength++;
                }
                if (tempVal > 0)
                {
                    if (value != 0 || (data[maxLength - 1] & 0x80000000) != 0)
                        throw (new ArithmeticException("构造函数中的正溢出."));
                }
                else if (tempVal < 0)
                {
                    if (value != -1 || (data[dataLength - 1] & 0x80000000) == 0)
                        throw (new ArithmeticException("构造函数中的负溢出."));
                }
                if (dataLength == 0)
                    dataLength = 1;
            }
            /// <summary>
            /// 构造函数 (由 ulong 提供的默认值)
            /// </summary>
            /// <param name="value"></param>
            public BigInteger(ulong value)
            {
                data = new uint[maxLength];
                dataLength = 0;
                while (value != 0 && dataLength < maxLength)
                {
                    data[dataLength] = (uint)(value & 0xFFFFFFFF);
                    value >>= 32;
                    dataLength++;
                }
                if (value != 0 || (data[maxLength - 1] & 0x80000000) != 0)
                    throw (new ArithmeticException("构造函数中的正溢出."));
                if (dataLength == 0)
                    dataLength = 1;
            }
            /// <summary>
            /// 构造函数 (由 BigInteger 提供的默认值)
            /// </summary>
            /// <param name="bi"></param>
            public BigInteger(BigInteger bi)
            {
                data = new uint[maxLength];
                dataLength = bi.dataLength;
                for (int i = 0; i < dataLength; i++)
                    data[i] = bi.data[i];
            }
            /// <summary>
            /// 构造函数 (由指定基的数字字符串提供的默认值)
            /// 示例 (10进制)
            /// 在 10进制 中初始化默认值为1234年的 "a"
            ///       BigInteger a = new BigInteger ("1234", 10)
            /// 初始化默认值为-1234 的 "a"
            ///       BigInteger a = new BigInteger ("-1234", 10)
            /// 示例 (16进制)
            /// 在 base 16 中初始化具有默认值0x1D4F 的 "a"
            ///       BigInteger a = new BigInteger ("1D4F", 16)
            /// 使用默认值0x1d4f 初始化 "a"
            ///       BigInteger a = new BigInteger ("-1D4F", 16)
            /// </summary>
            /// <param name="value"></param>
            /// <param name="radix">进制</param>
            public BigInteger(string value, int radix)
            {
                BigInteger multiplier = new BigInteger(1);
                BigInteger result = new BigInteger();
                value = (value.ToUpper()).Trim();
                int limit = 0;
                if (value[0] == '-')
                    limit = 1;
                for (int i = value.Length - 1; i >= limit; i--)
                {
                    int posVal = (int)value[i];
                    if (posVal >= '0' && posVal <= '9')
                        posVal -= '0';
                    else if (posVal >= 'A' && posVal <= 'Z')
                        posVal = (posVal - 'A') + 10;
                    else
                        posVal = 9999999;
                    if (posVal >= radix)
                        throw (new ArithmeticException("构造函数中的字符串无效."));
                    else
                    {
                        if (value[0] == '-')
                            posVal = -posVal;
                        result = result + (multiplier * posVal);
                        if ((i - 1) >= limit)
                            multiplier = multiplier * radix;
                    }
                }
                if (value[0] == '-')
                {
                    if ((result.data[maxLength - 1] & 0x80000000) == 0)
                        throw (new ArithmeticException("构造函数中的负溢出."));
                }
                else
                {
                    if ((result.data[maxLength - 1] & 0x80000000) != 0)
                        throw (new ArithmeticException("构造函数中的正溢出."));
                }
                data = new uint[maxLength];
                for (int i = 0; i < result.dataLength; i++)
                    data[i] = result.data[i];
                dataLength = result.dataLength;
            }
            /// <summary>
            /// 构造函数 (由字节数组提供的默认值)
            /// 输入字节数组的最低索引 (i. e [0]) 应包含数字中最重要的字节, 最高索引应包含最不重要的字节。
            /// 例如:
            /// 在 16进制 中初始化具有默认值0x1D4F 的 "a"
            ///       byte[] temp = {0x1D, 0x4F};
            ///       BigInteger a = new BigInteger (temp);
            /// 请注意, 此初始化方法不允许指定符号.
