• ACM-ICPC-Swiss-Subregional 2017 训练日志


    solved 7 (2/59)

    Chess 

    #include<bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    
    template<class T>
    inline void read(T &ret){
        int sign=1;
        char c=getchar();
        while(c!='-' && (c>'9'||c<'0'))c=getchar();
        if(c=='-')sign=-1;
        else ret=c-'0';
        while(c=getchar(),c>='0'&&c<='9'){
            ret=ret*10+c-'0';
        }
        ret*=sign;
    }
    
    
    ll a[200005];
    vector<ll> vec[200005];
    multiset<ll> st;
    unordered_set<ll> st2;
    multiset<ll>::iterator it;
    int cnt;
    int n;
    ll maxv=0;
    bool zero=0;
    
    int main(){
        read(n);
        for(int i=1;i<=n;i++){
            read(a[i]);
            st.insert(a[i]);
            st2.insert(a[i]);
            if(!a[i])zero=1;
            maxv = max(maxv,a[i]);
        }
        if(zero){
            for(int j=0;;j++){
                if(st.count((1LL<<j))==0){
                    return cout<<(1LL<<j),0;
                }
            }
        }
    
        vec[++cnt].push_back(1);
        st.erase(st.find(1));
    
        while(1){
            if(st.size()==0)break;
    
            ll val = vec[cnt].back();
            it = st.find(val*2);
            if(it==st.end()){
                vec[++cnt].push_back(*st.begin());
                st.erase(st.begin());
            } else {
                vec[cnt].push_back(val*2);
                st.erase(it);
            }
        }
    
        ll valend = vec[1].back()*2;
        ll ans = 0x3f3f3f3f3f3f3f3f;
    
        multiset<pair<ll,int> >stt;
    
        for(int i=2;i<=cnt;i++){
            ll mod = valend - vec[i].front();
            if(mod<=maxv)continue;
            stt.insert(make_pair(mod,i));
        }
    
        if(cnt==1){
            ans = maxv+1;
        }
        else if(cnt==2){
            ans = valend - vec[2][0];
        }
    
        for(auto pp:stt){
            ll mod = pp.first;
            int id = pp.second;
            if(st2.count(vec[id].back()*2%mod)){
                if(cnt==3||st2.count(((vec[id].back()*2%mod)*2)%mod)) ans = min(ans , mod);
            }
        }
        cout<<ans;
        return 0;
    }

    B - Triangle in a Triangle 

    #include <bits/stdc++.h>
    using namespace std;
    #define maxn 1000006
    double ax,ay;
    double bx,by;
    double cx,cy;
    
    int dista[maxn],distb[maxn],distc[maxn];
    int ab,bc,ca;
    
    double a1x,a1y,a2x,a2y;
    double b1x,b1y,b2x,b2y;
    double c1x,c1y,c2x,c2y;
    
    double lenab,lenbc,lenca;
    
    double dis(double x1,double y1,double x2,double y2){
        return sqrt((x1-x2)*(x1-x2) + (y1-y2)*(y1-y2));
    }
    
    double mj(double x1,double y1,double x2,double y2,double x3,double y3){
        double a = dis(x1,y1,x2,y2);
        double b = dis(x2,y2,x3,y3);
        double c = dis(x3,y3,x1,y1);
        double p = (a+b+c)/2;
        return sqrt(p*(p-a)*(p-b)*(p-c));
    }
    
    int main(){
        while(cin>>ax>>ay>>bx>>by>>cx>>cy){
    
            lenab = dis(ax,ay,bx,by);
            lenbc = dis(bx,by,cx,cy);
            lenca = dis(cx,cy,ax,ay);
    
            cin>>ab;
            for(int i=1;i<=ab;i++){
                scanf("%d",dista+i);
            }
            cin>>bc;
            for(int i=1;i<=bc;i++){
                scanf("%d",distb+i);
            }
            cin>>ca;
            for(int i=1;i<=ca;i++){
                scanf("%d",distc+i);
            }
            sort(dista+1,dista+1+ab);
            sort(distb+1,distb+1+bc);
            sort(distc+1,distc+1+ca);
    
            a1x = (ax - bx)*(lenab - dista[1])/(lenab) + bx;
            a1y = (ay - by)*(lenab - dista[1])/(lenab) + by;
    
            b1x = (ax - bx)*(lenab - dista[ab])/lenab + bx;
            b1y = (ay - by)*(lenab - dista[ab])/lenab + by;
    
            b2x = (cx - bx)*(distb[1])/lenbc + bx;
            b2y = (cy - by)*(distb[1])/lenbc + by;
    
            c1x = (cx - bx)*(distb[bc])/lenbc + bx;
            c1y = (cy - by)*(distb[bc])/lenbc + by;
    
            c2x = (cx - ax)*(lenca - distc[1])/lenca + ax;
            c2y = (cy - ay)*(lenca - distc[1])/lenca + ay;
    
            a2x = (cx - ax)*(lenca - distc[ca])/lenca + ax;
            a2y = (cy - ay)*(lenca - distc[ca])/lenca + ay;
    
            double ans = 0;
    
            ans = max(ans , mj(a1x,a1y,b1x,b1y,c1x,c1y));
    
            ans = max(ans , mj(a2x,a2y,b1x,b1y,c1x,c1y));
    
            ans = max(ans , mj(a1x,a1y,b2x,b2y,c1x,c1y));
    
            ans = max(ans , mj(a1x,a1y,b1x,b1y,c2x,c2y));
    
            ans = max(ans , mj(a2x,a2y,b1x,b1y,c2x,c2y));
    
            ans = max(ans , mj(a1x,a1y,b2x,b2y,c2x,c2y));
    
            ans = max(ans , mj(a2x,a2y,b2x,b2y,c1x,c1y));
    
