• 从HashMap.KeySet对象的交集和差集看HashMap相关源码


    本文从HashMap.KeySet对象的交集和差集看HashMap相关源码。

    1. 下面例子的错误操作

    package com.mingo.exp.verify.set;
    
    import java.util.HashMap;
    import java.util.Map;
    import java.util.Set;
    
    /**
     * HashMap KeySet
     */
    public class MapKeySetTest {
    
        public static void main(String[] args) {
            Map<String, Integer> mapOne = new HashMap<String, Integer>() {{
                put("A", 98);
                put("B", 98);
                put("C", 98);
            }};
            Map<String, Integer> mapTwo = new HashMap<String, Integer>() {{
                put("K", 99);
                put("B", 99);
                put("P", 99);
                put("C", 99);
            }};
    
            // 下面三行是错误代码
            
            // 交集
            Set<String> intersectSet = mapOne.keySet();
            // mapOne - mapTwo
            Set<String> diffSetOne = mapOne.keySet();
            // mapTwo - mapOne
            Set<String> diffSetTwo = mapTwo.keySet();
    
            intersectSet.retainAll(mapTwo.keySet());
            diffSetOne.removeAll(mapTwo.keySet());
            diffSetTwo.removeAll(mapOne.keySet());
    
            System.out.println("交集:" + intersectSet);
            System.out.println("mapOne - mapTwo:" + diffSetOne);
            System.out.println("mapTwo - mapOne:" + diffSetTwo);
        }
    }
    

    运行结果如下

    交集:[]
    mapOne - mapTwo:[]
    mapTwo - mapOne:[P, B, C, K]
    

    结果明显不正确,下面我用这个例子看下相关源码。

    2. HashMap.keySet()

    源码

    // keySet对象初始未设置值
    transient Set<K>        keySet;
    
    // keySet()方法对keySet设值
    public Set<K> keySet() {
    	Set<K> ks = keySet;
    	if (ks == null) {
    		ks = new KeySet();
    		keySet = ks;
    	}
    	return ks;
    }
    

    初次调用keySet()方法时才设置keySet字段值,也可看出代码线程不安全。也就是说测试例子中的mapOne.keySet()mapTwo.keySet()返回的是同一个对象,做retainAll()removeAll()操作都是在同一个对象上操作。这就造成结果不正确,并且例子中mapOne和mapTwo对象的key也被修改了。

    下面先看HashMap.KeySet类的源码。

    3. HashMap.KeySet类

    类图

    源码如下

    final class KeySet extends AbstractSet<K> {
    	public final int size()                 { return size; }
    	public final void clear()               { HashMap.this.clear(); }
    	// 迭代器实现
    	public final Iterator<K> iterator()     { return new KeyIterator(); }
    	public final boolean contains(Object o) { return containsKey(o); }
    	public final boolean remove(Object key) {
    		return removeNode(hash(key), key, null, false, true) != null;
    	}
    	public final Spliterator<K> spliterator() {
    		return new KeySpliterator<>(HashMap.this, 0, -1, 0, 0);
    	}
    	public final void forEach(Consumer<? super K> action) {
    		Node<K,V>[] tab;
    		if (action == null)
    			throw new NullPointerException();
    		if (size > 0 && (tab = table) != null) {
    			int mc = modCount;
    			// 两重循环,先数元素,再遍历每个数组元素的next
    			for (int i = 0; i < tab.length; ++i) {
    				for (Node<K,V> e = tab[i]; e != null; e = e.next)
    				    // HashMap对象的key作为lamda表达式入参
    					action.accept(e.key);
    			}
    			// 比如非正常删除了元素,这里会抛异常
    			if (modCount != mc)
    				throw new ConcurrentModificationException();
    		}
    	}
    }
    

    HasMap.containsKey(Object key)

    /**
     * Returns <tt>true</tt> if this map contains a mapping for the
     * specified key.
     *
     * @param   key   The key whose presence in this map is to be tested
     * @return <tt>true</tt> if this map contains a mapping for the specified
     * key.
     */
    public boolean containsKey(Object key) {
    	return getNode(hash(key), key) != null;
    }
    
    /**
     * Implements Map.get and related methods.
     *
     * @param hash hash for key
     * @param key the key
     * @return the node, or null if none
     */
    final Node<K,V> getNode(int hash, Object key) {
    	Node<K,V>[] tab; Node<K,V> first, e; int n; K k;
    	// 先判断是否存在该key,(n - 1) & hash 定位下标
    	if ((tab = table) != null && (n = tab.length) > 0 &&
    		(first = tab[(n - 1) & hash]) != null) {
    		// 先比较第一个元素
    		if (first.hash == hash && // always check first node
    			((k = first.key) == key || (key != null && key.equals(k))))
    			return first;
    	    // 检查该节点下next
    		if ((e = first.next) != null) {
    		    // 红黑树
    			if (first instanceof TreeNode)
    				return ((TreeNode<K,V>)first).getTreeNode(hash, key);
    			// 链表
    			do {
    				if (e.hash == hash &&
    					((k = e.key) == key || (key != null && key.equals(k))))
    					return e;
    			} while ((e = e.next) != null);
    		}
    	}
    	return null;
    }
    