            /// </summary>
            /// <param name="inData"></param>
            public BigInteger(byte[] inData)
            {
                dataLength = inData.Length >> 2;
                int leftOver = inData.Length & 0x3;
                if (leftOver != 0)
                    dataLength++;
                if (dataLength > maxLength)
                    throw (new ArithmeticException("构造函数中的字节溢出."));
                data = new uint[maxLength];
                for (int i = inData.Length - 1, j = 0; i >= 3; i -= 4, j++)
                {
                    data[j] = (uint)((inData[i - 3] << 24) + (inData[i - 2] << 16) + (inData[i - 1] << 8) + inData[i]);
                }
                if (leftOver == 1)
                    data[dataLength - 1] = (uint)inData[0];
                else if (leftOver == 2)
                    data[dataLength - 1] = (uint)((inData[0] << 8) + inData[1]);
                else if (leftOver == 3)
                    data[dataLength - 1] = (uint)((inData[0] << 16) + (inData[1] << 8) + inData[2]);
                while (dataLength > 1 && data[dataLength - 1] == 0)
                    dataLength--;
            }
            /// <summary>
            /// 构造函数 (由指定长度的字节数组提供的默认值.)
            /// </summary>
            /// <param name="inData">字节数组</param>
            /// <param name="inLen">长度</param>
            public BigInteger(byte[] inData, int inLen)
            {
                dataLength = inLen >> 2;
                int leftOver = inLen & 0x3;
                if (leftOver != 0)
                    dataLength++;
                if (dataLength > maxLength || inLen > inData.Length)
                    throw (new ArithmeticException("构造函数中的字节溢出."));
                data = new uint[maxLength];
                for (int i = inLen - 1, j = 0; i >= 3; i -= 4, j++)
                {
                    data[j] = (uint)((inData[i - 3] << 24) + (inData[i - 2] << 16) + (inData[i - 1] << 8) + inData[i]);
                }
                if (leftOver == 1)
                    data[dataLength - 1] = (uint)inData[0];
                else if (leftOver == 2)
                    data[dataLength - 1] = (uint)((inData[0] << 8) + inData[1]);
                else if (leftOver == 3)
                    data[dataLength - 1] = (uint)((inData[0] << 16) + (inData[1] << 8) + inData[2]);
                if (dataLength == 0)
                    dataLength = 1;
                while (dataLength > 1 && data[dataLength - 1] == 0)
                    dataLength--;
            }
            /// <summary>
            /// 构造函数 (由无符号整数数组提供的默认值)
            /// </summary>
            /// <param name="inData"></param>
            public BigInteger(uint[] inData)
            {
                dataLength = inData.Length;
                if (dataLength > maxLength)
                    throw (new ArithmeticException("构造函数中的字节溢出."));
                data = new uint[maxLength];
                for (int i = dataLength - 1, j = 0; i >= 0; i--, j++)
                    data[j] = inData[i];
                while (dataLength > 1 && data[dataLength - 1] == 0)
                    dataLength--;
            }
            public static implicit operator BigInteger(long value)
            {
                return (new BigInteger(value));
            }
            public static implicit operator BigInteger(ulong value)
            {
                return (new BigInteger(value));
            }
            public static implicit operator BigInteger(int value)
            {
                return (new BigInteger((long)value));
            }
            public static implicit operator BigInteger(uint value)
            {
                return (new BigInteger((ulong)value));
            }
            /// <summary>
            /// 加法运算符的重载
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>bi1与bi2的加法运算结果</returns>
            public static BigInteger operator +(BigInteger bi1, BigInteger bi2)
            {
                BigInteger result = new BigInteger();
                result.dataLength = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                long carry = 0;
                for (int i = 0; i < result.dataLength; i++)
                {
                    long sum = (long)bi1.data[i] + (long)bi2.data[i] + carry;
                    carry = sum >> 32;
                    result.data[i] = (uint)(sum & 0xFFFFFFFF);
                }
                if (carry != 0 && result.dataLength < maxLength)
                {
                    result.data[result.dataLength] = (uint)(carry);
                    result.dataLength++;
                }
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                int lastPos = maxLength - 1;
                if ((bi1.data[lastPos] & 0x80000000) == (bi2.data[lastPos] & 0x80000000) && (result.data[lastPos] & 0x80000000) != (bi1.data[lastPos] & 0x80000000))
                {
                    throw (new ArithmeticException("加法运算溢出."));
                }
                return result;
            }
            /// <summary>
            /// 一元 ++ 运算符的重载
            /// </summary>
            /// <param name="bi1"></param>
            /// <returns></returns>
            public static BigInteger operator ++(BigInteger bi1)
            {
                BigInteger result = new BigInteger(bi1);
                long val, carry = 1;
                int index = 0;
                while (carry != 0 && index < maxLength)
                {
                    val = (long)(result.data[index]);
                    val++;
                    result.data[index] = (uint)(val & 0xFFFFFFFF);
