• oracle 关于表中重复记录的处理


    一、查询某个字段重复

    select *
    from User u
    where u.user_name in (select
    u.user_name
    from User u
    group by u.user_name having count(*) > 1)

    二,删除表中某几个字段的重复

    例:表中有条六条记录。 其中张三和王五 的记录有重复
    TableA
    id
    customer PhoneNo
    001 张三 777777
    002 李四 444444
    003 王五 555555
    004 张三
    777777
    005 张三 777777
    006 王五 555555
    如何写一个sql语句将TableA变成如下
    001 张三
    777777
    002 李四 444444
    003 王五 555555

    --测试环境
    create table TableA (
    id varchar(3),customer varchar(5),PhoneNo varchar(6))
    insert into TableA
    select '001','张三','777777'
    union all select '002','李四','444444'
    union all
    select '003','王五','555555'
    union all select '004','张三','777777'
    union all
    select '005','张三','777777'
    union all select
    '006','王五','555555'

    --结果

    delete TableA from TableA T
    where

    exists(
    select 1 from tablea where customer=T.customer and
    phoneno=T.phoneno
    and id <
    tt.id

    )

    --总结

    该方法适用于有一个字段为自增性,例如本例中的:id

    delete 表名
    from 表名 as T where

    exists(
    select 1 from 表名 where 字段A=T.字段A and
    字段B=T.字段B,(....)
    and 自增列 <
    T.自增列

    )

    三,查询并删除重复记录的SQL语句

    查询及删除重复记录的SQL语句
    1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
    select
    * from people
    where peopleId in (select peopleId from people group by
    peopleId having count(peopleId) >
    1)
    2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
    delete from
    people
    where peopleId in (select peopleId from people group by peopleId
    having count(peopleId) > 1)
    and rowid not in (select min(rowid) from
    people group by peopleId having count(peopleId
    )>1)

    注:rowid为oracle自带不用该.....

    3、查找表中多余的重复记录(多个字段)
    select *
    from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae
    group by peopleId,seq having count(*) >
    1)
    4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
    delete from vitae a
    where
    (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq
    having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group
    by peopleId,seq having
    count(*)>1)

    5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
    select * from vitae
    a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by
    peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from
    vitae group by peopleId,seq having
    count(*)>1)
    (二)
    比方说
    在A表中存在一个字段“name”,
    而且不同记录之间的“name”值有可能会相同,
    现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
    Select
    Name,Count(*) From A Group By Name Having Count(*) >
    1
    如果还查性别也相同大则如下:
    Select Name,sex,Count(*) From A Group By Name,sex Having
    Count(*) > 1

    (三)
    方法一
    declare @max integer,@id integer
    declare
    cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having
    count(*) >; 1
    open cur_rows
    fetch cur_rows into @id,@max
    while
    @@fetch_status=0
    begin
    select @max = @max -1
    set rowcount
    @max
    delete from 表名 where 主字段 = @id
    fetch cur_rows into
    @id,@max
    end
    close cur_rows
    set rowcount 0
    方法二
    "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
      1、对于第一种重复,比较容易解决,使用
    select
    distinct * from
    tableName
      就可以得到无重复记录的结果集。
      如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除
    select
    distinct * into #Tmp from tableName
    drop table tableName
    select * into
    tableName from #Tmp
    drop table
    #Tmp
      发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
      2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下
      假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
    select
    identity(int,1,1) as autoID, * into #Tmp from tableName
    select min(autoID) as
    autoID into #Tmp2 from #Tmp group by Name,autoID
    select * from #Tmp where
    autoID in(select autoID from
    #tmp2)
      最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)
    (四)
    查询重复
    select
    * from tablename where id in (
    select id from tablename
    group by
    id
    having count(id) > 1
    )

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  • 原文地址:https://www.cnblogs.com/dogxuefeng/p/2557698.html
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