    HasMap.removeNode(int hash, Object key, Object value,boolean matchValue, boolean movable)

    /**
     * Implements Map.remove and related methods.
     *
     * @param hash hash for key
     * @param key the key
     * @param value the value to match if matchValue, else ignored
     * @param matchValue if true only remove if value is equal
     * @param movable if false do not move other nodes while removing
     * @return the node, or null if none
     */
    final Node<K,V> removeNode(int hash, Object key, Object value,
    						   boolean matchValue, boolean movable) {
    	Node<K,V>[] tab; Node<K,V> p; int n, index;
    	// index记录下标
    	if ((tab = table) != null && (n = tab.length) > 0 &&
    		(p = tab[index = (n - 1) & hash]) != null) {
    		Node<K,V> node = null, e; K k; V v;
    		// 比较第一个值
    		if (p.hash == hash &&
    			((k = p.key) == key || (key != null && key.equals(k))))
    			node = p;
    	    // 数组元素next指向不为空时
    		else if ((e = p.next) != null) {
    		    // 红黑树结构
    			if (p instanceof TreeNode)
    				node = ((TreeNode<K,V>)p).getTreeNode(hash, key);
    			else {
    			    // 链表结构
    				do {
    					if (e.hash == hash &&
    						((k = e.key) == key ||
    						 (key != null && key.equals(k)))) {
    						node = e;
    						break;
    					}
    					// p最终指向node元素的上一个节点,便于删除操作
    					p = e;
    				} while ((e = e.next) != null);
    			}
    		}
    		if (node != null && (!matchValue || (v = node.value) == value ||
    							 (value != null && value.equals(v)))) {
    			if (node instanceof TreeNode)
    				((TreeNode<K,V>)node).removeTreeNode(this, tab, movable);
    			else if (node == p)
    			    // 即在第一个值时就相等,直接赋值next
    				tab[index] = node.next;
    			else
    			    // 链表非首元素时,指向被删除元素的next
    				p.next = node.next;
    			++modCount;
    			--size;
    			afterNodeRemoval(node);
    			return node;
    		}
    	}
    	return null;
    }
    

    可看到clear()remove(Object key)forEach(Consumer<? super K> action)等方法都是和外部类HashMap关联。

    下面先给出相关的内部类。

    4. HashMap.Node类

    HashMap的底层就是这样一个数组,数组中每一个元素就是hash值一样的Node的集合,排列的数据结构是链表或红黑树。

    /**
     * The table, initialized on first use, and resized as
     * necessary. When allocated, length is always a power of two.
     * (We also tolerate length zero in some operations to allow
     * bootstrapping mechanics that are currently not needed.)
     */
    transient Node<K,V>[] table;
    

    Node类源码

    /**
     * Basic hash bin node, used for most entries.  (See below for
     * TreeNode subclass, and in LinkedHashMap for its Entry subclass.)
     */
    static class Node<K,V> implements Map.Entry<K,V> {
        // 计算规则: (h = key.hashCode()) ^ (h >>> 16)
    	final int hash;
    	final K key;
    	V value;
    	// 链表或红黑树
    	Node<K,V> next;
    
    	Node(int hash, K key, V value, Node<K,V> next) {
    		this.hash = hash;
    		this.key = key;
    		this.value = value;
    		this.next = next;
    	}
    
    	public final K getKey()        { return key; }
    	public final V getValue()      { return value; }
    	public final String toString() { return key + "=" + value; }
    
    	public final int hashCode() {
    		return Objects.hashCode(key) ^ Objects.hashCode(value);
    	}
    
    	public final V setValue(V newValue) {
    		V oldValue = value;
    		value = newValue;
    		// 旧值
    		return oldValue;
    	}
    
    	public final boolean equals(Object o) {
    		if (o == this)
    			return true;
    		if (o instanceof Map.Entry) {
    			Map.Entry<?,?> e = (Map.Entry<?,?>)o;
    			if (Objects.equals(key, e.getKey()) &&
    				Objects.equals(value, e.getValue()))
    				return true;
    		}
    		return false;
    	}
    }
    

    5. HashMap.KeyIterator类

    abstract class HashIterator {
    	Node<K,V> next;        // next entry to return
    	Node<K,V> current;     // current entry
    	int expectedModCount;  // for fast-fail
    	int index;             // current slot
    