                    carry = val >> 32;
                    index++;
                }
                if (index > result.dataLength)
                    result.dataLength = index;
                else
                {
                    while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                        result.dataLength--;
                }
                int lastPos = maxLength - 1;
                if ((bi1.data[lastPos] & 0x80000000) == 0 && (result.data[lastPos] & 0x80000000) != (bi1.data[lastPos] & 0x80000000))
                {
                    throw (new ArithmeticException("++运算溢出."));
                }
                return result;
            }
            /// <summary>
            /// 减法运算符的重载
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>bi1与bi2的减法运算结果</returns>
            public static BigInteger operator -(BigInteger bi1, BigInteger bi2)
            {
                BigInteger result = new BigInteger();
                result.dataLength = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                long carryIn = 0;
                for (int i = 0; i < result.dataLength; i++)
                {
                    long diff;
                    diff = (long)bi1.data[i] - (long)bi2.data[i] - carryIn;
                    result.data[i] = (uint)(diff & 0xFFFFFFFF);
                    if (diff < 0)
                        carryIn = 1;
                    else
                        carryIn = 0;
                }
                if (carryIn != 0)
                {
                    for (int i = result.dataLength; i < maxLength; i++)
                        result.data[i] = 0xFFFFFFFF;
                    result.dataLength = maxLength;
                }
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                int lastPos = maxLength - 1;
                if ((bi1.data[lastPos] & 0x80000000) != (bi2.data[lastPos] & 0x80000000) && (result.data[lastPos] & 0x80000000) != (bi1.data[lastPos] & 0x80000000))
                {
                    throw (new ArithmeticException("减法运算溢出."));
                }
                return result;
            }
            /// <summary>
            /// 一元--运算符的重载
            /// </summary>
            /// <param name="bi1"></param>
            /// <returns></returns>
            public static BigInteger operator --(BigInteger bi1)
            {
                BigInteger result = new BigInteger(bi1);
                long val;
                bool carryIn = true;
                int index = 0;
                while (carryIn && index < maxLength)
                {
                    val = (long)(result.data[index]);
                    val--;
                    result.data[index] = (uint)(val & 0xFFFFFFFF);
                    if (val >= 0)
                        carryIn = false;
                    index++;
                }
                if (index > result.dataLength)
                    result.dataLength = index;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                int lastPos = maxLength - 1;
                if ((bi1.data[lastPos] & 0x80000000) != 0 && (result.data[lastPos] & 0x80000000) != (bi1.data[lastPos] & 0x80000000))
                {
                    throw (new ArithmeticException("--运算溢出."));
                }
                return result;
            }
            /// <summary>
            /// 乘法运算符的重载
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>bi1与bi2的乘法运算结果</returns>
            public static BigInteger operator *(BigInteger bi1, BigInteger bi2)
            {
                int lastPos = maxLength - 1;
                bool bi1Neg = false, bi2Neg = false;
                try
                {
                    if ((bi1.data[lastPos] & 0x80000000) != 0)
                    {
                        bi1Neg = true;
                        bi1 = -bi1;
                    }
                    if ((bi2.data[lastPos] & 0x80000000) != 0)
                    {
                        bi2Neg = true;
                        bi2 = -bi2;
                    }
                }
                catch (Exception) { }
                BigInteger result = new BigInteger();
                try
                {
                    for (int i = 0; i < bi1.dataLength; i++)
                    {
                        if (bi1.data[i] == 0)
                            continue;
                        ulong mcarry = 0;
                        for (int j = 0, k = i; j < bi2.dataLength; j++, k++)
                        {
                            ulong val = ((ulong)bi1.data[i] * (ulong)bi2.data[j]) + (ulong)result.data[k] + mcarry;
                            result.data[k] = (uint)(val & 0xFFFFFFFF);
                            mcarry = (val >> 32);
                        }
                        if (mcarry != 0)
                            result.data[i + bi2.dataLength] = (uint)mcarry;
                    }
                }
                catch (Exception)
                {
                    throw (new ArithmeticException("乘法溢出."));
                }
                result.dataLength = bi1.dataLength + bi2.dataLength;
                if (result.dataLength > maxLength)
                    result.dataLength = maxLength;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                if ((result.data[lastPos] & 0x80000000) != 0)
                {
                    if (bi1Neg != bi2Neg && result.data[lastPos] == 0x80000000)
                    {
                        if (result.dataLength == 1)
                            return result;
                        else
                        {
