• [hihocoder][Offer收割]编程练习赛43


    版本号排序

    不知道什么傻逼原因,就是过不了

    #pragma comment(linker, "/STACK:102400000,102400000")
    #include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<vector>
    #include<algorithm>
    #include<iostream>
    #include<map>
    #include<queue>
    #include<stack>
    #include<string>
    #include<functional>
    #include<math.h>
    //#include<bits/stdc++.h>
    using namespace std;
    typedef long long lint;
    typedef vector<int> VI;
    typedef pair<int, int> PII;
    void makedata() {
        freopen("input.txt", "w", stdout);
        cout << 200000 << endl;
    
        for(int i = 0; i < 200000; i++) cout << 1000000000 << ' ';
    
        fclose(stdout);
    }
    
    VI a[200];
    bool ok(int x, int y) {
        int lx = a[x].size(), ly = a[y].size();
        int l = min(lx, ly);
    
        for(int i = 0; i < l; i++) {
            if(a[x][i] < a[y][i]) return true;
    
            if(a[x][i] > a[y][i]) return false;
        }
    
        if(lx <= ly) return true;
        else return false;
    }
    int main() {
    #ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
    #endif
        //makedata();
        std::ios::sync_with_stdio(0), cin.tie(0);
        int n;
        cin >> n;
    
        for(int i = 0; i < n; i++) {
            int tmp;
            cin >> tmp;
            a[i].push_back(tmp);
    
            while(getchar() == '.') {
                cin >> tmp;
                a[i].push_back(tmp);
            }
        }
    
        for(int i = 0; i < n; i++) {
            for(int j = i + 1; j < n; j++) {
                if(!ok(i, j)) swap(a[i], a[j]);
            }
        }
    
        for(int i = 0; i < n; i++) {
            cout << a[i][0];
    
            for(int j = 1; j < a[i].size(); j++) cout << '.' << a[i][j];
    
            cout << endl;
        }
    
        return 0;
    }
    View Code

    自底向上遍历二叉树

     叶节点从左到右的顺序就是它们在树的从上到下的遍历中的顺序,按遍历中的顺序不断向上找

    #pragma comment(linker, "/STACK:102400000,102400000")
    #include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<vector>
    #include<algorithm>
    #include<iostream>
    #include<map>
    #include<queue>
    #include<stack>
    #include<string>
    #include<functional>
    #include<math.h>
    //#include<bits/stdc++.h>
    using namespace std;
    typedef long long lint;
    typedef vector<int> VI;
    typedef pair<int, int> PII;
    void makedata() {
        freopen("input.txt", "w", stdout);
        cout << 200000 << endl;
    
        for(int i = 0; i < 200000; i++) cout << 1000000000 << ' ';
    
        fclose(stdout);
    }
    
    VI ch[110000];
    bool f[110000];
    int father[110000];
    void traverse(int x) {
        while(f[x] == false && x) {
            cout << x << endl;
            f[x] = true;
            x = father[x];
        }
    }
    void dfs(int x) {
        if(ch[x].size() == 0) traverse(x);
        else for(int i = 0; i < ch[x].size(); i++) dfs(ch[x][i]);
    }
    
    int main() {
    #ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
    #endif
        //makedata();
        std::ios::sync_with_stdio(0), cin.tie(0);
        int n;
        cin >> n;
        memset(father, 0, sizeof(father));
    
        for(int i = 1; i < n; i++) {
            int u, v;
            cin >> u >> v;
            father[v] = u;
            ch[u].push_back(v);
        }
    
        for(int i = 1; i <= n; i++) {
            if(ch[i].size() != 2) continue;
    
            if(ch[i][0] > ch[i][1]) {
                int tmp = ch[i][0];
                ch[i][0] = ch[i][1];
                ch[i][1] = tmp;
            }
        }
    
        int root = 1;
    
        while(father[root]) root = father[root];
    
        memset(f, false, sizeof(f));
        dfs(root);
        return 0;
    }
    View Code

    hiho字符串2

    根据长度dfs,注意一开始是第1代而不是第0代。

    #pragma comment(linker, "/STACK:102400000,102400000")
    #include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<vector>
    #include<algorithm>
    #include<iostream>
    #include<map>
    #include<queue>
    #include<stack>
    #include<string>
    #include<functional>
    #include<math.h>
    //#include<bits/stdc++.h>
    using namespace std;
    typedef long long lint;
    typedef vector<int> VI;
    typedef pair<int, int> PII;
    void makedata() {
        freopen("input.txt", "w", stdout);
        cout << 200000 << endl;
    
        for(int i = 0; i < 200000; i++) cout << 1000000000 << ' ';
    
        fclose(stdout);
    }
    
    lint L[256][200];
    const lint INF = (1LL << 40);
    
    char dfs(string s, int n, lint k) {
        char ch = s[0];
        int len = s.size();
        string ss;
    