    	HashIterator() {
    		expectedModCount = modCount;
    		Node<K,V>[] t = table;
    		current = next = null;
    		index = 0;
    		if (t != null && size > 0) {
                // advance to first entry
                // 如注释所说 剔除前面的空值,next指向数组第一个Node,index是下标
    			do {} while (index < t.length && (next = t[index++]) == null);
    		}
    	}
    
    	public final boolean hasNext() {
    		return next != null;
    	}
    
    	final Node<K,V> nextNode() {
    		Node<K,V>[] t;
    		// 要返回的值
    		Node<K,V> e = next;
    		if (modCount != expectedModCount)
    			throw new ConcurrentModificationException();
    		if (e == null)
    			throw new NoSuchElementException();
    		
    		// 设置current值为当前next值
    		// (next = (current = e).next) == null 用于判断该Node有无挂节点,true时且 (t = table) != null则查找下一个数组元素
    		// 
    		if ((next = (current = e).next) == null && (t = table) != null) {
    			do {} while (index < t.length && (next = t[index++]) == null);
    		}
    		return e;
    	}
    
    	public final void remove() {
    		Node<K,V> p = current;
    		if (p == null)
    			throw new IllegalStateException();
    		if (modCount != expectedModCount)
    			throw new ConcurrentModificationException();
    		current = null;
    		K key = p.key;
    		removeNode(hash(key), key, null, false, false);
    		expectedModCount = modCount;
    	}
    }
    
    // HashIterator.hasNext()
    final class KeyIterator extends HashIterator
    	implements Iterator<K> {
    	// 返回key
    	public final K next() { return nextNode().key; }
    }
    

    下面看下AbstractCollection.retainAll(Collection c)AbstractSet.removeAll(Collection c)

    6. AbstractCollection.retainAll(Collection<?> c)

    源码如下

    public boolean retainAll(Collection<?> c) {
    	Objects.requireNonNull(c);
    	boolean modified = false;
    	Iterator<E> it = iterator();
    	while (it.hasNext()) {
    	    // c集合不包含的元素就删除
    		if (!c.contains(it.next())) {
                // 见HashMap.removeNode(...)方法
    			it.remove();
    			modified = true;
    		}
    	}
    	return modified;
    }
    

    7. AbstractSet.removeAll(Collection<?> c)

    源码如下

    public boolean removeAll(Collection<?> c) {
    	Objects.requireNonNull(c);
    	boolean modified = false;
        
        // 这里将长度较小的集合遍历
    	if (size() > c.size()) {
    		for (Iterator<?> i = c.iterator(); i.hasNext(); )
    			modified |= remove(i.next());
    	} else {
    		for (Iterator<?> i = iterator(); i.hasNext(); ) {
    			if (c.contains(i.next())) {
    				i.remove();
    				modified = true;
    			}
    		}
    	}
    	return modified;
    }
    

    上面的分析可看出对HashMap.keySet()的操作会体现到HashMap对象本身上,文章开始的例子可做如下处理即可得到正确结果。

    8. 正确的例子

    package com.mingo.exp.verify.set;
    
    import java.util.HashMap;
    import java.util.HashSet;
    import java.util.Map;
    import java.util.Set;
    
    /**
     * HashMap KeySet
     */
    public class MapKeySetTest {
    
        public static void main(String[] args) {
            Map<String, Integer> mapOne = new HashMap<String, Integer>() {{
                put("A", 98);
                put("B", 98);
                put("C", 98);
            }};
            Map<String, Integer> mapTwo = new HashMap<String, Integer>() {{
                put("K", 99);
                put("B", 99);
                put("P", 99);
                put("C", 99);
            }};
    
            // 用new HashSet()处理
            // 交集
            Set<String> intersectSet = new HashSet<>(mapOne.keySet());
            // mapOne - mapTwo
            Set<String> diffSetOne = new HashSet<>(mapOne.keySet());
            // mapTwo - mapOne
            Set<String> diffSetTwo = new HashSet<>(mapTwo.keySet());
    
            intersectSet.retainAll(mapTwo.keySet());
            diffSetOne.removeAll(mapTwo.keySet());
            diffSetTwo.removeAll(mapOne.keySet());
    
            System.out.println("交集:" + intersectSet);
            System.out.println("mapOne - mapTwo:" + diffSetOne);
            System.out.println("mapTwo - mapOne:" + diffSetTwo);
        }
    }
    

    运行结果

    交集:[B, C]
    mapOne - mapTwo:[A]
    mapTwo - mapOne:[P, K]
    

    new HashSet(Collection<? extends E> c)源码

    public HashSet(Collection<? extends E> c) {
    	map = new HashMap<>(Math.max((int) (c.size()/.75f) + 1, 16));
    	addAll(c);
    }
    
    public boolean addAll(Collection<? extends E> c) {
    	boolean modified = false;
    	for (E e : c)
    		if (add(e))
    			modified = true;
    	return modified;
    }
    

    new一个HashSet对象,对入参集合元素做复制操作,生成了新的集合对象。

    原创 Doflamingo https://www.cnblogs.com/doflamingo
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  • 原文地址:https://www.cnblogs.com/doflamingo/p/13364085.html
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