                            bool isMaxNeg = true;
                            for (int i = 0; i < result.dataLength - 1 && isMaxNeg; i++)
                            {
                                if (result.data[i] != 0)
                                    isMaxNeg = false;
                            }
                            if (isMaxNeg)
                                return result;
                        }
                    }
                    throw (new ArithmeticException("乘法溢出."));
                }
                if (bi1Neg != bi2Neg)
                    return -result;
                return result;
            }
            /// <summary>
            ///  一元 << 运算符的重载(左移位运算)
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="shiftVal">移动位数</param>
            /// <returns></returns>
            public static BigInteger operator <<(BigInteger bi1, int shiftVal)
            {
                BigInteger result = new BigInteger(bi1);
                result.dataLength = ShiftLeft(result.data, shiftVal);
                return result;
            }
            private static int ShiftLeft(uint[] buffer, int shiftVal)
            {
                int shiftAmount = 32;
                int bufLen = buffer.Length;
                while (bufLen > 1 && buffer[bufLen - 1] == 0)
                    bufLen--;
                for (int count = shiftVal; count > 0; )
                {
                    if (count < shiftAmount)
                        shiftAmount = count;
                    ulong carry = 0;
                    for (int i = 0; i < bufLen; i++)
                    {
                        ulong val = ((ulong)buffer[i]) << shiftAmount;
                        val |= carry;
                        buffer[i] = (uint)(val & 0xFFFFFFFF);
                        carry = val >> 32;
                    }
                    if (carry != 0)
                    {
                        if (bufLen + 1 <= buffer.Length)
                        {
                            buffer[bufLen] = (uint)carry;
                            bufLen++;
                        }
                    }
                    count -= shiftAmount;
                }
                return bufLen;
            }
            /// <summary>
            /// 一元 >> 运算符的重载(右移位运算)
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="shiftVal">移动位数</param>
            /// <returns></returns>
            public static BigInteger operator >>(BigInteger bi1, int shiftVal)
            {
                BigInteger result = new BigInteger(bi1);
                result.dataLength = ShiftRight(result.data, shiftVal);
                if ((bi1.data[maxLength - 1] & 0x80000000) != 0)
                {
                    for (int i = maxLength - 1; i >= result.dataLength; i--)
                        result.data[i] = 0xFFFFFFFF;
                    uint mask = 0x80000000;
                    for (int i = 0; i < 32; i++)
                    {
                        if ((result.data[result.dataLength - 1] & mask) != 0)
                            break;
                        result.data[result.dataLength - 1] |= mask;
                        mask >>= 1;
                    }
                    result.dataLength = maxLength;
                }
                return result;
            }
            private static int ShiftRight(uint[] buffer, int shiftVal)
            {
                int shiftAmount = 32;
                int invShift = 0;
                int bufLen = buffer.Length;
                while (bufLen > 1 && buffer[bufLen - 1] == 0)
                    bufLen--;
                for (int count = shiftVal; count > 0; )
                {
                    if (count < shiftAmount)
                    {
                        shiftAmount = count;
                        invShift = 32 - shiftAmount;
                    }
                    ulong carry = 0;
                    for (int i = bufLen - 1; i >= 0; i--)
                    {
                        ulong val = ((ulong)buffer[i]) >> shiftAmount;
                        val |= carry;
                        carry = ((ulong)buffer[i]) << invShift;
                        buffer[i] = (uint)(val);
                    }
                    count -= shiftAmount;
                }
                while (bufLen > 1 && buffer[bufLen - 1] == 0)
                    bufLen--;
                return bufLen;
            }
            /// <summary>
            /// 非运算符重载 (1 的补数)
            /// </summary>
            /// <param name="bi1">需要取非的 BigInteger</param>
            /// <returns>返回1的补数</returns>
            public static BigInteger operator ~(BigInteger bi1)
            {
                BigInteger result = new BigInteger(bi1);
                for (int i = 0; i < maxLength; i++)
                    result.data[i] = (uint)(~(bi1.data[i]));
                result.dataLength = maxLength;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                return result;
            }
            /// <summary>
            /// 否定运算符的重载 (2 的补数)
            /// </summary>
            /// <param name="bi1">需要取否的 BigInteger</param>
            /// <returns>返回2的补数</returns>
            public static BigInteger operator -(BigInteger bi1)
            {
                if (bi1.dataLength == 1 && bi1.data[0] == 0)
                    return (new BigInteger());
                BigInteger result = new BigInteger(bi1);
                for (int i = 0; i < maxLength; i++)
                    result.data[i] = (uint)(~(bi1.data[i]));
                long val, carry = 1;
                int index = 0;