            ans = max(ans , mj(a2x,a2y, b2x,b2y, c2x,c2y));
    
            printf("%.10f",ans);
        }
        return 0;
    }

    C - Candy division

    #include<bits/stdc++.h>
    using namespace std;
    typedef long long LL;
    int main(){
        int T;
        LL n;
        cin >> T;
        while(T--){
            cin >> n;
            if(n % 3 == 0){
                LL t = n / 3;
                cout << t << " " << t << " " << t << endl;
            }else if(n % 4 == 0){
                cout << (n >> 1) << " " << (n >> 2) << " " << (n >> 2) << endl;
            }else cout << "IMPOSSIBLE" << endl;
        }
    
        return 0;
    }

    D - Effective network

    #include<bits/stdc++.h>
    using namespace std;
    int head[10010],cnt=0,maxlen,vis[10010],n,m,k;
    struct e{
        int next,to;
    }edge[100010];
    void add(int a,int b)
    {
        edge[++cnt].to=b;
        edge[cnt].next=head[a];
        head[a]=cnt;
    }
    bool bfs(int x)
    {
        bool vis[10000]={0};
        queue<pair<int,int> > q;
        q.push(make_pair(x,0));
        vis[x]=1;
        while(!q.empty())
        {
            int u=q.front().first,step=q.front().second;
            q.pop();
            maxlen=max(step,maxlen);
            for(int i=head[u];i!=-1;i=edge[i].next)
            {
                int v=edge[i].to;
                if(!vis[v]){q.push(make_pair(v,step+1));vis[v]=1;}
            }
        }
    }
    int main()
    {
        memset(head,-1,sizeof(head));
        cin>>n>>m>>k;
        for(int i=0;i<m;i++)
        {
            int a,b;
            scanf("%d %d",&a,&b);
            add(a,b);
            add(b,a);
        }
        for(int i=1;i<=n;i++)
        {
            bfs(i);
        }
        if(maxlen<=n-k)
        {
            printf("%d
    ",n);
            for(int i=1;i<=n;i++) printf("%d ",i);
        }
        else printf("0
    ");
    }

    E - Collection

    #include <bits/stdc++.h>
    using namespace std;
    
    template<class T>
    inline void read(T &ret){
        char c;
        int sign=1;
        while(c=getchar(),c!='-'&&(c>'9'||c<'0'));
        if(c=='-')sign=-1;
        else ret = c-'0';
        while(c=getchar(),c>='0'&&c<='9'){
            ret = ret*10 + c-'0';
        }
        ret*=sign;
    }
    
    int main(){
        int n;set<int> st;
        while(cin>>n){
            st.clear();
            int ans=0;
            for(int i=0;i<n;i++){
                int a;scanf("%d",&a);
                if(st.count(a))ans++;
                st.insert(a);
            }cout<<ans<<endl;
        }
        return 0;
    }

    F - Mattress Run 

    J - Box Hedge

    #include<bits/stdc++.h>
    using namespace std;
    int n,cnt=0,prelt[1001000],prert[1001000];
    long long cir=0,sz=0,area=0;
    struct row{
        int lt,rt,h;
    }r[1001000];
    struct point{
        int x,y;
    }p[1001000];
    bool cmp(point a,point b)
    {
        return a.y<b.y;
    }
    int main(){
        cin>>n;
        for(int i=0;i<n;i++)
        {
            scanf("%d %d",&p[i].x,&p[i].y);
            p[i].y++;
        }
        sort(p,p+n,cmp);
        r[0].lt=r[0].rt=p[0].x;
        r[0].h=p[0].y;
        for(int i=1;i<n;i++)
        {
            if(r[cnt].h==p[i].y)
            {
                r[cnt].lt=min(r[cnt].lt,p[i].x);
                r[cnt].rt=max(r[cnt].rt,p[i].x);
            }
            else
            {
                cnt++;
                r[cnt].lt=r[cnt].rt=p[i].x;
                r[cnt].h=p[i].y;
            }
        }
        prelt[cnt]=r[cnt].lt;
        prert[cnt]=r[cnt].rt;
        for(int i=cnt-1;i>=0;i--) prelt[i]=min(prelt[i+1],r[i].lt);
        for(int i=cnt-1;i>=0;i--) prert[i]=max(prert[i+1],r[i].rt);
        area=1LL*(prert[0]-prelt[0]+1)*r[0].h;
        for(int i=1;i<=cnt;i++)
        {
            area=area+1LL*(prert[i]-prelt[i]+1)*(r[i].h-r[i-1].h);
        }
        sz=2LL*r[0].h;
        for(int i=1;i<=cnt;i++)
        {
            sz=sz+2LL*(r[i].h-r[i-1].h)+abs(prelt[i]-prelt[i-1])+abs(prert[i]-prert[i-1]);
        }
        sz+=((prert[cnt]-prelt[cnt]+3));
        cir=1LL*(prert[0]-prelt[0]+3)+2LL*(r[cnt].h+1);
        cout<<cir<<" "<<sz<<" "<<area<<endl;
        return 0;
    }

    K - ACM

    #include <bits/stdc++.h>
    using namespace std;
    
    template<class T>
    inline void read(T &ret){
        char c;
        int sign=1;
        while(c=getchar(),c!='-'&&(c>'9'||c<'0'));
        if(c=='-')sign=-1;
        else ret = c-'0';
        while(c=getchar(),c>='0'&&c<='9'){
            ret = ret*10 + c-'0';
        }
        ret*=sign;
    }
    
    int main(){
        string s;
        while(cin>>s){
            if(s.find("ACM")!=string::npos){
                puts("Fun!");
            } else puts("boring...");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/dowhile0/p/9190138.html
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