Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
DFS,递归
1 class Solution { 2 public: 3 vector<vector<int> > ans; 4 vector<int> vi; 5 int k_start,n_start; 6 void DFS(int Count,int start) 7 { 8 if(Count== k_start) 9 { 10 ans.push_back(vi); 11 return; 12 } 13 for(int i=start;i<n_start;i++) 14 { 15 vi[Count] = i+1; 16 DFS(Count+1, i+1); 17 } 18 } 19 vector<vector<int> > combine(int n, int k) { 20 ans.clear(); 21 vi.resize(k); 22 k_start = k; 23 n_start = n; 24 DFS(0,0); 25 return ans; 26 } 27 };