                while (carry != 0 && index < maxLength)
                {
                    val = (long)(result.data[index]);
                    val++;
                    result.data[index] = (uint)(val & 0xFFFFFFFF);
                    carry = val >> 32;
                    index++;
                }
                if ((bi1.data[maxLength - 1] & 0x80000000) == (result.data[maxLength - 1] & 0x80000000))
                    throw (new ArithmeticException("在否定运算中溢出."));
                result.dataLength = maxLength;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                return result;
            }
            #region 相等运算符的重载
            public static bool operator ==(BigInteger bi1, BigInteger bi2)
            {
                return bi1.Equals(bi2);
            }
            public static bool operator !=(BigInteger bi1, BigInteger bi2)
            {
                return !(bi1.Equals(bi2));
            }
            public override bool Equals(object o)
            {
                BigInteger bi = (BigInteger)o;
                if (this.dataLength != bi.dataLength)
                    return false;
                for (int i = 0; i < this.dataLength; i++)
                {
                    if (this.data[i] != bi.data[i])
                        return false;
                }
                return true;
            }
            #endregion
            /// <summary>
            /// 获取当前 BigInteger 在10进制数格式字符串的哈希代码
            /// </summary>
            /// <returns></returns>
            public override int GetHashCode()
            {
                return this.ToString().GetHashCode();
            }
            #region 不等式运算符的重载
            public static bool operator >(BigInteger bi1, BigInteger bi2)
            {
                int pos = maxLength - 1;
                if ((bi1.data[pos] & 0x80000000) != 0 && (bi2.data[pos] & 0x80000000) == 0)
                    return false;
                else if ((bi1.data[pos] & 0x80000000) == 0 && (bi2.data[pos] & 0x80000000) != 0)
                    return true;
                int len = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                for (pos = len - 1; pos >= 0 && bi1.data[pos] == bi2.data[pos]; pos--) ;
                if (pos >= 0)
                {
                    if (bi1.data[pos] > bi2.data[pos])
                        return true;
                    return false;
                }
                return false;
            }
            public static bool operator <(BigInteger bi1, BigInteger bi2)
            {
                int pos = maxLength - 1;
                if ((bi1.data[pos] & 0x80000000) != 0 && (bi2.data[pos] & 0x80000000) == 0)
                    return true;
                else if ((bi1.data[pos] & 0x80000000) == 0 && (bi2.data[pos] & 0x80000000) != 0)
                    return false;
                int len = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                for (pos = len - 1; pos >= 0 && bi1.data[pos] == bi2.data[pos]; pos--) ;
                if (pos >= 0)
                {
                    if (bi1.data[pos] < bi2.data[pos])
                        return true;
                    return false;
                }
                return false;
            }
            public static bool operator >=(BigInteger bi1, BigInteger bi2)
            {
                return (bi1 == bi2 || bi1 > bi2);
            }
            public static bool operator <=(BigInteger bi1, BigInteger bi2)
            {
                return (bi1 == bi2 || bi1 < bi2);
            }
            #endregion
            /// <summary>
            /// 私有函数, 它支持两个数的除法, 除数超过1位。
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <param name="outQuotient">出商</param>
            /// <param name="outRemainder">出余数</param>
            private static void MultiByteDivide(BigInteger bi1, BigInteger bi2, BigInteger outQuotient, BigInteger outRemainder)
            {
                uint[] result = new uint[maxLength];
                int remainderLen = bi1.dataLength + 1;
                uint[] remainder = new uint[remainderLen];
                uint mask = 0x80000000;
                uint val = bi2.data[bi2.dataLength - 1];
                int shift = 0, resultPos = 0;
                while (mask != 0 && (val & mask) == 0)
                {
                    shift++; mask >>= 1;
                }
                for (int i = 0; i < bi1.dataLength; i++)
                    remainder[i] = bi1.data[i];
                ShiftLeft(remainder, shift);
                bi2 = bi2 << shift;
                int j = remainderLen - bi2.dataLength;
                int pos = remainderLen - 1;
                ulong firstDivisorByte = bi2.data[bi2.dataLength - 1];
                ulong secondDivisorByte = bi2.data[bi2.dataLength - 2];
                int divisorLen = bi2.dataLength + 1;
                uint[] dividendPart = new uint[divisorLen];
                while (j > 0)
                {
                    ulong dividend = ((ulong)remainder[pos] << 32) + (ulong)remainder[pos - 1];
                    ulong q_hat = dividend / firstDivisorByte;
                    ulong r_hat = dividend % firstDivisorByte;
                    bool done = false;
                    while (!done)
                    {
                        done = true;
                        if (q_hat == 0x100000000 || (q_hat * secondDivisorByte) > ((r_hat << 32) + remainder[pos - 2]))
                        {
                            q_hat--;
                            r_hat += firstDivisorByte;
                            if (r_hat < 0x100000000)
