• CodeForces 707B Bakery (水题,暴力,贪心)


    题意:给定n个城市,其中有k个有仓库,问你在其他n-k个城市离仓库的最短距离是多少。

    析:很容易想到暴力,并且要想最短,那么肯定是某一个仓库和某一个城市直接相连,这才是最优,所以只要枚举仓库,找第一个城市,然后更新答案即可。

    代码如下:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <cctype>
    #include <stack>
    using namespace std ;
    
    typedef long long LL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f;
    const LL LNF = 100000000000000000;
    const double PI = acos(-1.0);
    const double eps = 1e-10;
    const int maxn = 1e5 + 5;
    const int mod = 1e9 + 7;
    const char *mark = "+-*";
    const int dr[] = {-1, 0, 1, 0};
    const int dc[] = {0, 1, 0, -1};
    int n, m;
    inline int Min(int a, int b){ return a < b ? a : b; }
    inline int Max(int a, int b){ return a > b ? a : b; }
    inline LL Min(LL a, LL b){ return a < b ? a : b; }
    inline LL Max(LL a, LL b){ return a > b ? a : b; }
    inline bool is_in(int r, int c){
        return r >= 0 && r < n && c >= 0 && c < m;
    }
    
    vector<int> G[maxn];
    vector<int> w[maxn];
    
    bool a[maxn];
    
    int main(){
        int k;
        scanf("%d %d %d", &n, &m, &k);
        memset(a, 0, sizeof(a));
        for(int i = 0; i < m; ++i){
            int x, y, v;
            scanf("%d %d %d", &x, &y, &v);
            G[x].push_back(y);
            G[y].push_back(x);
            w[x].push_back(v);
            w[y].push_back(v);
        }
        for(int i = 0; i < k; ++i){
            int x;
            scanf("%d", &x);
            a[x] = true;
        }
        if(k == 0){  printf("-1
    "); return 0; }
        LL ans = LNF;
        for(int i = 1; i <= n; ++i){
            if(a[i]){
                for(int j = 0; j < G[i].size(); ++j){
                    int u = G[i][j];
                    if(!a[u])  ans = Min(ans, (LL)w[i][j]);
                }
            }
        }
    
        if(ans == LNF)  printf("-1
    ");
        else  printf("%I64d
    ", ans);
    
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/5793075.html
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