LeetCode OJ

题目：

　　Given a linked list, determine if it has a cycle in it.

　　Follow up:
　　　　Can you solve it without using extra space?

解题思路：

　　使用快慢指针，快指针每次走两步，慢指针每次走一步，若快指针能追上慢指针，则表明有圈。

代码如下：

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    bool hasCycle(ListNode *head) {
        if (head == NULL) {
            return false;
        }
        
        ListNode *quicker = head->next;
        ListNode *slower = head;
        
        while ((quicker != NULL && quicker->next != NULL) && slower != NULL && quicker != slower) {
            quicker = quicker->next->next;
            slower = slower->next;
        }
        
        return quicker == slower;
    }
};