                                done = false;
                        }
                    }
                    for (int h = 0; h < divisorLen; h++)
                        dividendPart[h] = remainder[pos - h];
                    BigInteger kk = new BigInteger(dividendPart);
                    BigInteger ss = bi2 * (long)q_hat;
                    while (ss > kk)
                    {
                        q_hat--;
                        ss -= bi2;
                    }
                    BigInteger yy = kk - ss;
                    for (int h = 0; h < divisorLen; h++)
                        remainder[pos - h] = yy.data[bi2.dataLength - h];
                    result[resultPos++] = (uint)q_hat;
                    pos--;
                    j--;
                }
                outQuotient.dataLength = resultPos;
                int y = 0;
                for (int x = outQuotient.dataLength - 1; x >= 0; x--, y++)
                    outQuotient.data[y] = result[x];
                for (; y < maxLength; y++)
                    outQuotient.data[y] = 0;
                while (outQuotient.dataLength > 1 && outQuotient.data[outQuotient.dataLength - 1] == 0)
                    outQuotient.dataLength--;
                if (outQuotient.dataLength == 0)
                    outQuotient.dataLength = 1;
                outRemainder.dataLength = ShiftRight(remainder, shift);
                for (y = 0; y < outRemainder.dataLength; y++)
                    outRemainder.data[y] = remainder[y];
                for (; y < maxLength; y++)
                    outRemainder.data[y] = 0;
            }
            /// <summary>
            /// 私有函数, 它支持两个数的除法, 除数只有1位。
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <param name="outQuotient">出商</param>
            /// <param name="outRemainder">出余数</param>
            private static void SingleByteDivide(BigInteger bi1, BigInteger bi2, BigInteger outQuotient, BigInteger outRemainder)
            {
                uint[] result = new uint[maxLength];
                int resultPos = 0;
                for (int i = 0; i < maxLength; i++)
                    outRemainder.data[i] = bi1.data[i];
                outRemainder.dataLength = bi1.dataLength;
                while (outRemainder.dataLength > 1 && outRemainder.data[outRemainder.dataLength - 1] == 0)
                    outRemainder.dataLength--;
                ulong divisor = (ulong)bi2.data[0];
                int pos = outRemainder.dataLength - 1;
                ulong dividend = (ulong)outRemainder.data[pos];
                if (dividend >= divisor)
                {
                    ulong quotient = dividend / divisor;
                    result[resultPos++] = (uint)quotient;
                    outRemainder.data[pos] = (uint)(dividend % divisor);
                }
                pos--;
                while (pos >= 0)
                {
                    dividend = ((ulong)outRemainder.data[pos + 1] << 32) + (ulong)outRemainder.data[pos];
                    ulong quotient = dividend / divisor;
                    result[resultPos++] = (uint)quotient;
                    outRemainder.data[pos + 1] = 0;
                    outRemainder.data[pos--] = (uint)(dividend % divisor);
                }
                outQuotient.dataLength = resultPos;
                int j = 0;
                for (int i = outQuotient.dataLength - 1; i >= 0; i--, j++)
                    outQuotient.data[j] = result[i];
                for (; j < maxLength; j++)
                    outQuotient.data[j] = 0;
                while (outQuotient.dataLength > 1 && outQuotient.data[outQuotient.dataLength - 1] == 0)
                    outQuotient.dataLength--;
                if (outQuotient.dataLength == 0)
                    outQuotient.dataLength = 1;
                while (outRemainder.dataLength > 1 && outRemainder.data[outRemainder.dataLength - 1] == 0)
                    outRemainder.dataLength--;
            }
            /// <summary>
            /// 除法运算符的重载
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>返回bi1与bi2进行除法运算的结果</returns>
            public static BigInteger operator /(BigInteger bi1, BigInteger bi2)
            {
                BigInteger quotient = new BigInteger();
                BigInteger remainder = new BigInteger();
                int lastPos = maxLength - 1;
                bool divisorNeg = false, dividendNeg = false;
                if ((bi1.data[lastPos] & 0x80000000) != 0)
                {
                    bi1 = -bi1;
                    dividendNeg = true;
                }
                if ((bi2.data[lastPos] & 0x80000000) != 0)
                {
                    bi2 = -bi2;
                    divisorNeg = true;
                }
                if (bi1 < bi2)
                    return quotient;
                else
                {
                    if (bi2.dataLength == 1)
                        SingleByteDivide(bi1, bi2, quotient, remainder);
                    else
                        MultiByteDivide(bi1, bi2, quotient, remainder);
                    if (dividendNeg != divisorNeg)
                        return -quotient;
                    return quotient;
                }
            }
            /// <summary>
            /// 模数运算符的重载(取余)
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>返回bi1与bi2取余运算后的结果</returns>
            public static BigInteger operator %(BigInteger bi1, BigInteger bi2)
            {
                BigInteger quotient = new BigInteger();
                BigInteger remainder = new BigInteger(bi1);
                int lastPos = maxLength - 1;
