• bzoj1176: [Balkan2007]Mokia cdq


    链接

    bzoj

    思路

    cdq入门题,拆成4个矩阵,然后cdq。

    代码

    /**************************************************************
        Problem: 1176
        User: gryz2016
        Language: C++
        Result: Accepted
        Time:2652 ms
        Memory:13012 kb
    ****************************************************************/
     
    #include <bits/stdc++.h>
    using namespace std;
    #define lowbit(x) (x&-x)
    const int N = 2e5 + 7;
    int read() {
        int x = 0, f = 1; char s = getchar();
        for (; s > '9' || s < '0'; s = getchar()) if (s == '-') f = -1;
        for (; s >= '0' && s <= '9'; s = getchar()) x = x * 10 + s - '0';
        return x * f;
    }
    int n, a[N], ans[N];
    struct ask {
        int opt, x, y, w, id;
        ask(int a = 0, int b = 0, int c = 0, int d = 0, int e = 0) {
            opt = a, x = b, y = c, w = d, id = e;
        }
        bool operator < (const ask &b) const {
            return x == b.x ? opt < b.opt : x < b.x;
        }
    } Q[N], tmp[N];
    int lsh_y[N << 1];
    namespace BIT {
        int sum[N], maxn;
        void add(int id, int w) {
            for (int i = id; i <= maxn; i += lowbit(i)) sum[i] += w;
        }
        int query(int x) {
            int ans = 0;
            for (int i = x; i >= 1; i -= lowbit(i)) ans += sum[i];
            return ans;
        }
    }
    void cdq(int l, int r) {
        if (l == r) return;
        int mid = (l + r) >> 1;
        cdq(l, mid), cdq(mid + 1, r);
        int p = l, q = mid + 1, js = l;
        while (p <= mid && q <= r) {
            if (Q[p] < Q[q]) {
                if (Q[p].opt == 1) BIT::add(Q[p].y, Q[p].w);
                tmp[js++] = Q[p++];
            } else {
                if (Q[q].opt == 2) ans[Q[q].id] += Q[q].w * BIT::query(Q[q].y);
                tmp[js++] = Q[q++];
            }
        }
        if (p <= mid) {
            for (int i = l; i < p; ++i) if (Q[i].opt == 1) BIT::add(Q[i].y, -Q[i].w);
            while (p <= mid) tmp[js++] = Q[p++];
        } else {
            while (q <= r) {
                if (Q[q].opt == 2) ans[Q[q].id] += Q[q].w * BIT::query(Q[q].y);
                tmp[js++] = Q[q++];
            }
            for (int i = l; i <= mid; ++i) if (Q[i].opt == 1) BIT::add(Q[i].y, -Q[i].w);
        }
        for (int i = l; i <= r; ++i) Q[i] = tmp[i];
    }
    int main() {
    //  freopen("a.in", "r", stdin);
        int S = read(), W = read(), n = 0, DSR = 0;
        while (233) {
            int opt = read();
            if (opt == 3) break;
            if (opt == 1) {
                int x = read(), y = read(), w = read();
                Q[++n] = ask(opt, x, y, w), lsh_y[++lsh_y[0]] = Q[n].y;
            } else {
                ++DSR;
                int a = read(), b = read(), x = read(), y = read();
                if (x && y) Q[++n] = ask(opt, x, y, 1, DSR), lsh_y[++lsh_y[0]] = Q[n].y;
                if (a - 1 && b - 1) Q[++n] = ask(opt, a - 1, b - 1, 1, DSR), lsh_y[++lsh_y[0]] = Q[n].y;
                if (a - 1 && y) Q[++n] = ask(opt, a - 1, y, -1, DSR), lsh_y[++lsh_y[0]] = Q[n].y;
                if (x && b - 1) Q[++n] = ask(opt, x, b - 1, -1, DSR), lsh_y[++lsh_y[0]] = Q[n].y;
            }
        }
        sort(lsh_y + 1, lsh_y + 1 + lsh_y[0]);
        lsh_y[0] = unique(lsh_y + 1, lsh_y + 1 + lsh_y[0]) - lsh_y - 1;
        for (int i = 1; i <= n; ++i) Q[i].y = lower_bound(lsh_y + 1, lsh_y + 1 + lsh_y[0], Q[i].y) - lsh_y;
        BIT::maxn = lsh_y[0] + 1;
        cdq(1, n);
        for (int i = 1; i <= DSR; ++i) printf("%d
    ", ans[i]);
        return 0;
    }
    
  • 相关阅读:
    莫名其妙的float:left; 不能使元素紧贴父级的坑
    将HTML元素转换成图片供用户下载(html2canvas + canvas2Image)
    使用Git代替FTP进行虚拟主机的代码管理
    jQuery: on()特别的几种用法
    监控页面后退前进,浏览器文档加载事件之pageshow、pagehide
    博客园Markdown编辑器试玩~~~
    移动端调试神器(eruda)
    移动端分享插件使用总结
    sqlloader的使用------windows版
    运维工作总结教训
  • 原文地址:https://www.cnblogs.com/dsrdsr/p/10992605.html
Copyright © 2020-2023  润新知