• HDU 3365 New Ground (计算几何)


    题意:给定点A[0~n-1]和B[0],B[1],A[0]、A[1]映射到B[0]、B[1],求出其余点的映射B[2]~B[n-1]。

    析:运用复数类,关键是用模板复数类,一直编译不过,我明明能编译过,交上就不过,只能写一个复数了。。。

    代码如下:

    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <string>
    #include <algorithm>
    #include <vector>
    #include <map>
    using namespace std ;
    typedef long long LL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f3f;
    const int maxn = 10000 + 5;
    template<class T>
    class Complex
    {
    public:
          Complex( ){real=0;imag=0;}
          Complex(T r,T i){real=r;imag=i;}
          Complex complex_add(Complex &c2);
          Complex complex_minus(Complex &c2);
          Complex complex_multiply(Complex &c2);
          Complex complex_divide(Complex &c2);
          T real1();
          T imag1();
    
    public:
        friend istream &operator >>(istream &is, Complex<T> &p){
            cin >> p.real >> p.imag;
            return is;
        }
    
    private:
          T real;
          T imag;
    };
    
    template<class T>
    Complex<T> Complex<T>::complex_add(Complex<T> &c2)
    {
          Complex<T> c;
          c.real=real+c2.real;
          c.imag=imag+c2.imag;
          return c;
    }
    
    template <class T>
    Complex<T> Complex<T>::complex_minus(Complex <T> &c2)
    {
          Complex <T> c;
          c.real=real-c2.real;
          c.imag=imag-c2.imag;
          return c;
    }
    
    template <class T>
    Complex<T> Complex<T>::complex_multiply(Complex <T> &c2)
    {
          Complex <T> c;
          c.real=real*c2.real-imag*c2.imag;
          c.imag=imag*c2.real+real*c2.imag;
          return c;
    }
    
    template <class T>
    Complex<T> Complex<T>::complex_divide(Complex <T> &c2)
    {
          Complex <T> c;
          T d=c2.real*c2.real+c2.imag*c2.imag;
          c.real=(real*c2.real+imag*c2.imag)/d;
          c.imag=(imag*c2.real-real*c2.imag)/d;
          return c;
    }
    
    template <class T>
    T Complex<T>::real1(){
        return real;
    }
    
    template <class T>
    T Complex<T>::imag1(){
        return imag;
    }
    
    
    
    Complex<double> a[maxn], b[2], ans;
    
    int main(){
        int T, n;  cin >> T;
        for(int kase = 1; kase <= T; ++kase){
            scanf("%d", &n);
            double x, y;
            for(int i = 0; i < n; ++i){
                cin >> a[i];
    
            }
            for(int i = 0; i < 2; ++i){
                cin >> b[i];
            }
    
            Complex<double> tmp = (b[1].complex_minus(b[0]));
            Complex<double> tmp1 = (a[1].complex_minus(a[0]));
            tmp = tmp.complex_divide(tmp1);
            printf("Case %d:
    ", kase);
            for(int i = 0; i < n; ++i){
                ans = (a[i].complex_minus(a[0]));
                ans = ans.complex_multiply(tmp);
                ans = ans.complex_add(b[0]);
                printf("%.2lf %.2lf
    ", ans.real1(), ans.imag1());
            }
        }
        return 0;
    }
    
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <string>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <complex>
    using namespace std ;
    typedef long long LL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f3f;
    const int maxn = 10000 + 5;
    complex<double> a[maxn], b[2], ans;
    
    int main(){
        int T, n;  cin >> T;
        for(int kase = 1; kase <= T; ++kase){
            scanf("%d", &n);
            for(int i = 0; i < n; ++i)
                scanf("%lf %lf", &a[i].real(), &a[i].imag());
            scanf("%lf %lf %lf %lf", &b[0].real(), &b[0].imag(), &b[1].real(), &b[1].imag());
            complex<double> tmp = (b[1]-b[0])/(a[1]-a[0]);
            printf("Case %d:
    ", kase);
            for(int i = 0; i < n; ++i){
                ans = (a[i]-a[0]) * tmp + b[0];
                printf("%.2lf %.2lf
    ", ans.real(), ans.imag());
            }
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/5713229.html
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