                bool dividendNeg = false;
                if ((bi1.data[lastPos] & 0x80000000) != 0)
                {
                    bi1 = -bi1;
                    dividendNeg = true;
                }
                if ((bi2.data[lastPos] & 0x80000000) != 0)
                    bi2 = -bi2;
                if (bi1 < bi2)
                    return remainder;
                else
                {
                    if (bi2.dataLength == 1)
                        SingleByteDivide(bi1, bi2, quotient, remainder);
                    else
                        MultiByteDivide(bi1, bi2, quotient, remainder);
                    if (dividendNeg)
                        return -remainder;
                    return remainder;
                }
            }
            /// <summary>
            /// 按位 AND 运算符重载(与运算)
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>返回bi1与bi2进行与运算的结果</returns>
            public static BigInteger operator &(BigInteger bi1, BigInteger bi2)
            {
                BigInteger result = new BigInteger();
                int len = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                for (int i = 0; i < len; i++)
                {
                    uint sum = (uint)(bi1.data[i] & bi2.data[i]);
                    result.data[i] = sum;
                }
                result.dataLength = maxLength;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                return result;
            }
            /// <summary>
            /// 按位 OR 运算符重载(或)
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>返回bi1与bi2进行或运算的结果</returns>
            public static BigInteger operator |(BigInteger bi1, BigInteger bi2)
            {
                BigInteger result = new BigInteger();
                int len = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                for (int i = 0; i < len; i++)
                {
                    uint sum = (uint)(bi1.data[i] | bi2.data[i]);
                    result.data[i] = sum;
                }
                result.dataLength = maxLength;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                return result;
            }
            /// <summary>
            /// 按位 XOR 运算符的重载(异或运算)
            /// </summary>
            /// <param name="bi1"></param>
            /// <param name="bi2"></param>
            /// <returns>返回bi1与bi2进行异或逻辑运算的结果</returns>
            public static BigInteger operator ^(BigInteger bi1, BigInteger bi2)
            {
                BigInteger result = new BigInteger();
                int len = (bi1.dataLength > bi2.dataLength) ? bi1.dataLength : bi2.dataLength;
                for (int i = 0; i < len; i++)
                {
                    uint sum = (uint)(bi1.data[i] ^ bi2.data[i]);
                    result.data[i] = sum;
                }
                result.dataLength = maxLength;
                while (result.dataLength > 1 && result.data[result.dataLength - 1] == 0)
                    result.dataLength--;
                return result;
            }
            /// <summary>
            /// 求 BigInteger 的绝对值
            /// </summary>
            /// <returns>返回 BigInteger 的绝对值</returns>
            public BigInteger Abs()
            {
                if ((this.data[maxLength - 1] & 0x80000000) != 0)
                    return (-this);
                else
                    return (new BigInteger(this));
            }
            /// <summary>
            ///  返回一个字符串,表示符号和大小的 BigInteger 在10进制数格式.
            /// </summary>
            /// <returns>表示符号和大小的 BigInteger 在10进制数格式</returns>
            public override string ToString()
            {
                return ToString(10);
            }
            /// <summary>
            /// 返回一个字符串, 表示符号和大小的 BigInteger指定进制数的格式.
            /// </summary>
            /// <param name="radix">进制数2-36</param>
            /// <returns>
            ///如果 BigInteger 的值在 10进制 中为-255, 则ToString (16) 返回 "-FF"
            ///</returns>
            public string ToString(int radix)
            {
                if (radix < 2 || radix > 36)
                    throw (new ArgumentException("进制数需 >= 2 和 <= 36"));
                string charSet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
                string result = "";
                BigInteger a = this;
                bool negative = false;
                if ((a.data[maxLength - 1] & 0x80000000) != 0)
                {
                    negative = true;
                    try
                    {
                        a = -a;
                    }
                    catch (Exception) { }
                }
                BigInteger quotient = new BigInteger();
                BigInteger remainder = new BigInteger();
                BigInteger biRadix = new BigInteger(radix);
                if (a.dataLength == 1 && a.data[0] == 0)
                    result = "0";
                else
                {
                    while (a.dataLength > 1 || (a.dataLength == 1 && a.data[0] != 0))
                    {
                        SingleByteDivide(a, biRadix, quotient, remainder);
                        if (remainder.data[0] < 10)
                            result = remainder.data[0] + result;
                        else
                            result = charSet[(int)remainder.data[0] - 10] + result;
                        a = quotient;
                    }
                    if (negative)
                        result = "-" + result;
                }
                return result;
            }
            /// <summary>
            /// 返回BigInteger的十六进制字符串