        if(n == 0) {
            if(k > len) return 0;
            else return s[k - 1];
        }
    
        if(L[ch][n] >= k) {
            if(ch == 'h') ss = "hio";
    
            if(ch == 'i') ss = "hi";
    
            if(ch == 'o') ss = "ho";
    
            return dfs(ss, n - 1, k);
        } else {
            k -= L[ch][n];
            ss = s.substr(1, len - 1);
            return dfs(ss, n, k);
        }
    }
    
    int main() {
    #ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
    #endif
        //makedata();
        std::ios::sync_with_stdio(0), cin.tie(0);
        L['h'][0] = L['i'][0] = L['o'][0] = 1;
    
        for(int i = 1; i <= 150; i++) {
            L['h'][i] = L['h'][i - 1] + L['i'][i - 1] + L['o'][i - 1];
            L['i'][i] = L['h'][i - 1] + L['i'][i - 1];
            L['o'][i] = L['h'][i - 1] + L['o'][i - 1];
    
            if(L['h'][i] > INF) L['h'][i] = INF;
    
            if(L['i'][i] > INF) L['i'][i] = INF;
    
            if(L['o'][i] > INF) L['o'][i] = INF;
        }
    
        int t, n;
        lint k;
        cin >> t;
        string s = "hiho";
    
        while(t--) {
            cin >> n >> k;
            cout << dfs(s, n - 1, k) << endl;;
        }
    
        return 0;
    }
    View Code

    最长多数子串

    一开始想的是二分+hash,没过。别人用的SAM,想破了脑袋也想不清楚。以前看过SAM,当时看完就觉得:“好叼啊,可是有什么用啊?”,怎么也想不通在哪里能用上,这里别人用了,怎么也想不通到底怎么过的。

    #include<iostream>
    #include<cstdio>
    #include<algorithm>
    #include<cstring>
    #include<memory>
    #include<cmath>
    #define maxn 2000003
    using namespace std;
    int n, m, len, ans, Max, now;
    char s[maxn], cap[maxn];
    struct SAM {
        int ch[maxn][26], fa[maxn], maxlen[maxn], Last, sz;
        int root, nxt[maxn], size[maxn];
        void init() {
            sz = 0;
            root = ++sz;
            memset(size, 0, sizeof(size));
            memset(ch[1], 0, sizeof(ch[1]));
            memset(nxt, 0, sizeof(nxt));
        }
        void add(int x) {
            int np = ++sz, p = Last;
            Last = np;
            memset(ch[np], 0, sizeof(ch[np]));
            maxlen[np] = maxlen[p] + 1;
            while (p && !ch[p][x]) ch[p][x] = np, p = fa[p];
            if (!p) fa[np] = 1;
            else {
                int q = ch[p][x];
                if (maxlen[p] + 1 == maxlen[q]) fa[np] = q;
                else {
                    int nq = ++sz;
                    memcpy(ch[nq], ch[q], sizeof(ch[q]));
                    size[nq] = size[q];
                    nxt[nq] = nxt[q];
                    maxlen[nq] = maxlen[p] + 1;
                    fa[nq] = fa[q];
                    fa[q] = fa[np] = nq;
                    while (p && ch[p][x] == q) ch[p][x] = nq, p = fa[p];
                }
            }
            for (; np; np = fa[np])
                if (nxt[np] != now) {
                    size[np]++;
                    nxt[np] = now;
                } else break;
        }
    };
    SAM Sam;
    int main() {
        while (~scanf("%d%d", &n, &m) && n) {
            Sam.init();
            for (int i = 1; i <= n; i++) {
                scanf("%s", s + 1);
                Sam.Last = Sam.root;
                len = strlen(s + 1);
                now = i;
                for (int j = 1; j <= len; j++) Sam.add(s[j] - 'a');
            }
            Max = 0;
            ans = 0;
            for (int i = 1; i <= Sam.sz; i++)
                if (Sam.size[i] >= m && Sam.maxlen[i] > ans) {
                    Max = i;
                    ans = Sam.maxlen[i];
                }
            printf("%d
    ", ans);
        }
        return 0;
    }
    View Code
  • 相关阅读:
    深入理解Android(1)——理解Android中的JNI(上)
    我的2014——北京梦的起点和终点
    Phalcon的MVC框架解析
    jquery方法操作iframe元素
    Phalcon学习-model
    Phalcon Framework的Mvc结构及启动流程(部分源码分析)
    使用 OAuth2-Server-php 在 Yii 框架上搭建 OAuth2 Server
    Yii CDbCriteria 常用方法
    Yii-模型- criteria查找数据库方法
    Yii CDbCriteria常用用法
  • 原文地址:https://www.cnblogs.com/dramstadt/p/8251562.html
Copyright © 2020-2023  润新知