• 产生一个数组的全排列,非冗余 C++实现


     finds all the permutaitons of n elements, repeated elements are allowed and do not create redundant permutations.

    蛋白质组学Ms-TopDown源代码auxfun.cpp中一个函数,看了很久没有注释,有点晕,但是以后可以直接拿来使用.

    产生原始数组元素的全排列,但是要求是非冗余的,也就是说原始数组可以有重复的元素,比如{2,2,2}这个数组,只有一种排列,2这个元素必须按相同处理,只是个数是3

     1 void generate_all_permutations(const vector<int>& org_vector, 
     2                                vector< vector<int> >& permutations)
     3 {
     4     unsigned int i;
     5     vector<int> counts, symbols;
     6     permutations.clear();
     7 
     8     if (org_vector.size() == 0)
     9         return;
    10 
    11     counts.clear();
    12     symbols.clear();
    13 
    14     // create vector with symbols and their counts
    15     symbols.push_back(org_vector[0]);
    16     counts.push_back(1);
    17 
    18     for (i=1; i<org_vector.size(); i++)
    19     {
    20         unsigned int j;
    21         for (j=0; j<counts.size(); j++)
    22         {
    23             if (org_vector[i] == symbols[j])
    24             {
    25                 counts[j]++;
    26                 break;
    27             }
    28         }
    29 
    30         if (j == counts.size())
    31         {
    32             symbols.push_back(org_vector[i]);
    33             counts.push_back(1);
    34         }
    35     }
    36 
    37     vector<int> next_sym_idx,perm;
    38     int n = org_vector.size(); // total number of elements
    39     int k = counts.size(); // total number of element types
    40     next_sym_idx.resize(n,0);
    41     perm.resize(n,-1);
    42     int d=0;
    43 
    44     while (1)
    45     {
    46         while (next_sym_idx[d]<k && counts[next_sym_idx[d]] == 0)
    47             next_sym_idx[d]++;
    48 
    49         if (next_sym_idx[0]==k)
    50             break;
    51 
    52         if (next_sym_idx[d] >= k)
    53         {
    54             next_sym_idx[d]=0;
    55             d--;
    56             counts[next_sym_idx[d]]++;
    57             next_sym_idx[d]++;
    58             continue;
    59         }
    60 
    61         // add symbol
    62         perm[d]=symbols[next_sym_idx[d]];
    63         counts[next_sym_idx[d]]--;
    64         d++;
    65 
    66         if (d == n)
    67         {
    68             permutations.push_back(perm);
    69     //        int k;
    70     //        for (k=0; k<perm.size(); k++)
    71     //            cout << perm[k] << " ";
    72     //        cout << endl;
    73 
    74             d--;
    75             counts[next_sym_idx[d]]++;
    76             next_sym_idx[d]++;
    77         }
    78     }
    79 }
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  • 原文地址:https://www.cnblogs.com/duanqiong/p/4422187.html
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