            /// </summary>
            /// <returns>
            /// 1) 如果 BigInteger 的值为255在 10进制 中, 则ToHexString () 返回 "FF"
            /// 2) 如果 BigInteger 的值为-255 在 10进制 中, 则ToHexString () 返回 "..。FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF01 ",这是2的补语表示-255。
            /// </returns>
            public string ToHexString()
            {
                string result = data[dataLength - 1].ToString("X");
                for (int i = dataLength - 2; i >= 0; i--)
                {
                    result += data[i].ToString("X8");
                }
                return result;
            }
            /// <summary>
            /// 利用Barrett's还原法快速计算模块化复位。需要 x 小于b ^ (2 k), 其中 b 是基数。 在这种情况下, 基是2 ^ 32 (uint)。
            /// </summary>
            /// <param name="x"></param>
            /// <param name="n"></param>
            /// <param name="constant"></param>
            /// <returns></returns>
            private BigInteger BarrettReduction(BigInteger x, BigInteger n, BigInteger constant)
            {
                int k = n.dataLength, kPlusOne = k + 1, kMinusOne = k - 1;
                BigInteger q1 = new BigInteger();
                for (int i = kMinusOne, j = 0; i < x.dataLength; i++, j++)
                    q1.data[j] = x.data[i];
                q1.dataLength = x.dataLength - kMinusOne;
                if (q1.dataLength <= 0)
                    q1.dataLength = 1;
                BigInteger q2 = q1 * constant;
                BigInteger q3 = new BigInteger();
                for (int i = kPlusOne, j = 0; i < q2.dataLength; i++, j++)
                    q3.data[j] = q2.data[i];
                q3.dataLength = q2.dataLength - kPlusOne;
                if (q3.dataLength <= 0)
                    q3.dataLength = 1;
                BigInteger r1 = new BigInteger();
                int lengthToCopy = (x.dataLength > kPlusOne) ? kPlusOne : x.dataLength;
                for (int i = 0; i < lengthToCopy; i++)
                    r1.data[i] = x.data[i];
                r1.dataLength = lengthToCopy;
                BigInteger r2 = new BigInteger();
                for (int i = 0; i < q3.dataLength; i++)
                {
                    if (q3.data[i] == 0)
                        continue;
                    ulong mcarry = 0;
                    int t = i;
                    for (int j = 0; j < n.dataLength && t < kPlusOne; j++, t++)
                    {
                        ulong val = ((ulong)q3.data[i] * (ulong)n.data[j]) + (ulong)r2.data[t] + mcarry;
                        r2.data[t] = (uint)(val & 0xFFFFFFFF);
                        mcarry = (val >> 32);
                    }
                    if (t < kPlusOne)
                        r2.data[t] = (uint)mcarry;
                }
                r2.dataLength = kPlusOne;
                while (r2.dataLength > 1 && r2.data[r2.dataLength - 1] == 0)
                    r2.dataLength--;
                r1 -= r2;
                if ((r1.data[maxLength - 1] & 0x80000000) != 0)
                {
                    BigInteger val = new BigInteger();
                    val.data[kPlusOne] = 0x00000001;
                    val.dataLength = kPlusOne + 1;
                    r1 += val;
                }
                while (r1 >= n)
                    r1 -= n;
                return r1;
            }
            /// <summary>
            /// 返回 BigInteger 中最重要位的位置。
            /// 结果为 0, 如果 BigInteger 的值为 0... 0000 0000
            /// 结果为 1, 如果 BigInteger 的值为 0... 0000 0001
            /// 结果为 2, 如果 BigInteger 的值为 0... 0000 0010
            /// 结果为 3, 如果 BigInteger 的值为 0... 0000 0011
            /// </summary>
            /// <returns></returns>
            public int BitCount()
            {
                while (dataLength > 1 && data[dataLength - 1] == 0)
                    dataLength--;
                uint value = data[dataLength - 1];
                uint mask = 0x80000000;
                int bits = 32;
                while (bits > 0 && (value & mask) == 0)
                {
                    bits--;
                    mask >>= 1;
                }
                bits += ((dataLength - 1) << 5);
                return bits;
            }
            /// <summary>
            /// 计算当前BigInteger的平方根
            /// </summary>
            /// <returns>返回一个等效于 BigInteger 的整数平方根的值。</returns>
            public BigInteger Sqrt()
            {
                uint numBits = (uint)this.BitCount();
                if ((numBits & 0x1) != 0)
                    numBits = (numBits >> 1) + 1;
                else
                    numBits = (numBits >> 1);
                uint bytePos = numBits >> 5;
                byte bitPos = (byte)(numBits & 0x1F);
                uint mask;
                BigInteger result = new BigInteger();
                if (bitPos == 0)
                    mask = 0x80000000;
                else
                {
                    mask = (uint)1 << bitPos;
                    bytePos++;
                }
                result.dataLength = (int)bytePos;
                for (int i = (int)bytePos - 1; i >= 0; i--)
                {
                    while (mask != 0)
                    {
                        result.data[i] ^= mask;
                        if ((result * result) > this)
                            result.data[i] ^= mask;
                        mask >>= 1;
                    }
                    mask = 0x80000000;
                }
                return result;
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/dygood/p/12937689.html
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