需要改变迭代对象 for(auto &i:s)
string s = "hello";
for (auto &i : s )
i = toupper(i); //改变成大写,影响s的值
cout<<s<<endl; //s的值是 HELLO
不需要改变迭代对象 for(auto i:s)
string s = "hello";
for (auto i : s )
i = toupper(i); //改变成大写,不影响s的值
cout<<s<<endl; //s的值是 hello
迭代map
#include <iostream>
#include <map>
using namespace std;
int main() {
map<int,string> student;
student.insert(pair<int,string>(2,"li"));
student.insert(pair<int,string>(1,"wang"));
student.insert(pair<int,string>(3,"sun"));
for(auto &v : student) // for(auto v : student)也是可以的
cout<<"key: "<<v.first<<" | value: "<<v.second<<endl;
return 0;
}