• Multiply Strings


    Given two numbers represented as strings, return multiplication of the numbers as a string.

    Note: The numbers can be arbitrarily large and are non-negative.

    思路:

    大整数运算的思路,模拟乘法运算

    代码:

    class Solution {
    public:
        string multiply(string num1, string num2) {
            int len1 = num1.size(), len2 = num2.size(), len = len1 + len2;
            string str(len, '0');
            for (int i = len1 - 1; i >= 0; i--)
            {
                int a = num1[i] - '0';
                for (int j = len2 - 1, k = len2 + i; j >= 0; j--, k--)
                {
                    int b = num2[j] - '0';
                    int c = str[k] - '0';
                    int t = b * a + c;
                    str[k] = t % 10 + '0';
                    int d = (str[k-1] - '0') + t / 10;
                    if (d >= 10)  //开始这里没有等号,检查了很久才发现,细心啊细心
                        str[k-2] = str[k-2] - '0' + d / 10 + '0';
                    str[k-1] = d % 10 + '0';
                }
            }
            int x = 0;
            while (str[x] == '0')
                x++;
            if (str.substr(x, len - x) == "")
                return "0";
            return str.substr(x, len - x);
    
        }
    };
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  • 原文地址:https://www.cnblogs.com/dollarzhaole/p/3249759.html
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